5. If logx (5/7) = −1/3, then the value of x is (A) 343/125 (B) 125/343 (C) −25/49 (D) −49/25

5. If logx (5/7) = −1/3, then the value of x is

(A) 343/125
(B) 125/343
(C) −25/49
(D) −49/25

Final Answer: x = 343/125

Given Equation

logx(5/7) = −1/3

Step-by-Step Solution

Step 1: Convert Logarithmic Form to Exponential Form

Using the definition of logarithms:

logx(a) = b ⇒ xb = a

Therefore:

x−1/3 = 5/7

Step 2: Take Reciprocal of Both Sides

Taking reciprocal to remove the negative exponent:

x1/3 = 7/5

Step 3: Cube Both Sides

Cubing both sides:

x = (7/5)3

x = 343/125

Final Answer

x = 343/125

Verification

Substitute x = 343/125: (343/125)−1/3=(125/343)1/3=5/7

Hence, the solution is verified.

Option Analysis

Option Value Reason
(A) 343/125 Correct; equals (7/5)3
(B) 125/343 Reciprocal gives a positive logarithm
(C) −25/49 Negative base not allowed in real logarithms
(D) −49/25 Negative value; logarithm undefined

Introduction

The equation
logx(5/7) = −1/3
commonly appears in competitive exams such as GATE and JEE.
It tests understanding of logarithm rules, negative exponents,
and base restrictions.

Key Concept

If logb(a) = c, then bc = a.
A negative logarithmic value indicates that the argument is less than 1.

Exam Tips

  • Always ensure base > 0 and base ≠ 1
  • Argument of logarithm must be positive
  • Negative logarithm values often lead to reciprocal forms

Conclusion

Solving logx(5/7) = −1/3 by converting to exponential form
gives the unique valid solution:

x = 343/125

This structured approach ensures accuracy and is ideal for
competitive mathematics examinations.

 

Leave a Reply

Your email address will not be published. Required fields are marked *

Latest Courses