Q.7 The sum of n terms of the series 4 + 44 + 444 + … is Options: (A) (4/81) [10n+1 − 9n − 1] (B) (4/81) [10n − 9n − 1] (C) (4/81) [10n+1 − 9n − 10] (D) (4/81) [10n − 9n − 10]

Q.7

The sum of n terms of the series 4 + 44 + 444 + … is

Options:

(A) (4/81) [10n+1 − 9n − 1]

(B) (4/81) [10n − 9n − 1]

(C) (4/81) [10n+1 − 9n − 10]

(D) (4/81) [10n − 9n − 10]

Sum of n Terms of the Series 4 + 44 + 444 + …

The series 4 + 44 + 444 + … is a commonly asked question in competitive exams.
In this solution, we derive the general formula for the sum of n terms and
identify the correct option.

Step-by-Step Solution

Step 1: General Term

The nth term of the series is:

an = 4 × (10n − 1) / 9

Step 2: Sum of n Terms

Sn = (4/9) Σ (10k − 1), where k = 1 to n

Step 3: Evaluate the Summation

Σ10k = 10(10n − 1)/9

Σ1 = n

Step 4: Simplification

Sn = (4/9) [10(10n − 1)/9 − n]

Sn = (4/81) [10n+1 − 9n − 10]

Correct Answer

Option (C)

Sn = (4/81) [10n+1 − 9n − 10]

Explanation of Options

Option (A): Incorrect constant term.

Option (B): Incorrect power of 10.

Option (C): Matches the derived formula exactly.

Option (D): Incorrect exponent.

Conclusion

The correct formula for the sum of n terms of the series
4 + 44 + 444 + … is:

Sn = (4/81) [10n+1 − 9n − 10]

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