Category: CUET PG Botany 2024 Previous Year Question Papers PDF with Solutions

Category: CUET PG Botany 2024 Previous Year Question Papers PDF with Solutions

CUET PG Botany 2024 Previous Year Question Papers PDF with Solutions

Q.75 Which of the following cell organelle is regarded as semi-autonomous? 1. Chloroplast 2. Peroxisomes 3. Ribosomes 4. Lysosome

Which Cell Organelle is Semi-Autonomous?

Q.74 There are different possible glucuronides that can be used as substrates for the ß- glucuronidase (GUS-reporter system), depending on the type of detection needed. The most common substrate for GUS histochemical staining is? 1. Galactic acid 2. 5-chloro-4-bromo-3-indolyl glucuronide 3. 5-bromo-4-chloro-3-indolyl glucuronide 4. 5,5'-dibromo-4,4'-dichloro-indigo

GUS Histochemical Staining Substrate

Q.73 Which disease is a severe form of protein-energy malnutrition which results when a person does not consume enough protein and calories? 1. Lathyrism 2. Marasmus 3. Favism 4. Night blindness

Severe Protein-Energy Malnutrition Explained

Q.72 During the germination of cereal seeds, what is the role of a-amylase present in the aleurone layer? 1. It directly gets converted into sugars 2. It is a reserve food material 3. It hydrolyzes the endosperm starch into sugars, which provide the energy for the growth of roots and shoots 4. It is responsible for seed dormancy

α-Amylase in Cereal Seed Germination

Q.71 What is the correct sequence of the steps which takes place in Polymerase Chain Reaction (PCR)? 1. Annealing, Extension, Denaturation 2. Denaturation, Annealing, Extension 3. Extension, Denaturation, Annealing 4. Denaturation, Extension, Annealing

PCR Steps Sequence

Q.70 In the Polyacrylamide Gel Electrophoresis, what is the role of APS (ammonium persulphate)? 1. It is an alkylating agent that is used with TEMED to catalyze the polymerization of acrylamide and bisacrylamide 2. It is an reducing agent that is used with TEMED to catalyze the polymerization of acrylamide and bisacrylamide 3. It is an oxidizing agent that is used with TEMED to catalyze the polymerization of acrylamide and bisacrylamide 4. It is an mutagenic agent that is used with TEMED to catalyze the polymerization of acrylamide and bisacrylamide

Role of APS in Polyacrylamide Gel Electrophoresis

Q.69 The transfer of DNA from one bacterial strain to another by a virus and the subsequent recombination between the chromosomes of the recepient cells and the introduced DNA is called as: 1. Transformation 2. Transduction 3. Conjugation 4. Recombination

DNA Transfer via Virus

Q.68 Calculate the degree of freedom, if the given data set represents a dihybrid cross? 1.3 2.2 3.4 4.5

Degrees of Freedom in Dihybrid Cross

Q.67 Given below are two statements, one is labelled as Assertion (A) and other one labelled as Reason (R). Assertion (A) : Penetrance and Expressivity are term which can be used interchangeably Reason (R) : Expressivity is the degree to which a genotype is expressed as a phenotype within an individual, while penetrance refers to the percentage of individuals with a particular genotype who express the associated phenotype. In light of the above statements, choose the most appropriate answer from the options given below . 1. Both (A) and (R) are correct and (R) is the correct explanation of (A). 2. Both (A) and (R) are correct but (R) is NOT the correct explanation of (A). 3. (A) is correct but (R) is not correct. 4. (A) is not correct but (R) is correct.

Penetrance vs Expressivity

Q.66 In sweet pea, the development of purple colored flowers requires the presence of two dominant genes, C and R, e.g. CCRR. When either C (e.g. ccRR) or R (e.g. CCIr) or both the genes (e.g. ccrr) are present in homozygous state, the purple color of flowers CANNOT be produced. If CCrr (white) is crossed with ceRR (white), what will be the modified dihybrid ratio at F2 generation. 1.15:1 2. 13:3 3. 9:3:4 4.9:7

