(MODEL PAPER) 41. A solution of 1% (w/v) starch at pH 6.7 is digested by 15 µg of ß-amylase (mol wt 152,000). The rate of maltose (mol wt = 342) […]
Tag: csir pyq biochemistry
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CSIR NET Life Science Previous Year Questions and Solution on Biochemistry
Calculating Turnover Number (kcatkcat) for an Enzyme from Substrate and Product Data
(JUNE 2015) 40. A 1% (w/v) solution of a sugar polymer is digested by an enzyme (20µg, MW=200,000). The rate of monomer sugar (MW=400) liberated was determined to have a […]
CSIR NET Life Science Previous Year Questions and Solution on Biochemistry
Calculating Turnover Number and Specific Activity of an Enzyme: Step-by-Step Guide
(JUNE 2016) 39. The turnover number and specific activity of an enzyme (molecular weight 40,000 D) in a reaction (Vmax= 4µmol of substrate reacted/ min, enzyme amount = 2 µg) […]
CSIR NET Life Science Previous Year Questions and Solution on Biochemistry
Understanding Specific Activity of Enzymes: Definition, Calculation, and Importance
(DEC 2001) 38. Which statement is CORRECT regarding specific activity of enzyme? (1) Depends on concentration of substrate and amount of free enzyme (2) The number of enzyme units per […]
![(DEC 2019) 37. Given below is the [P] vs time plot of an enzymatic reaction carried out by the enzyme X Which one of the following statements is the correct interpretation of the data? (1) The Km and Vmax of the enzyme X are 15 and 60 units, respectively. (2) The Vmax is 60 but the Km cannot be determined (3) The Km 15 but the Vmax cannot be determined (4) Neither the Km nor the Vmax of the enzyme X can be determined from these data](https://www.letstalkacademy.com/wp-content/uploads/2025/09/37.jpg)
CSIR NET Life Science Previous Year Questions and Solution on Biochemistry
Interpreting [P] vs Time Plots in Enzyme Kinetics: Determining Vmax and Km
The correct answer is (2) The Vmax is 60 but the Km cannot be determined. Introduction Graphical data are fundamental tools in enzyme kinetics, helping derive quantitative parameters such as Vmax […]
![(JUNE 2018) 36. The Vmax and Km from a Lineweaver-Burk plot of an enzyme reaction where 1/v = 40µM-1 min at 1/[S] = 0 and 1/[S] = -1.5 x 102 mM-1 at 1/v = 0 are (1) 0.025 µM min-1 and 0.67 x 10-2mM (2) 0.025 µM-1 min and 0.67 x 10-2 (3) 0.025 µM min-1 and 1.5 x 102 mM-1 (4) 0.038 µM min-1 and 0.67 x 10-2mM](https://www.letstalkacademy.com/wp-content/uploads/2025/09/36-1.jpg)
CSIR NET Life Science Previous Year Questions and Solution on Biochemistry
Determining VmaxVmax and KmKm from a Lineweaver-Burk Plot: Step-by-Step Explanation
(JUNE 2018) 36. The Vmax and Km from a Lineweaver-Burk plot of an enzyme reaction where 1/v = 40µM-1 min at 1/[S] = 0 and 1/[S] = -1.5 x 102 […]
![(SEPT 2022-ll) 35. Given below are plots of the linear derivation of Michaelis-Menten kinetic equation and statements related to the variables (initial velocity-Vo and substrate concentration - [S]) used. A. In plot (i), both x and y axes have dependent variables B. In plot (ii) neither x nor y axis has independent variables C. In plot (i) only y-axis has a dependent variable D. In both the plots, x axis has an independent variable](https://www.letstalkacademy.com/wp-content/uploads/2025/09/35.jpg)
CSIR NET Life Science Previous Year Questions and Solution on Biochemistry
Identifying Dependent and Independent Variables in Enzyme Kinetic Linear Plots
The correct answer is (1) A, B and D only. Introduction Linear transformations of the Michaelis-Menten equation allow extraction of key enzyme kinetics parameters. These transforms produce specific plots, notably the […]
![(JUNE 2012) 33. A plot of V/[S] versus V is generated for an enzyme catalyzed reaction, and a straight line is obtained. Indicate the information that can be obtained from the plot. (1) Vmax and Km can be obtained only from a plot of 1/V versus 1/[S]. (2) Km/Vmax from the slope (3) Vmax and Km (4) only Km](https://www.letstalkacademy.com/wp-content/uploads/2025/09/33.jpg)
CSIR NET Life Science Previous Year Questions and Solution on Biochemistry
Interpreting a Plot of V/[S]V/[S] vs. VV in Enzyme Kinetics: Extracting Km and Vmax
(JUNE 2012) 33. A plot of V/[S] versus V is generated for an enzyme catalyzed reaction, and a straight line is obtained. Indicate the information that can be obtained from […]
CSIR NET Life Science Previous Year Questions and Solution on Biochemistry
Calculating Km and Ks in Michaelis-Menten Enzyme Kinetics: Strategy and Application
The correct answer is (4) Kₛ: 400 μM, Kₘ: 408 μM. Introduction Michaelis-Menten kinetics provides a foundation for understanding enzyme-catalyzed reactions. Two important constants—substrate dissociation constant (KsKs) and Michaelis constant (KmKm)—help […]
![(FEB 2022-11) 31. What is the fold difference between v at [S] =Km and v at [S] = 1000 Km where v is the initial velocity of an enzyme catalyzed reaction, [S] is substrate concentration and Km is the Michaelis constant? (1) 1.998 (2) 1000 (3) 2.998 (4) 3.998](https://www.letstalkacademy.com/wp-content/uploads/2025/09/31.jpg)
CSIR NET Life Science Previous Year Questions and Solution on Biochemistry
Fold Difference in Initial Velocity Between Substrate Concentrations Km and 1000 Km in Michaelis-Menten Enzyme Kinetics
(FEB 2022-11) 31. What is the fold difference between v at [S] =Km and v at [S] = 1000 Km where v is the initial velocity of an enzyme catalyzed […]
