6. In a transformation experiment, donor DNA from an E. coli strain with the genotypes was used to transform a strain of genotype Z+Y+. The frequencies of transformed classes were:
Z+ Y+ 200
Z+ Y– 400
Z– Y+ 400
Total 1000
What is the frequency (%) with which Y locus is co- transformed with the Z locus?
(1) 1 (2) 20
(3) 33.3 (4) 40
Experiment Overview
In this E. coli transformation experiment, donor DNA from a Z⁺Y⁺ strain transforms a Z⁻Y⁻ recipient. The transformed classes show Z⁺Y⁺: 200, Z⁺Y⁻: 400, and Z⁻Y⁺: 400 out of 1000 total transformants. Cotransformation frequency measures how often both Z⁺ and Y⁺ markers transfer together on the same DNA fragment, indicating genetic linkage. The formula uses the proportion of double transformants (Z⁺Y⁺) among all Z⁺ recipients.
Step-by-Step Calculation
Total Z⁺ transformants equal Z⁺Y⁺ plus Z⁺Y⁻: 200 + 400 = 600. Z⁺Y⁺ double transformants number 200. Frequency = (200 / 600) × 100 = 33.3%. This value reflects linkage; closer loci yield higher cotransformation.
Option Analysis
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Option (1) 1%: Far too low; ignores actual data ratio, possibly confusing with rare events.
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Option (2) 20%: Incorrect; matches 200/1000 (overall double transformants), not Z⁺-specific cotransformation.
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Option (3) 33.3%: Correct; precisely (Z⁺Y⁺ / total Z⁺) × 100 = 33.3%.
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Option (4) 40%: Wrong; no data supports this (e.g., not 400/1000), likely misread frequencies.
Correct Answer: (3) 33.3. This CSIR NET-style question tests bacterial genetics mapping via transformation.



1 Comment
Juber Khan
February 21, 2026Z+Y+= 200/1000✖️100= 20%
According to question if y locus is co transformed with z locus
Total no of z+ locus = 200(z+y+) +400(z+y) = 600
200/600✖️100 = 33.33~