Sweet Pea Purple Flower Genetics

Q.65 Match List I with List II List I (Numerical Change in Chromosome) List II (Symbolic representation) A. Autotetraploid B. Nullisomy C. Monosomy D. Allohexaploid I. 4x II. 2x(1) + 2x(2) + 2x(3) III. 2n − 2 IV. 2n − 1 Choose the correct answer from the options given below: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) (A) - (I), (B) - (III), (C) - (IV), (D) - (II) (A) - (I), (B) - (II), (C) - (IV), (D) - (III) (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Autotetraploid Nullisomy Monosomy Allohexaploid Matching

Q.64 According to Vavilov, crop plants evolved from the wild species in the area which shows greater diversity and richness in variation. That area is called as: 1. Secondary gene centre 2. Non-centre 3. Primary gene centre 4. Centre for plant genome

Vavilov Primary Gene Centre

Q.63 Match List I with List II List I (Economically useful plant) List II (Family) A. Corchorus sp. B. Rosa damascena C. Piper nigrum D. Curcuma longa I. Piperaceae II. Malvaceae III. Rosaceae IV. Zingiberaceae Choose the correct answer from the options given below: (A) - (II), (B) - (III), (C) - (IV), (D) - (I) (A) - (II), (B) - (III), (C) - (I), (D) - (IV) (A) - (I), (B) - (II), (C) - (IV), (D) - (III) (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Economically Useful Plants with Families

Q.62 Which of the following statement(s) is/are TRUE for Retting in Jute (A). It is a kind of fermentation process (B). It employs the action of bacteria on plants (C). In this, the cortical tissues and phloem tissues of the bark of the plants which contains free strands are decomposed to separate fibre from non-fibrous woody stem (D). This process does not involve any microorganisms and is purely the outcome of long soaking hours Choose the correct answer from the options given below: 1. (A), (B) and (D) only. 2. (A), (B) and (C) only. 3. (A), (B), (C) and (D). 4. (B), (C) and (D) only.

Retting in Jute

Q.61 Reserpine is obtained from the roots? 1. Rauwolfia serpentina 2. Datura innoxia 3. Withania somnifera 4. Digitalis purpurea

Reserpine Source

Q.60 What is the major secondary metabolite present in Clove buds? 1. Thymol 2. Eugenol 3. Zingiberine 4. Piperine

Clove Buds Major Secondary Metabolite

Q.59 A stele which does NOT contain a central pith is called as: 1. Solenostele 2. Dictyostele 3. Protostele 4. Siphonostele

Stele Without Central Pith

Q.58 Which of the following Gymnosperms possess winged pollen grains? 1. Dandelion 2. Cycas 3. Pinus 4. Ephedra

Gymnosperms with Winged Pollen Grains

Q.57 Which of the following is not an identifying feature of Cycas 1. Antherozoids are motile 2. Anatomical features of the leaflet indicating it as a mesophyte 3. Circinate venation of the foliage leaves 4. Xylem lacking vessels

Which Feature Identifies Cycas?

Q.56 Pseudoelators, which help in the dispersal of spores, are present in 1. Psilotum 2. Marchantia 3. Riccia 4. Anthoceros

Pseudoelators for Spore Dispersal in Bryophytes

Q.55 Bryophytes are distinct from all other land plants in having an independent _________ and a dependent ________. 1. sporophyte, gametophyte 2. female, male 3. gametophyte, sporophyte 4. antherozoid, oogonia

Bryophytes Life Cycle

Q.54 Which of the following is/are prophylactic (preventive) methods of plant disease control (A). Eradication of alternate host (B). Spraying plants with pesticides and fungicides on a regular basis (C). Crop rotation practices to control soil borne diseases (D). Growing antagonistic plants Choose the correct answer from the options given below: 1. (A) and (D) only. 2. (A) and (C) only. 3. (A), (B), (C) and (D). 4. (B) and (D) only.

Prophylactic Methods of Plant Disease Control

Q.53 The alternate host for Puccinia graminis is 1. Delonix regia 2. Thalictrum falvum 3. Muehlenbergia hugeli 4. Berberis vulgaris

Puccinia Graminis Alternate Host

Q.52 Match List I with List II List I List II A. Penicillin B. Fermentation of sucrose and molasses to produce citric acid C. Fermentation of carbohydrates to produce ethyl alcohol and CO2 D. Irish potato famine I. Aspergillus niger II. Phytophthora infestans III. Penicillium notatum IV. Saccharomyces cerevisiae Choose the correct answer from the options given below: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) (A) - (III), (B) - (I), (C) - (II), (D) - (IV) (A) - (III), (B) - (I), (C) - (IV), (D) - (II) (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Microbiology Matching

Q.51 Who discovered the heterothallism in fungi? 1. AF Blakeslee 2. Alexander Flemming 3. MP Iyenger 4. Alexopoulos and Mims

Who Discovered Heterothallism in Fungi?

