Category: TIFR Previous Year Question Papers 2025 Biology With Answer Key Download

Category: TIFR Previous Year Question Papers 2025 Biology With Answer Key Download

TIFR Previous Year Question Papers 2025 Biology With Answer Key Download

60. A predatory fish blows bubbles just before it approaches and stuns its prey. A student postulated that blowing bubbles is a socially learned behavior and is a not heritable trait. To test this hypothesis, she raised the offsprings of the wildtype fishes either in “treatment 1”: the fishes were raised in a tank with the parent population or “treatment 2”: they were raised in a tank in isolation without any conspecifics. If blowing bubbles is not a socially learnt behavior, we would expect: a) None of the fishes in treatment 1 and 2 will blow bubbles b) Individuals in both treatment 1 and 2 will blow bubbles c) 75% fishes in treatment 1 will blow bubbles but none in treatment 2 d) 75% fishes in treatment 2 will blow bubbles but none in treatment 1

Predatory Fish Bubbles Social Learning Hypothesis

59. You restriction map a vector using Bam HI, Eco RI and Hae III and obtained fragments of the following sizes. Draw a restriction map of the vector and determine which of the following statements is correct. Results: Bam HI alone: 4,000bp; Eco RI alone: 4,000bp; Hae III alone: 3,000bp and 1,000bp; Bam HI and Eco RI: 3,500bp, 500bp; Bam HI and Hae III: 2,300bp, 1,000bp, 700bp; Eco RI and Hae III: 2,8000bp, 1,000bp, 200bp; Bam HI, Eco RI, and Hae III: 2,300bp, 1,000bp, 500bp, 200bp Answer a. There are three Hae III sites in this vector b. Bam HI is 1,000bp away from Eco RI c. Bam HI is present within the smaller fragment from the Hae III digestion d. Eco RI is present within the larger fragment from the Hae III digestion

Restriction Mapping Vector BamHI EcoRI HaeIII Fragments

58. One molecule of a small Ras-like GTPase (Ras) of 22 kDa forms a strong high affinity complex with one molecule of the GTPase activating protein (GAP) of 50 kDa. The complex was analysed using size exclusion chromatography and the profile is shown below. The peaks 1, 2, 3 labeled in the profile were analysed on an SDS-PAGE gel. How many bands do you expect to see in the SDS-PAGE profile for the three lanes corresponding to peaks 1, 2 and 3 under reducing condition? A. Peak 1 – 3 bands at 72, 50 and 22 kDa; Peak 2 – 1 band at 50 kDa; Peak 3 – 1 band at 22 kDa B. Peak 1 – 1 band at 22 kDa; Peak 2 – 1 band at 50 kDa; Peak 3 – 3 bands at 72, 50 and 22 kDa C. Peak 1 – 1 band at 22 kDa; Peak 2 – 1 band at 50 kDa; Peak 3 – 2 bands at 50 and 22 kDa D. Peak 1 – 2 bands at 50 and 22 kDa; Peak 2 – 1 band at 50 kDa; Peak 3 – 1 band at 22 kDa

Ras–GAP Size Exclusion Chromatography

57. Orobanche is an obligate parasitic plant. Despite being a plant, it is not an autotroph. It is related to an autotrophic plant Mimulus and an autotrophic partial parasite Triphysaria as shown in the following rooted tree. Which of the following statements is most likely to be true about the evolution of Orobanche? Assume maximum parsimony. (a) The ancestor lacked photosynthetic apparatus, which was gained independently and exclusively in the Mimulus and Triphysaria lineages (b) Photosynthetic machinery was present in all the ancestral nodes, but lost specifically in the terminal branch leading to Orobanche (c) Photosynthesis was lost following the branching of Mimulus, but regained in the terminal branch to Triphysaria. (d) Rooted trees cannot be used to make predictions about ancestral states under the maximum parsimony assumption.

Evolution of Orobanche

56. Assume a gene does not have any introns, any upstream promoter or regulatory element, or any element post the DNA sequence ending at the STOP position. If a hypothetical genome has only 500 genes – and each gene encodes an mRNA for a 50 kDa protein. What would be the approximate size of this genome? A) 275 kb B) 250 kb C) 500 kb D) 750 kb

Genome Size Calculation

55. At the Hogwarts School of Wizardry they use the fairly modern science of genetics to identify potential witches and wizards. Being a witch or a wizard is dependent on the presence of an autosomal dominant trait (the W allele). The W allele can be suppressed by the squib allele (s), an unlinked autosomal recessive trait. Presence of two s alleles can lead to no magical powers in individuals with the W allele. Given these observations what fraction of the progeny from the cross outlined below will be capable of performing magic and candidates for the Hogwarts School of Wizardry? ww:ss x Ww:Ss a. 1/4 b. 1/8 c. 1/2 d. 0

