- Fruit colour of wild Solanum nigrum is controlled by two alleles of a gene (A and a). The
frequency of A, p=O.8 and a, q=O.2. In a neighbouring field a tetraploid genotype of S. nigrum was found.
After critical examination five distinct genotypes found; which are AAAA, AAAa, AAaa, Aaaa and aaaa. Following Hardy Weinberg principle and assuming the same allelic frequency as that of diploid population the numbers of phenotypes calculated within a population of 1000 plants are close to one of the following:
AAAA : AAAa : AAaa : Aaaa ; aaaa
(1) 409 :409:154:26:2
(2) 420: 420: 140: 18: 2
(3) 409:409:144:36:2
(4) 409: 420 144: 25: 2Calculating Tetraploid Genotype Frequencies in Solanum nigrum Using Hardy-Weinberg Principles
Polyploidy is common in plants and adds complexity to genetic calculations. In Solanum nigrum, a wild species with diploid, tetraploid, and hexaploid forms, understanding genotype frequencies in polyploid populations is essential for evolutionary and breeding studies. Here’s how to calculate expected genotype frequencies for a tetraploid population at a locus with two alleles (A and a), given known allele frequencies.
Problem Overview
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Alleles: A (frequency p=0.8), a (frequency q=0.2)
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Population: Tetraploid (each plant has 4 alleles per locus)
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Genotypes observed: AAAA, AAAa, AAaa, Aaaa, aaaa
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Population size: 1,000 plants
Step 1: Hardy-Weinberg for Tetraploids
For a tetraploid, the expansion is:
(p+q)4=p4+4p3q+6p2q2+4pq3+q4
This gives the genotype frequencies:
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AAAA: p4
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AAAa: 4p3q
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AAaa: 6p2q2
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Aaaa: 4pq3
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aaaa: q4
Step 2: Calculate Each Genotype Frequency
Plug in p=0.8, q=0.2:
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AAAA: (0.8)4=0.4096
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AAAa: 4×(0.8)3×0.2=4×0.512×0.2=0.4096
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AAaa: 6×(0.8)2×(0.2)2=6×0.64×0.04=0.1536
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Aaaa: 4×0.8×(0.2)3=4×0.8×0.008=0.0256
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aaaa: (0.2)4=0.0016
Step 3: Calculate Expected Numbers in 1,000 Plants
Multiply each frequency by 1,000:
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AAAA: 0.4096×1000=409.6≈409
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AAAa: 0.4096×1000=409.6≈409
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AAaa: 0.1536×1000=153.6≈154
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Aaaa: 0.0256×1000=25.6≈26
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aaaa: 0.0016×1000=1.6≈2
Step 4: Match with Provided Options
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(1) 409 : 409 : 154 : 26 : 2
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(2) 420 : 420 : 140 : 18 : 2
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(3) 409 : 409 : 144 : 36 : 2
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(4) 409 : 420 : 144 : 25 : 2
The correct answer is (1) 409 : 409 : 154 : 26 : 2.
Why This Calculation Matters
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Polyploid genetics: Accurate genotype frequency estimates are crucial for plant breeding and evolutionary studies.
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Conservation: Helps track genetic variation in wild populations.
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Research: Provides a basis for understanding inheritance and selection in polyploid species.
Conclusion
For a tetraploid Solanum nigrum population with allele frequencies p=0.8 and q=0.2, the expected genotype numbers among 1,000 plants are 409 AAAA, 409 AAAa, 154 AAaa, 26 Aaaa, and 2 aaaa. This demonstrates the power of Hardy-Weinberg principles in polyploid genetics.
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