Q.50 Name the fungus whose extract from the sclerotia can be used to produce a powerfull hallucinogenic drug? 1. Agaricus 2. Claviceps purpurea 3. Alternaria solani 4. Neurospora crassa

Fungus Producing Hallucinogenic Drug

Q.49 Which of the following algae are used as bio-fertilizers? 1. Spirogyra, Gloiopeltis, Ulothrix 2. Ulothrix, Chara and Anabaena 3. Anabaena, Azolla, Nostoc 4. Nostoc, Volvox, Anabaena

Algae Biofertilizers

Q.48 The shape of chloroplast in Spirogyra is 1. Cup-shaped 2. Spiral 3. Girdle shaped 4. Discoid

Spirogyra Chloroplast Shape

Q.47 Match List I with List II List I (Plants source) List II (Uses) A. Allium sativa B. Coptis japonica C. Taxus baccata D. Digitalis lanata I. Anticarcinogenic II. Cardiac medicine III. Insecticidal IV. Antibacterial Choose the correct answer from the options given below: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) (A) - (I), (B) - (III), (C) - (II), (D) - (IV) (A) - (III), (B) - (IV), (C) - (I), (D) - (II) (A) - (I), (B) - (IV), (C) - (III), (D) - (II)

 Medicinal Plants Matching

Q.46 The role of ethylene in plants is: 1. senescence of leaves and ripining of fruits 2. cell division 3. inhibition of root growth 4. production of tuber and bulb formation

Ethylene Plant Hormone Role

Q.45 Given below are two statements, one is labelled as Assertion (A) and other one labelled as Reason (R). Assertion (A) : The application of transgenic plants are in the delayed ripening, production of bioplastic, plant as a bioreactor for the production of antibodies, etc. Reason (R) : Agrobacteria that carries a recombinant plasmid with both a selectable marker and a desired transgene are used to make plant transgenic. In light of the above statements, choose the correct answer from the options given below. 1. Both (A) and (R) are true and (R) is the correct explanation of (A). 2. Both (A) and (R) are true but (R) is NOT the correct explanation of (A). 3. (A) is true but (R) is false. 4. (A) is false but (R) is true.

Transgenic Plants Assertion Reason

Q.44 Given below are two statements, one is labelled as Assertion (A) and other one labelled as Reason (R). Assertion (A) : Osmosis is a special type of diffusion in which movement of substances occurs from higher solute concentration to lower solute concentration. Reason (R) : Diffusion is dominant mode of transport at the scale of a cell. In light of the above statements, choose the correct answer from the options given below. 1. Both (A) and (R) are true and (R) is the correct explanation of (A). 2. Both (A) and (R) are true but (R) is NOT the correct explanation of (A). 3. (A) is true but (R) is false. 4. (A) is false but (R) is true.

Osmosis Assertion Reason

Q.43 Selenocysteine is an amino acid, which is: 1. present in only prokaryotes 2. coded by UGA 3. derived from cysteine 4. is present in many eukaryotic proteins

Selenocysteine Characteristics

Q.42 Given below are two statements, one is labelled as Assertion (A) and other one labelled as Reason (R). Assertion (A) : Euchromatin is transcriptionally active and contains most of the protein-coding DNA. Reason (R) : Heterochromatin is light staining and less condensed portion of the chromatin. In light of the above statements, choose the correct answer from the options given below. 1. Both (A) and (R) are true and (R) is the correct explanation of (A). 2. Both (A) and (R) are true but (R) is NOT the correct explanation of (A). 3. (A) is true but (R) is false. 4. (A) is false but (R) is true.

