Tag: CSIR NET Life Science Previous Year Questions on METHODS IN BIOLOGY

43. In anion exchange chromatography, A. The column contains negatively charged beads where positively charged proteins bind B. The column contains positively charged beads where negatively charged proteins bind C. […]

42. The use of insulin hormone to purify its receptor is an example of (A) Ion exchange chromatography (B) Affinity chromatography (C) Gel filtration chromatography (D) Ligand mediated chromatography Answer: […]

41. In gel filtration chromatography, separation of proteins are based on their (A) Size and net charge (B) Size and shape (C) Size and specific affinity (D) Shape and net […]

40. In which of the following separation method where proteins are separated on the basis of their net charge (A) Affinity chromatography (B) Ion exchange chromatography (C) Dialysis (D) Gel […]

39. Which of the following statements is incorrect? A. In affinity chromatography, lectins are used to purify a glycoprotein B. The separation in gel filtration chromatography is based on size, […]

38. In a mixture of the five proteins listed below, which should elute second in size-exclusion (gel-filtration) chromatography? A. Cytochrome c (Mw = 13,000) B. Immunoglobulin G (Mw = 145,000) […]

37. Which of the following methods could be used to check the molecular weight of your purified protein? A. SDS-PAGE only B. Mass spectrometry only C. Analytical size exclusion chromatography […]

36. To elute target proteins from an affinity chromatography matrix, which of the following conditions would be the most appropriate? A. Low salt concentrations B. High salt concentrations C. Adding […]

35. What properties of a protein does hydrophobic interaction chromatography exploit for purification? A. Charged amino acids B. Hydrophobic amino acids on the protein surface C. Molecular weight D. Enzyme […]

34. For an application where you require a sample of your target protein at high purity, what would be a good purification strategy? Assume that your starting point is E. […]