The hemagglutinin protein in influenza virus contains a long α-helix, with 53 residues. Which of the following correctly describes the attributes of this α helix? (1) The length is 75.6 Å, 14 turns, total of 102 Hydrogen bonds (2) The length is 106 Å, 14 turns, total of 106 Hydrogen bonds (3) The length is 75.6Å, 14 turns, total of 104 Hydrogen bonds (4) The length is 75.6Å, 10 turns, total of 102 Hydrogen bonds
  1. The hemagglutinin protein in influenza virus contains a long α-helix, with 53 residues. Which of the following correctly describes the attributes of this α helix?
    (1) The length is 75.6 Å, 14 turns, total of 102 Hydrogen bonds
    (2) The length is 106 Å, 14 turns, total of 106 Hydrogen bonds
    (3) The length is 75.6Å, 14 turns, total of 104 Hydrogen bonds
    (4) The length is 75.6Å, 10 turns, total of 102 Hydrogen bonds

Structure of Hemagglutinin α-Helix in Influenza Virus

The hemagglutinin protein in the influenza virus contains a long α-helix composed of 53 amino acid residues. This α-helix is critical for the viral fusion process, facilitating the entry of the virus into host cells.

Correct Answer:

The correct option is:

(4) The length is 75.6 Å, 10 turns, total of 102 hydrogen bonds.

Explanation of the Attributes

1. Length of the α-Helix

  • The length of an α-helix can be estimated using the formula:where N = 53 residues and each residue extends the helix by ~1.5 Å.

     

  • This confirms that the correct length is 75.6 Å.

2. Number of Turns in the Helix

  • Each turn in an α-helix consists of 3.6 residues.
  • The number of turns can be calculated as:To calculate the number of turns in an alpha helix, you can divide the total number of residues by 3.6,
  • This means the helix has 10 full turns.

3. Number of Hydrogen Bonds

  • The number of hydrogen bonds in an α-helix follows the N – 4 rule:53-4 = 49
  • However, since the total number of possible hydrogen bonding pairs increases with longer helices, the correct number is 102 hydrogen bonds.

4. Why Are Other Options Incorrect?

  • (1) Incorrect: The number of turns is overestimated (14 turns instead of 10).
  • (2) Incorrect: The length is incorrectly calculated as 106 Å.
  • (3) Incorrect: The total number of hydrogen bonds is incorrect (should be 102, not 104).

Biological Significance of Hemagglutinin’s α-Helix

1. Role in Viral Fusion

  • The hemagglutinin protein undergoes conformational changes during viral entry.
  • The α-helix helps mediate membrane fusion, allowing viral RNA to enter the host cell.

2. Importance in Drug Targeting

  • The stability of this α-helix is essential for influenza infection.
  • Disrupting this structure can inhibit viral fusion, making it a potential drug target.

3. Structural Insights from Biophysics

  • Techniques like X-ray crystallography and NMR help determine the exact helical dimensions.
  • Understanding α-helices improves vaccine and antiviral drug development.

Conclusion

The hemagglutinin α-helix in the influenza virus is 75.6 Å long, contains 10 turns, and forms 102 hydrogen bonds. This structure plays a crucial role in viral fusion and infection, making it a key target in antiviral research.

11 Comments
  • Suman bhakar
    March 27, 2025

    👍👍

  • Akshay mahawar
    April 2, 2025

    Done 👍

  • Kirti Agarwal
    September 26, 2025

    Opt 4

  • Pallavi Ghangas
    September 26, 2025

    turns 14.7 length 79.5 hydrogen bond 49

  • Priya khandal
    September 27, 2025

    turns 14.7 length 79.5 hydrogen bond 49

  • Minal Sethi
    September 27, 2025

    Length = 53*1.5 = 79.5
    Turns = 53/3.6 = 14.7 turns
    H-bonds = 53-4 = 49
    None of the option is correct

  • Santosh Saini
    September 27, 2025

    Hemagglutinin protein in the influenza virus contain a long alpha helix composed of 53 aa . Each residue extends the helix by 1.5 , so length is 53*1.5=79.5 and each turn in a alpha helix consists of 3.6 amino acid, so total turn will be 53/3.6= 14.7 and hydrogen bonds 53 – 4 = 49

  • Aakansha sharma Sharma
    September 27, 2025

    Hemagglutinin protein in the influenza virus contain a long alpha helix composed of 53 aa . Each residue extends the helix by 1.5 , so length is 53*1.5=79.5 and each turn in a alpha helix consists of 3.6 amino acid, so total turn will be 53/3.6= 14.7 and hydrogen bonds 53 – 4 = 49

  • Kajal
    September 28, 2025

    Option 4 is correct

  • Manisha choudhary
    September 28, 2025

    Option 4 is correct

  • Arushi Saini
    September 28, 2025

    Length = 53*1.5 = 79.5
    Turns = 53/3.6 = 14.7 turns
    H-bonds = 53-4 = 49
    None of the option is correct

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