Euchromatin vs Heterochromatin

Q.41 Match List I with List II List I (Group-1) List II (Group-2) A. VNTR sequence B. Leader sequence C. SD sequence D. Cis-acting sequence I. Gene regulation of the same chromosome II. Ribosome binding site III. DNA finger printing IV. Function in attenuation Choose the correct answer from the options given below: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) (A) - (III), (B) - (IV), (C) - (II), (D) - (I) (A) - (I), (B) - (II), (C) - (IV), (D) - (III) (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

VNTR, Leader, SD & Cis-Acting Sequences Matching

Q.40 Which of the following is true about Poly(A) tail ? (A). Synthesizes post transcriptionally (B). Usually shorter than 300 nt (C). Its function is to protect the mRNA from cytoplasmic RNAases (D). Its function is to stimulate translation Choose the correct answer from the options given below: 1. (A), (B) and (D) only. 2. (A), (B) and (C) only. 3. (A), (B), (C) and (D). 4. (B), (C) and (D) only.

Poly(A) Tail

Q.39 Which of the following is the most common form of a DNA? 1. Z-DNA 2. A-DNA 3. B-DNA 4. C-DNA

Most Common DNA Form

Q.38 The amount of DNA present in the genome of a species is called as 1. D-value 2. C-value 3. B-value 4. T-value

C-Value in Genome Biology

Q.37 The enzyme which converts citrate to isocitrate in TCA cycle is: 1. Aconitase 2. Isocitrate dehydrogenase 3. Fumarase 4. Trans ketolase

TCA Cycle Enzyme

Q.36 Jasmonic acid 1. is synthesized from linolenic acid 2. is growth promoter 3. delays leaf senescence 4. present in the mosses and ferns

Jasmonic Acid

Q.35 Lignin (A). is a polysaccharide (B). is second most abundant organic compound (C). is a polymer of aromatic alcohols (D). synthetic pathway is peroxidase dependent Choose the correct answer from the options given below: 1. (A), (B) and (D) only. 2. (A), (B) and (C) only. 3. (A), (B), (C) and (D). 4. (B), (C) and (D) only.

What is Lignin?

Q.34 The total number of ATP is required for the conversion of one N2 to 2 NH4+ during biological N2 fixation? 8 ATP 10 ATP 12 ATP 16 ATP

How Many ATP for N2 to 2 NH4+ in Biological Nitrogen Fixation?

Q.33 'B' gene of ABCD flower model is made silenced in a plant. Which of the whorl is absent in the plant. (A). Sepals (B). Carpels (C). Stamens (D). Petals Choose the correct answer from the options given below: 1. (B) and (D) only. 2. (B) and (C) only. 3. (A) and (B) only. 4. (C) and (D) only.

ABC Model Flower Development

Q.32 Which is not a transmembrane protein? 1. ATP synthase 2. LHC 3. PS II 4. Ferredoxin

Which is Not a Transmembrane Protein?

Q.31 Which of the following technique is used to inactivate a gene by altering the DNA 1. Homologous recombination 2. Antisense nucleic acid block 3. Antibody microinjection 4. Introduction of dominant inhibitory mutant

Gene Inactivation Techniques

Q.30 Agrobacterium rhizogenes is used to genetically engineer the plant because of the following statement 1. It contains a Ti plamid 2. It causes gene transfer to plants 3. It infects all types of plants 4. Infects plants and produce a good root system

Agrobacterium Rhizogenes Genetic Engineering

Q.29 Match List I with List II List I (Terms) List II (Example) A. Halophile B. Acidophile C. Thermophile D. Microaerophile I. Thermus aquaticus II. Treponema III. Halobacterium IV. Sulfolobus Choose the correct answer from the options given below: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) (A) - (I), (B) - (III), (C) - (II), (D) - (IV) (A) - (I), (B) - (II), (C) - (IV), (D) - (III) (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Extremophiles MCQ

Q.28 What are the basic properties of Gram positive (+ve) bacteria (A). Thick peptidoglycan layer is present (B). Teichoic acids are present (C). Periplasmic space is negligible (D). Outer membrane is present Choose the correct answer from the options given below: 1. (A), (B) and (D) only. 2. (A), (B) and (C) only. 3. (A), (B), (C) and (D). 4. (B), (C) and (D) only.