Hogwarts Genetics Problem

54. Bananas we routinely eat are seedless because A) They are naturally parthenogenetic B) They are triploid C) They are haploid D) Their fruits develop faster than the seeds

Why Bananas We Eat Are Seedless

53. In the euarchaeotic bacterium Pyrococcus furiosus the glycolysis pathway is modified by the use of ADP dependent glucokinase and ADP dependent phosphofructokinase. What will be the net gain of ATP during glycolysis in P. furiosus? A. 2 B. 3 C. 4 D. 6

Net ATP Gain in Pyrococcus furiosus Glycolysis

52. Many biological processes are known to oscillate over time, which are represented by an increase in a molecular factor followed by a decrease, which continues over time. Which of the following mechanisms would lead to multiple cycles of oscillating protein amounts in a cell over time? a) A constant activator of protein production that is regulated by a positive feedback loop. b) A constant activator of protein production that is regulated by a negative feedback loop. c) A one-time activator of protein production that is regulated by a negative feedback loop. d) A one-time activator of protein production that is regulated by a positive feedback loop.

How Negative Feedback Loops with Constant Activation Generate Sustained Biological Oscillations

51. After fertilization, cells in vertebrate embryos divide at regular intervals giving rise to a mass of cells termed the blastula. As cells divide, they undergo cleavage, where the enormous volume of the egg cytoplasm is slowly divided into numerous small cells, such that the total volume of the embryo remains the same. How embryo maintains its overall volume during this process? a) Cells in early vertebrate embryos do not have G1 and G2 phases and hence do not increase in volume. b) Cells in early vertebrate embryos do not have the S phase and hence do not increase in volume. c) Cells have all cell cycle phases, but they halve protein production in every cell cycle. d) Cells normally increase in volume as any dividing cell but degrade the half the material to ensure embryo volume is maintained.

How Vertebrate Embryo Maintains Volume During Cleavage

50. Species S1 and S2 use the same resource R, with S1 being more efficient in using the resource. A predator P consumes both prey species, but at different rates. Which statement is CORRECT? a. P will always eat S2, because it is an inferior competitor to S1 b. S1 will outcompete S2, unless the predator eats more of S1 c. P has no impact on the outcome of competition between S1 and S2 d. P will always preferentially consume S1 because it will be more abundant

Predator-Prey Competition

49. Carbon dioxide in the blood is mostly _____________. A. bound to albumin B. bound to hemoglobin C. in the form of carbonic acid D. bound to myoglobin

Carbon Dioxide in Blood Transport

48. A woman is heterozygous for both phenylketonuria mutation and for X-linked hemophilia mutation. She has a child with a phenotypically normal man, who is also heterozygous for a phenylketonuria mutation. What is the probability that the child will be affected by both the diseases? A. 1/8 B. 1/4 C. 1/16 D. 3/8

Probability Child Affected Both Phenylketonuria Hemophilia Heterozygous Parents

47. A friend of yours measured the quantity of DNA in grasshopper cells growing in the cell culture. Cells examined during the G2 phase of the cell cycle contained 200 units of DNA/cell. What would be the amount of DNA/cell in grasshopper cells seen in the anaphase of mitosis? A. 50 units B. 100 units C. 400 units D. 200 units

Grasshopper Cells DNA Content G2 Phase 200 Units Anaphase Mitosis

46. The time required for replication of the E.coli chromosome is 40 minutes but the bacterium is capable of dividing every 20 minutes under the right nutritional conditions. This is because DNA replication can initiate in the daughter chromosomes before the initial replication is completed. How many replication bubbles would be observed if DNA replication initiates one additional time over a single cell division cycle? a. 2 b. 4 c. 3 d. 5

E. coli Replication Bubbles

45. If the backbone -NH2 group in amino acids are modified to -NH(CH3) group, how will the allowed regions in Ramachandran map of the modified protein change? A. Allowed region remain unchanged. B. Allowed regions shrink. C. Allowed regions expand. D. It depends on the specific amino acid side chains.

