Q. 15 The total number of stereoisomers possible for the following structure is ____

Q. 15 The total number of stereoisomers possible for the following structure is ___


Understanding the Given Structure

The given compound is 1,2,3-tribromocyclopropane, which consists of:

  • A cyclopropane ring (three-membered ring)
  • One bromine atom attached to each carbon
  • Each carbon is sp³ hybridized
  • Each carbon becomes a stereogenic (chiral) center

Hence, the total number of chiral centers = 3.


Step 1: Maximum Possible Stereoisomers

The general formula for calculating the maximum number of stereoisomers is:

2n

Where n is the number of chiral centers.

For this molecule:

23 = 8

So, the maximum possible stereoisomers are 8.


Step 2: Check for Symmetry and Meso Forms

Even though there are three chiral centers, the molecule exhibits internal symmetry due to:

  • Identical bromine substituents on all three carbon atoms
  • Symmetrical cyclopropane ring structure

Due to this symmetry:

  • Some stereoisomers become identical
  • One configuration forms a meso compound, which is optically inactive despite having chiral centers

Step 3: Elimination of Identical Forms

Out of the 8 theoretical stereoisomers:

  • 2 stereoisomers are identical due to symmetry
  • 1 meso form exists
  • The remaining stereoisomers exist as optically active enantiomeric pairs

Final Count of Stereoisomers

Type Count
Enantiomeric pairs 2 pairs (4 isomers)
Meso form 1
Total stereoisomers 5

Correct Answer

5


Explanation of Possible Options

Option A: 8 ❌

  • This represents the maximum theoretical number
  • Does not consider molecular symmetry
  • Hence, incorrect

Option B: 6 ❌

  • Overlooks the presence of a meso compound
  • Incorrect count

Option C: 4 ❌

  • Counts only enantiomeric pairs
  • Ignores the meso form
  • Incorrect

Option D: 5 ✅ (Correct Answer)

  • Accounts for molecular symmetry
  • Includes one meso form
  • Includes two enantiomeric pairs
  • Correct choice

Key Takeaways for Exams

  • Always check for molecular symmetry
  • Presence of identical substituents can reduce the number of stereoisomers
  • Meso compounds reduce the total stereoisomer count
  • Cyclopropane derivatives often show hidden symmetry

Final Answer

5

 

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