Gram Positive Bacteria Properties

Q.27 N-acetylglucosamine (NAG) and N- acetylmuramic acid (NAM) in cell wall of bacteria are connected by: 1. ß-1,4 glycosidic bond 2. ß-1,2 glycosidic bond 3. ß-1,3 glycosidic bond 4. ß-2,4 glycosidic bond

N-Acetylglucosamine and N-Acetylmuramic Acid

Q.26 Which types of protein is commonly found in RBC? 1. Glyoprotein 2. Spectrin 3. Ankyrin 4. Spectrin and Ankyrin

RBC Proteins

Q.25 Myoglobin is a globular protein, which is made up of 1. 159 2.153 3.160 4.170

Myoglobin Amino Acids

Q.24 Which of the following is correct statement about ATP A. It contains two phosphodiester bond B. It has one phosphate ester bond C. It contains ribose sugar D. It contains adenosine as nucleoside Choose the correct answer from the options given below: 1. (A) - (I), (B) - (II), (C) - (III), (D) - (IV) 2. (A) - (I), (B) - (III), (C) - (II), (D) - (IV) 3. (A) - (I), (B) - (II), (C) - (IV), (D) - (III) 4. (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

ATP Structure MCQ

Q.23 Match List I with List II List I (Chemical nature of side chain) List II (Amino Acid) A. Aliphatic amino acid B. Sulphur containing C. Imino D. Amide I. Pro II. Gln III. Val IV. Cys Choose the correct answer from the options given below: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) (A) - (I), (B) - (III), (C) - (II), (D) - (IV) (A) - (I), (B) - (II), (C) - (IV), (D) - (III) (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Matching Amino Acid Side Chains

Q.22 The ideal value for the backbone dihedral angles for antiparallel β-sheets are: (A) φ = −120° and ψ = +125° (B) φ = −139° and ψ = +135° (C) φ = −120° and ψ = +130° (D) φ = −115° and ψ = +140° Choose the correct answer from the options given below: (A) and (D) only (B) only (A), (B) and (C) only (B), (C) and (D) only

Ideal Dihedral Angles for Antiparallel β-Sheets

Q.21 Which amino acid(s) contain/s the amino group (-NH2) attached as a side chain. 1. Lys 2. Arg 3. Asn 4. Lys and Arg

Which Amino Acid Has -NH₂ Side Chain?

Q.20 Malacophyllous leaves are found in 1. submerged hydrophytes 2. xerophytes 3. amphibious plants 4. free floating hydrophytes

Malacophyllous Leaves

Q.19 The anamalous distribution of vascular tissues in older stem of Bougainvillea is due to (A). formation of accessory cambial rings (B). formation of interxylary phloem (C). abnormal behaviour of normal cambium (D). abnormal behaviour of abnormal cambium Choose the correct answer from the options given below: 1. (A) only. 2. (A), (B) and (C) only. 3. (A), (B), (C) and (D). 4. (B), (C) and (D) only.

Bougainvillea Stem Anomalous Vascular Distribution

Q.18 Match List I with List II List I (Stomata type) List II (Family) A. Anomocytic B. Anisocytic C. Paracytic D. Diacytic I. Acanthaceae II. Magnoliaceae III. Apiaceae IV. Papaveraceae Choose the correct answer from the options given below: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) (A) - (I), (B) - (III), (C) - (II), (D) - (IV) (A) - (I), (B) - (II), (C) - (IV), (D) - (III) (A) - (IV), (B) - (III), (C) - (II), (D) - (I)

Botany Stomata Types Families Matching

Q.17 Given below are two statements, one is labelled as Assertion (A) and other one labelled as Reason (R). Assertion (A) : Root apical cell theory of Nageli does not hold good for flowering plants Reason (R) : In flowering plants, a group of initials has been observed In light of the above statements, choose the correct answer from the options given below. 1. Both (A) and (R) are true and (R) is the correct explanation of (A). 2. Both (A) and (R) are true but (R) is NOT the correct explanation of (A). 3. (A) is true but (R) is false. 4. (A) is false but (R) is true.

Root Apical Cell Theory Nageli

Q.16 Hanstein proposed - 1. Apical cell theory 2. Histogen theory 3. Tunica corpus theory 4. Histogen layer theory

Hanstein Proposed Which Theory?

Q.15 The important character of the family Asteraceae is (A). Inflorescence is a racemose head or capitulum (B). Presence of cypsela fruit (C). Presence of gynostegium (D). Placentation is free central Choose the correct answer from the options given below: 1. (A) and (B) only. 2. (A), (B) and (C) only. 3. (A), (B), (C) and (D). 4. (B), (C) and (D) only.