Ramachandran Map Changes

44. The keto (left) and enol (right) tautomerized structures of guanine is shown below. The keto and enol forms of cytosine and thymine are shown below. Which of the following bases will the enol form of guanine most stably base pair with A. Amino form of cytosine B. Imino form of cytosine C. Keto form of Thymine D. Enol form of Thymine

Enol Form of Guanine

43. An enzyme has a Vmax of 50 mol product formed (minute X mg protein)-1 and a Km of 10 M for the substrate. When a reaction mixture contains the enzyme and 5 M substrate, which of the following percentage of the maximum velocity will be closest to the initial reaction rate? a. 5% b. 15% c. 33% d. 50%

Enzyme Vmax 50 Km 10ÎŒM 5ÎŒM Substrate Percentage Maximum Velocity

42. Arrange the metabolites in increasing order of phosphoryl transfer potential p) ATP, q) Phosphoenolpyruvate, r) 1,3-Bisphosphoglycerate, s) pyrophosphate a) s

Arrange Metabolites in Increasing Order of Phosphoryl Transfer Potential

41. The spine of a neuron is approximately a sphere of diameter 1ÎŒm. The concentration of K+ within this spine is 150mM. How many K+ ions are in this sphere? Assume Avagadro's number is 6.023 * 1023. Choose the option closest to the correct answer. a. 5 * 1010 b. 5 * 107 c. 5 * 105 d. 5 * 1012

Neuron Spine K+ Ions Calculation: 1ÎŒm Sphere 150mM Concentration

40. Which number of signals are observed for the following compound in 13C-NMR proton decoupled spectrum? A. One B. Two C. Eight D. Four

Number of Signals in 1313C‑NMR Proton Decoupled Spectrum of Cyclooctane

39. The following pair of compounds is an example of

Keto–Enol Tautomerism: Why This Pair of Compounds Are Functional Isomers

38. Secondary alcohols on catalytic dehydrogenation by Cu-Ni couple give; a) Ketone b) Aldehyde c) Carboxylic acid d) Amine

Secondary Alcohols Catalytic Dehydrogenation Cu-Ni Couple Gives Ketone

37. Which of the following equations represents an oxidation-reduction reaction? A. Ba(NO3)2 + Na2SO4 → BaSO4 + 2NaNO3 B. H3PO4 + 3KOH → K3PO4 + 3H2O C. Fe(s) + S(s) → FeS(s) D. NH3(g) + HCl(g) → NH4Cl(s)

Identifying Oxidation-Reduction Reactions

36. The pKa of the amino group of a zwitterion is 9.6. In a 0.1 M solution of the zwitterion at pH=9.0, what percentage of the amino group of the zwitterion is protonated? A. 80% B. 60% C. 40% D. 20%

Zwitterion Amino Group Protonation at pH 9.0

35. A wild type protein and its mutants E107A and E107D were analysed using isoelectric focussing, Which of the following options are most likely to correspond to lanes A and B in the figure below? A. A – Wild type; B – E107A mutant B. A - E107A mutant; B – WT C. A - wild type; B – E107D mutant D. A - E107A mutant; B – E107D mutant

Isoelectric Focusing Question on E107A and E107D Mutants

34. In a complexometric titration S (substrate) + T (Titrant) → P (Product) The end point is estimated spectrophotometrically. If S and P have Δ = 0, the shape of the titration curve is which of the following?

Spectrophotometric Complexometric Titration Curve When Only Titrant Absorbs

33. Electric potential is a ______________ quantity A. Vector B. Scalar C. Tensor D. Pseudo Vector

Electric Potential is a Scalar Quantity

32. Which among the following is the easiest method to estimate the concentration of glycerol in an aqueous solution of glycerol? A. UV absorption spectroscopy B. Gas chromatography C. pH measurement D. Viscosity measurement

Easiest Method to Estimate Glycerol Concentration in Aqueous Solution

31. Which of the following is an aromatic compound?

Which of the Following Is an Aromatic Compound?

30. Suppose a two-wire transmission line has a basic element as represented above. Assume the special case of a lossless line where 𝑅=0 and đș=0. Which of the following equations describes this system:

Lossless Two‑Wire Transmission Line Equations

29. Assume that the Earth is in a circular orbit around the sun. If the mass of the sun is suddenly reduced to half of its original value, what will happen to the Earth? a. It will settle into a smaller orbit. b. It will remain in the same orbit. c. It will settle into a larger orbit. d. It will escape from the sun.

Earth Orbit Sun Mass Half Reduced Effect

28. A cricket ball and a table tennis ball are dropped with zero initial vertical velocity. Each will eventually reach a different terminal velocity in air. Which of the following is true? (We can say the ball "reaches" its terminal velocity when it hits 99% of the expected value.) a. The cricket ball has a higher terminal velocity and will reach it later. b. The table tennis ball has a higher terminal velocity and will reach it later. c. The cricket ball has a higher terminal velocity and will reach it sooner. d. The table tennis ball has a higher terminal velocity and will reach it sooner.

