55. A heterozygous tall plant (Tt) was crossed with a homozygous dwarf plant (tt). The resultant seeds were collected. If five seeds are chosen at random, then the probability (in %) that exactly two of these seeds will yield dwarf plants is __________.

55. A heterozygous tall plant (Tt) was crossed with a homozygous dwarf plant (tt).
The resultant seeds were collected. If five seeds are chosen at random, then the
probability (in %) that exactly two of these seeds will yield dwarf plants is
__________.

Probability Exactly 2 Dwarf Plants from Tt × tt Cross

Answer: 31% | NEET/JEE Genetics | Binomial Probability Calculation

Monohybrid Test Cross Analysis

Heterozygous tall plant (Tt) produces gametes T and t equally (50% each). Homozygous dwarf (tt) produces only t gametes. This test cross yields 50% Tt (tall) and 50% tt (dwarf) offspring with 1:1 phenotypic ratio.

Punnett Square:
Tt × tt → 50% dwarf probability per seed (p = 0.5)

Binomial Probability Formula

For exactly 2 dwarf plants in 5 seeds, use binomial probability:

P(k=2) = C(5,2) × (0.5)2 × (0.5)3 = 10 × 0.03125 = 0.3125 (31%)

Step-by-Step Calculation

  • n = 5 seeds, k = 2 dwarfs, p = 0.5 (dwarf probability)
  • Combinations: C(5,2) = 5!/(2!×3!) = 10
  • Probability: 10 × (0.5)5 = 10 × 0.03125 = 0.3125
  • Convert to percentage: 31.25% ≈ 31%
Correct Answer: 31%

Options Analysis Table

Option Calculation Why Correct/Incorrect
20% C(5,2)×(0.4)²×(0.6)³ ≈ 0.2 ❌ Wrong p=0.4; test cross is 1:1 (p=0.5), not 3:1
25% (0.5)² = 0.25 ❌ Single seed probability, ignores binomial distribution
31% C(5,2)×(0.5)⁵ = 0.3125 Exact binomial calculation
50% Overall dwarf proportion ❌ For single seed, not “exactly two” in five seeds

Key SEO Phrases

  • Primary: probability exactly two dwarf plants five seeds Tt tt cross
  • Secondary: genetics binomial probability NEET, test cross probability calculation
  • Long-tail: heterozygous tall plant crossed homozygous dwarf five seeds exactly two dwarf

 

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