Asteraceae Family Characteristics

Q.14 Given below are two statements, one is labelled as Assertion (A) and other one labelled as Reason (R). Assertion (A) : APG classification system is not useful for adoption in herbaria and flora Reason (R) : APG system taxa have been classified only up to the level of family In light of the above statements, choose the correct answer from the options given below. 1. Both (A) and (R) are true and (R) is the correct explanation of (A). 2. Both (A) and (R) are true but (R) is NOT the correct explanation of (A). 3. (A) is true but (R) is false. 4. (A) is false but (R) is true.

APG Classification

Q.14 Match List I with List II List I (Taxonomic characters) List II (Families) A. Jaculators B. Caryopsis fruits C. Cyathium D. Cremocarp fruit I. Apiaceae II. Euphorbiaceae III. Poaceae IV. Acanthaceae Choose the correct answer from the options given below: (A) - (IV), (B) - (III), (C) - (II), (D) - (I) (A) - (I), (B) - (III), (C) - (II), (D) - (IV) (A) - (I), (B) - (II), (C) - (IV), (D) - (III) (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Jaculators Acanthaceae, Caryopsis Poaceae Matching

Q.12 Free central placentation is present in the family of 1. Brassicaceae 2. Cucurbitaceae 3. Caryophyllaceae 4. Capparaceae

Free Central Placentation Family

Q.11 The specimen collected from the same locality from where the holotype was collected is called as 1. Isotype 2. Topotype 3. Syntype 4. Paratype

 Specimen Collected from Same Locality as Holotype

Q.10 The most effective sugar in promoting pollen germination is 1. Glucose 2. Fructose 3. Sucrose 4. Maltose

Most Effective Sugar for Pollen Germination

Q.9 Given below are two statements, one is labelled as Assertion (A) and other one labelled as Reason (R). Assertion (A) : Male sterility in angiosperms can be induced by inserting a bacterial gene called BARNASE Reason (R) : BARNASE causes premature breakdown of tapetum resulting in arrest of microspore development In light of the above statements, choose the correct answer from the options given below. 1. Both (A) and (R) are true and (R) is the correct explanation of (A). 2. Both (A) and (R) are true but (R) is NOT the correct explanation of (A). 3. (A) is true but (R) is false. 4. (A) is false but (R) is true.

BARNASE Gene Male Sterility

Q.8 Match List I with List II List I (Processes) List II (Scientists) A. Intra ovarian pollination B. Double fertilization C. Syngamy D. Necrohormone theory I. L. Haberlandt II. E. Strasburger III. S. Nawaschin IV. Kanta Choose the correct answer from the options given below: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) (A) - (I), (B) - (III), (C) - (II), (D) - (IV) (A) - (I), (B) - (II), (C) - (IV), (D) - (III) (A) - (IV), (B) - (III), (C) - (II), (D) - (I)

Plant Reproduction Matching

Q.7 The different methods to overcome self incompatibility are (A). mixed pollination (B). bud pollination (C). stub pollination (D). intra-ovarian pollination Choose the correct answer from the options given below: 1. (A), (B) and (D) only. 2. (A), (B) and (C) only. 3. (A), (B), (C) and (D). 4. (B), (C) and (D) only.

Methods to Overcome Self-Incompatibility

Q.6 Inverted ovules are called as 1. Orthotropus 2. Anatropus 3. Amphitropus 4. Hemianatropus

Inverted Ovules

Q.5 The decreasing order of concentration of green house gases (GHGs) in the atmosphere is : (A). CO2 (B). CH4 (C). CFCs (D). N2O Choose the correct answer from the options given below: 1. (A), (B), (C), (D). 2. (A), (C), (B), (D). 3. (B), (A), (D), (C). 4. (C), (B), (D), (A).

Decreasing Order of Greenhouse Gas Concentrations

Q.4 Given below are two statements, one is labelled as Assertion (A) and other one labelled as Reason (R). Assertion (A) : The zone of transition between two communities is called an ecotone Reason (R) : The ecotone has more diversity than either of the two communities In light of the above statements, choose the correct answer from the options given below. 1. Both (A) and (R) are true and (R) is the correct explanation of (A). 2. Both (A) and (R) are true but (R) is NOT the correct explanation of (A). 3. (A) is true but (R) is false. 4. (A) is false but (R) is true.

