12. In the following diagram, segments A and C are copies of 10 base pair repeat DNA sequences, flanking a unique stretch shown as B, A and C are in inverted orientation as indicated by arrows. Intramolecular recombination between A and C leads to which event: (1) The complete region encompassing A to C will be inverted (2) Only A and B will be inverted (3) Only B will be inverted (4) Only regions A and C will be inverted

12. In the following diagram, segments A and C are copies of 10 base pair repeat DNA sequences, flanking a unique stretch shown as B, A and C are in inverted orientation as indicated by arrows. Intramolecular recombination between A and C leads to which event:

(1) The complete region encompassing A to C will be inverted
(2) Only A and B will be inverted
(3) Only B will be inverted
(4) Only regions A and C will be inverted

Intramolecular recombination between inverted repeats A and C will invert only the unique intervening segment B, leaving A and C in their original positions and orientations. This corresponds to option (3): only B will be inverted.​

Question recap

The DNA fragment contains two identical 10 bp repeat segments A and C in inverted orientation, flanking a unique central region B on the same DNA molecule. Intramolecular recombination between such inverted repeats typically causes inversion of the DNA segment located between them, while the repeats themselves remain as boundary elements.​

Correct option: Only B will be inverted (3)

Recombination between inverted repeats acts like a site‑specific recombination event that cuts and rejoins DNA so that the sequence between the two inverted sites flips 180° within the chromosome. Because A and C are the recombination sites, they pair, exchange strands, and rejoin, producing an inversion of B while A and C end up again flanking B in the same outer positions.​

Why option (1) is incorrect

Option (1) claims that the complete region from A to C (A–B–C) will be inverted, which would require recombination between sites outside A and C or a whole‑chromosome rearrangement. In site‑specific intramolecular recombination, only the internal segment between the two homologous recombination sites is inverted when those sites are inverted, not the entire flanking block including them.​

Why option (2) is incorrect

Option (2) suggests A and B will be inverted, leaving C unaffected. This cannot occur because both recombination sites (A and C) must participate simultaneously in the exchange; one cannot recombine alone. As a result, the recombination outcome is symmetric around the two sites, inverting only the central segment between them and not just one repeat plus part of the internal region.​

Why option (4) is incorrect

Option (4) proposes that only A and C will be inverted, with B unchanged. However, when two inverted repeats recombine, the product keeps the repeats as boundary elements but flips the orientation of the intervening DNA; the repeats themselves end up in the same relative orientation as before. Inverting only the repeats without affecting B would require a different arrangement (for example, repeats placed outside A and C), which is not the case here.​


Introduction

Intramolecular recombination between inverted repeats is a classic genome rearrangement that generates precise DNA inversions and often appears in CSIR NET Life Sciences questions. In the June 2017 paper, segments A and C are inverted 10 bp repeats flanking a unique region B, and understanding how their recombination affects B is essential for mastering DNA recombination concepts and solving similar exam problems quickly.​

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