Cricket Ball vs Table Tennis Ball Terminal Velocity

27. A particle moves under the potential 𝑈(đ‘„) = 𝑒 +0.01đ‘„ . Which of the following describes the equilibrium points in the region −∞ < đ‘„ < ∞ a. b. c. d. One stable point, no unstable points One unstable points, no stable points Two stable points, one unstable point Two unstable points, one stable point

Particle Equilibrium Points in Potential U(x) = e0.01x + x

26. Imagine the gas that forms the thin atmosphere of a small exoplanet at a constant temperature. The speed of gas molecules at equilibrium are described by the Maxwell Boltzmann distribution. Molecules whose speed exceeds the escape velocity will occasionally be lost to space. Once the system re-equilibriates at the same temperature, which of the following statements is correct about the distribution of speeds: a. b. c. d. It will be identical to the original distribution, but truncated beyond the escape velocity. It will be identical to the original distribution. It will be a new Maxwell-Boltzmann distribution with a lower average velocity than before. It will be a new Maxwell-Boltzmann distribution with a higher average velocity than before.

 Exoplanet Atmosphere Maxwell Boltzmann Distribution Escape Velocity Higher Average Velocity

25. In quantum mechanics, the simple harmonic oscillator has a non-zero rest energy. This is best understood as: a. b. c. d. A measurement convention, since the zero point of energy is arbitrary. The result of thermal fluctuations. The result of the uncertainty principle. An error due to our inability to measure small quantities.

 Quantum Harmonic Oscillator Non-Zero Rest Energy Uncertainty Principle

24. An ideal gas at pressure P_0, volume V_0 and temperature T_0 is allowed to isothermally expand to twice its initial volume. What is the final pressure? A) P_0/2 B) 2 P_0 C) P_0 D) Undetermined

Ideal Gas Isothermal Expansion Final Pressure Twice Volume P0/2

23. I measure a certain quantity and report the results in units of Newtons x metres. The quantity is a. b. c. d. a measure of work. a measure of torque. a measure of force. not clear from the given information.

Newton-Meters Units

22. A thin cylindrical rod is rotating on a horizontal plane about its center of mass, which is at rest. It breaks instantaneously into two cylindrical halves. The two resulting pieces a. b. c. d. Move apart without spinning. Spin but have their centres of mass at rest. Move apart and spin in the same direction as the original rod. Move apart and spin in opposite directions.

Thin Cylindrical Rod Rotating Breaks into Two Halves

22. A thin cylindrical rod is rotating on a horizontal plane about its center of mass, which is at rest. It breaks instantaneously into two cylindrical halves. The two resulting pieces a. b. c. d. Move apart without spinning. Spin but have their centres of mass at rest. Move apart and spin in the same direction as the original rod. Move apart and spin in opposite directions.

Thin Cylindrical Rod Rotating Breaks into Two Halves

21. The elephant-nosed weakly electric fish generate electric fields to locate and identify nearby objects. They detect distortion of their own electric organ discharge to identify nearby objects. Consider the two following statements: i. An object is detectable if its specific resistance is different from that of water ii. An object is detectable if its specific capacitance is different from that of water a. b. c. d. Both statements i and ii are true. Only statement i is true. Only statement ii is true. Neither statement i nor statement ii are true.

 Elephant-Nosed Fish Electrolocation

20. Fraunhofer lines are dark lines in the solar spectrum. They arise because a. b. the sun consists mainly of hydrogen and helium, which do not emit a continuous spectrum. the sun's outer regions contain other elements which emit various wavelengths, making the spectrum uneven. c. gases in the sun's outer region absorb specific wavelengths. d. the absorption of specific wavelengths by gasses in the Earth's atmosphere.

 Fraunhofer Lines Solar Spectrum

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Specific Gravity Alloy Equal Volumes 4 Equal Masses 3 Metals Densities

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Shape A Mapped onto Shape B by Translation Rotation Reflection Scale Transformation

17. The volume of a liquid is measured to be 100 ml with an uncertainty of ± 3 ml, and its mass is measured to be 100 g with an uncertainty of ± 4 g. By calculating mass over volume, the density is reported to be 1 g/ml. Assuming the errors are uncorrelated, what is the uncertainty in the reported density, measured in g/ml? a. b. c. d. 1/100 5/100 7/100 10/100

