Question 34:

Match List I with List II:

Choose the correct answer from the options given below:

(A) (A) – (IV), (B) – (III), (C) – (II), (D) – (I)
(B) (A) – (II), (B) – (IV), (C) – (III), (D) – (I)
(C) (A) – (II), (B) – (IV), (C) – (I), (D) – (III)
(D) (A) – (II), (B) – (IV), (C) – (I), (D) – (III)

Answer: (B) A-(ii), B-(iv), C-(iii), D-(i). This matches standard molecular weights: β-galactosidase ~116 kDa, BSA 66.2 kDa, ovalbumin 45 kDa, lysozyme 14.4 kDa.

Matching Details

List II values align with monomeric or subunit masses from biochemical data.

• A. β-galactosidase → (ii) 116.25 kDa (E. coli tetramer subunit ~116 kDa).

• B. Bovine Serum Albumin → (iv) 66.2 kDa (exact monomer mass).​

• C. Ovalbumin → (iii) 45 kDa (common value for glycoprotein).​

• D. Lysozyme → (i) 14.4 kDa (precise sequence-based mass).​

Option Analysis

• (A): Wrong—A to 66.2 (iv, too small), mismatches BSA.

• (B): Correct—all pairs fit verified weights.

• (C): Wrong—C to 14.4 (i, way too small).

• (D): Duplicate/wrong—C and D both to (i); invalid.

Introduction
Match list protein name molecular weight kDa is a staple in GATE Life Sciences for biochemistry recall. Question 34 tests pairings like β-galactosidase (116 kDa) and BSA (66 kDa).​

Protein Weights Explained

Molecular weights (kDa) indicate monomer sizes, vital for SDS-PAGE and purification.

• β-Galactosidase: 116 kDa subunit in E. coli enzyme.​

• BSA: 66.2-66.4 kDa standard.

• Ovalbumin: 45 kDa egg white protein.​

• Lysozyme: 14.4 kDa antimicrobial.

GATE Solved Matching

List I (Proteins) vs List II (kDa):
A. β-galactosidase → ii (116.25)
B. BSA → iv (66.2)
C. Ovalbumin → iii (45)
D. Lysozyme → i (14.4)

Answer: (B)—Precise matches from sequence data.​