Ecotone Assertion Reason

Q.3 Match List I with List II List I (Processes) List II (Changes) A. Nudation B. Ecesis C. Reaction D. Stabilization I. Creation of barren area II. Establishment of species III. Community in equilibrium with organisms IV. Modification of habitat Choose the correct answer from the options given below: (A) - (I), (B) - (II), (C) - (IV), (D) - (III) (A) - (I), (B) - (III), (C) - (II), (D) - (IV) (A) - (II), (B) - (I), (C) - (IV), (D) - (III) (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Ecological Succession Stages

Q.2 The important characteristic of k-selected population is (A). convex survivorship curve (B). low fecundity (C). exist close to their carrying capacity (D). intraspecific competition Choose the correct answer from the options given below: 1. (A), (B) and (D) only. 2. (A), (B) and (C) only. 3. (A), (B), (C) and (D). 4. (B), (C) and (D) only.

Understanding K-Selected Populations

Q.1 The causal agent of Byssinosis is: 1. Pollen dust 2. Arsenic 3. Cotton dust 4. Iron dust

Byssinosis Cause

Q.75 Which of the following cell organelle is regarded as semi-autonomous? 1. Chloroplast 2. Peroxisomes 3. Ribosomes 4. Lysosome
CUET PG Botany 2024 Previous Year Question Papers PDF with Solutions

Which Cell Organelle is Semi-Autonomous?

Q.75 Which of the following cell organelle is regarded as semi-autonomous? 1. Chloroplast 2. Peroxisomes 3. Ribosomes 4. Lysosome Semi-Autonomous Organelles: Chloroplast MCQ Answer Semi-autonomous organelles contain their own DNA and ribosomes, enabling partial self-replication independent of the nucleus. Chloroplasts exemplify this in plant cells, crucial for NEET and CSIR NET biology exams. Correct Answer […]

Q.74 There are different possible glucuronides that can be used as substrates for the ß- glucuronidase (GUS-reporter system), depending on the type of detection needed. The most common substrate for GUS histochemical staining is? 1. Galactic acid 2. 5-chloro-4-bromo-3-indolyl glucuronide 3. 5-bromo-4-chloro-3-indolyl glucuronide 4. 5,5'-dibromo-4,4'-dichloro-indigo
CUET PG Botany 2024 Previous Year Question Papers PDF with Solutions

GUS Histochemical Staining Substrate

Q.74 There are different possible glucuronides that can be used as substrates for the ß- glucuronidase (GUS-reporter system), depending on the type of detection needed. The most common substrate for GUS histochemical staining is? 1. Galactic acid 2. 5-chloro-4-bromo-3-indolyl glucuronide 3. 5-bromo-4-chloro-3-indolyl glucuronide 4. 5,5′-dibromo-4,4′-dichloro-indigo GUS Histochemical Staining: Correct Substrate The GUS reporter system uses […]

Q.73 Which disease is a severe form of protein-energy malnutrition which results when a person does not consume enough protein and calories? 1. Lathyrism 2. Marasmus 3. Favism 4. Night blindness
CUET PG Botany 2024 Previous Year Question Papers PDF with Solutions

Severe Protein-Energy Malnutrition Explained

Q.73 Which disease is a severe form of protein-energy malnutrition which results when a person does not consume enough protein and calories? 1. Lathyrism 2. Marasmus 3. Favism 4. Night blindness Marasmus is the correct answer, as it represents a severe form of protein-energy malnutrition caused by insufficient protein and calorie intake. What is Marasmus? […]

Q.71 What is the correct sequence of the steps which takes place in Polymerase Chain Reaction (PCR)? 1. Annealing, Extension, Denaturation 2. Denaturation, Annealing, Extension 3. Extension, Denaturation, Annealing 4. Denaturation, Extension, Annealing
CUET PG Botany 2024 Previous Year Question Papers PDF with Solutions

PCR Steps Sequence

Q.71 What is the correct sequence of the steps which takes place in Polymerase Chain Reaction (PCR)? 1. Annealing, Extension, Denaturation 2. Denaturation, Annealing, Extension 3. Extension, Denaturation, Annealing 4. Denaturation, Extension, Annealing PCR Steps: Correct Sequence in Polymerase Chain Reaction PCR, or Polymerase Chain Reaction, amplifies DNA segments through repeated thermal cycles. The correct […]

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