Uncertainty in Density Calculation Using Error Propagation

16. Four charges of magnitude 𝑞 are put on a square of side length 𝑎. If three of the charges are positive and one is negative, what is the magnitude of the electric field at the centre? The magnitude of the electric field at a distance r is 𝐾=𝑞/4𝜋𝜖𝑎 . a. 2𝑞/𝜋𝜖𝑎 b. 𝒒/𝝅𝝐𝟎𝒂𝟐 c. 𝑞/2𝜋𝜖𝑎 d. 0

Electric Field at Center of Square

15. A train runs at a speed of 90 kmph from P to Q and 110 kmph from Q to P? What is the average speed of the train during the entire journey? A. 98.0 kmph B. 99.0 kmph C. 100 kmph D. 101 kmph

Average Speed of Train from P to Q at 90 kmph and Return at 110 kmph

14.Based on the phylogenetic tree provided below, which of the following statements is true? a. F is more closely related to A than to G b. E and D share a common ancestor who is more recent than the ancestor of C and D c. B is more advanced than the others as it is located on the left most branch d. All the above are true

Phylogenetic Tree Question

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 Two Digital Clocks Lose Gain 5 Minutes Each Hour Same Time Again

12. Imagine that you are looking at one cancer cell under the microscope, and trying to estimate the probability that it will die due to a chemotherapy. You know that approximately 95% of cells treated with the chemotherapy turn on the P53 gene and that these cells have 80% chance of dying. The rest 5% that do not turn on P53, have only 10% chance of dying. What is the probability that the cell you're looking at will die? a. 76.5% b. 66.5% c. 86.5% d. None of the above

 Cancer Cell Chemotherapy Death Probability 95% P53 80% 5% 10%

11. In statistics, a distribution is considered symmetric if the mean, median, and mode are equal. If they differ, the distribution is termed asymmetric. If the right tail is longer, we have a positively skewed distribution. Conversely, if the left tail is longer, we have a negatively skewed distribution. For the data: 2,4,6,6, find the skewness? (a) Skewness is zero (b) Skewness is positive (c) Skewness is negative (d) Skewness is +infinity

Skewness of Data 2,4,6,6 in Statistics

10. To estimate the number of fish in a pond, a researcher catches 25 fish randomly, marks them with yellow paint and then puts them back in the pond. The researcher comes back the next day and again catches 25 fish randomly and finds that 5 of them have yellow paint. Estimate the total number of fish in the pond? a. 25 fish b. 125 fish c. 625 fish d. 250 fish

Estimate Total Fish in Pond Mark Recapture 25 Marked 5 Recaptured

9.What is the output of the following pseudocode program, which first defines a function functn and then calls it from a for-loop? def functn(n) if n==1 return 1 else return n*functn(n-1) endif enddef for i = 1 to 5 print functn(i) endfor (a) 1 2 3 4 5 (b) 1 1 2 3 5 (c) 1 2 6 24 120 (d) None of the above

Pseudocode Recursive Factorial Function Output for Loop i=1 to 5 Explained

8. Sum of the eigenvalues of the matrix 2 2 −1 5 3 1 1 4 −2 is ________. (1m) (a) 1 (b) 2 (c) 3 (d) None of the above

Sum of Eigenvalues of a 3×3 Matrix Using Trace Property

7. Which of the following is the largest? (1m) (a) 1001/100 (b) 1001/101 (c) 101/51 (d) 101/52

Which of the Following is the Largest?

6. If the diameter of a circle is increased by 30% then the area is increased by: (a) 30% (b) 60% (c) 69% (d) 90%

Diameter of Circle Increased by 30% Area Increased by

5. The lesion most commonly induced by UV radiation is ______. A. Chromosome breaks B. Transition C. Transversion D. Thymine dimer

UV Radiation Induced Lesion

4. A batsman scores 100 runs in the 15th inning and thus increases his average by 5. What will be the average after 15th inning? A. 27 B. 30 C. 32 D. 33

Batsman Scores 100 Runs 15th Inning Average Increases by 5

3. The next number in the series 2, 5, 11, 23, 47, ? will be. A. 95 B. 96 C. 97 D. 98

Next Number in Series 2, 5, 11, 23, 47

2. A flea is about 3mm tall but can jump to a height of about 30 cm. If a child is 36 inches tall had flea-like abilities, how high will she be able to jump? a. 36 feet b. 3000 feet c. 300 feet d. 360 feet

 Child 36 Inches Tall Flea Jump Height

1. What is the probability that the second child will be a boy for parents whose first child is also a boy? (a) 0.25 (b) 1 (c) 0.5 (d) 0

 Probability Second Child Boy Given First Child Boy

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