Q.16
Consider the following equilibrium reaction:
CO (g) + Cl2 (g) ⇌ COCl2 (g)
0.60 atm of CO and 1.10 atm of Cl2 were mixed in a constant volume reaction vessel
at a particular temperature. After the equilibrium was established, 0.10 atm of COCl2
was observed. The equilibrium constant for the reaction is:
Equilibrium Constant (Kp) Calculation for CO + Cl2 ⇌ COCl2
Understanding the equilibrium constant calculation for CO Cl2 COCl2 reaction is very important for chemistry exams.
This problem can be solved easily using the ICE table method and partial pressures of gases.
✅ Given Reaction
CO(g) + Cl2(g) ⇌ COCl2(g)
Initial Pressures
- CO = 0.60 atm
- Cl2 = 1.10 atm
- COCl2 = 0 atm
At equilibrium: COCl2 = 0.10 atm
Find: Kp
Step 1: Construct ICE Table
| Species | Initial (atm) | Change (atm) | Equilibrium (atm) |
|---|---|---|---|
| CO | 0.60 | −x | 0.60 − x |
| Cl2 | 1.10 | −x | 1.10 − x |
| COCl2 | 0 | +x | x |
Given equilibrium COCl2 = 0.10 atm
Therefore, x = 0.10
- CO = 0.60 − 0.10 = 0.50 atm
- Cl2 = 1.10 − 0.10 = 1.00 atm
- COCl2 = 0.10 atm
Step 2: Write Expression for Kp
Kp = PCOCl2 / (PCO × PCl2)
Substitute Values
Kp = 0.10 / (0.50 × 1.00)
Kp = 0.10 / 0.50 = 0.20
✅ Final Answer
Kp = 0.2 → Option (C)
Explanation of All Options
Option (A) 0.02 ❌
Too small. Product formation is not extremely low, so this value is incorrect.
Option (B) 0.15 ❌
Close but results from rounding or calculation error.
Option (C) 0.2 ✅
Matches exact ICE table calculation. Correct equilibrium constant.
Option (D) 6.6 ❌
Very large value means products dominate heavily, which is not true here.
Important Concepts for Exams
- If K < 1 → Reactants favored
- If K > 1 → Products favored
- Always prepare ICE table before solving
- Use partial pressures for Kp calculations
Quick Memory Trick
If product pressure formed is small → K < 1
If product pressure formed is large → K > 1
Conclusion
Using the ICE table method, the equilibrium constant for the reaction
CO + Cl2 ⇌ COCl2 is 0.2.
This shows the reaction slightly favors reactants at equilibrium.


