β-Galactosidase bound to DEAE-cellulose is used to hydrolyze lactose to glucose and galactose in a plug flow bioreactor with a packed bed of volume 100 liters and a voidage (ε) of 0.55. The K'm and V'max for the immobilized enzyme are 0.72 g l−1 and 18 g l−1 h−1, respectively. The lactose concentration in the feed stream is 20 g l−1, and a fractional conversion of 0.90 is desired. Diffusional limitations may be ignored. Q.54 The residence time required for the steady state reactor operation will be (A) 0.1 h (B) 0.4 h (C) 1.0 h (D) 1.1 h

β-Galactosidase bound to DEAE-cellulose is used to hydrolyze lactose
to glucose and galactose in a plug flow bioreactor with a packed bed
of volume 100 liters and a voidage (ε) of 0.55. The K’m and
V’max for the immobilized enzyme are
0.72 g l−1 and
18 g l−1 h−1, respectively.
The lactose concentration in the feed stream is
20 g l−1, and a fractional conversion of 0.90 is desired.
Diffusional limitations may be ignored.

Q.54 The residence time required for the steady state
reactor operation will be

(A) 0.1 h

(B) 0.4 h

(C) 1.0 h

(D) 1.1 h

Introduction

Plug flow bioreactors (PFRs) employing immobilized enzymes are extensively used in biochemical engineering
for continuous substrate conversion. A common numerical problem involves estimating the
residence time required to achieve a desired conversion when the enzyme follows
Michaelis–Menten kinetics.

Problem Summary

  • Packed bed volume, V = 100 L
  • Voidage, ε = 0.55
  • Michaelis constant, Km = 0.72 g L-1
  • Maximum rate, Vmax = 18 g L-1 h-1
  • Feed lactose concentration, S0 = 20 g L-1
  • Desired conversion, X = 0.90
  • Diffusional limitations are negligible

Step-by-Step Solution

Step 1: Exit Substrate Concentration

S = S0(1 − X) = 20 × (1 − 0.9) = 2 g L-1

Step 2: Plug Flow Reactor Design Equation

For a plug flow reactor with Michaelis–Menten kinetics:

τ = 1 / Vmax [ (S0 − S) + Km ln(S0/S) ]

Step 3: Substitution of Values

τ = 1 / 18 [ (20 − 2) + 0.72 ln(20/2) ]

τ = 1 / 18 [ 18 + 0.72 ln(10) ]

ln(10) ≈ 2.303

τ = 1 / 18 (18 + 1.658)

τ ≈ 1.09 h ≈ 1.1 h

Final Answer

Correct Option: (D) 1.1 h

Explanation of All Options

(A) 0.1 h ❌
This value is too small and would not allow 90% conversion under Michaelis–Menten kinetics.

(B) 0.4 h ❌
Underestimates the required residence time and ignores enzyme saturation effects.

(C) 1.0 h ❌
Close to the correct value but slightly lower due to rounding or incomplete integration.

(D) 1.1 h ✅
Matches the full plug flow reactor design equation and is kinetically correct.

Conclusion

By applying the plug flow reactor design equation with Michaelis–Menten kinetics,
the required residence time for 90% lactose conversion is approximately
1.1 hours. Therefore, option (D) is the correct answer.
This problem is highly relevant for exams such as GATE and CSIR-NET.

 

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