Q.13 The CORRECT order of stability of the given metal oxides is
(A) LiO2 > NaO2 > KO2 > RbO2
(B) LiO2 < NaO2 < KO2 < RbO2
(C) LiO2 < NaO2 > KO2 > RbO2
(D) LiO2 > NaO2 < KO2 < RbO2
Stability Trend
Stability of alkali metal superoxides (MO₂) increases down Group 1 due to larger cation size. Small Li⁺ poorly stabilizes the large O₂⁻ ion, causing low lattice energy and instability for LiO₂. Larger cations like Rb⁺ provide better charge balance and higher stability.
Option Analysis
- (A) LiO₂ > NaO₂ > KO₂ > RbO₂: Incorrect, as stability decreases down the group, opposite to the observed trend.
- (B) LiO₂ < NaO₂ < KO₂ < RbO₂: Correct, matches increasing stability with cation size (Li⁺ < Na⁺ < K⁺ < Rb⁺).
- (C) LiO₂ < NaO₂ > KO₂ > RbO₂: Incorrect, implies peak stability at NaO₂, but trend continues upward.
- (D) LiO₂ > NaO₂ < KO₂ < RbO₂: Incorrect, wrongly shows LiO₂ most stable despite its known instability.
Introduction to Superoxide Stability
The stability order of LiO₂, NaO₂, KO₂, RbO₂ metal oxides follows a clear periodic trend crucial for CSIR NET Life Sciences and chemistry exams. Alkali metal superoxides (MO₂) gain stability down Group 1 as cation size increases from Li⁺ to Rb⁺, enabling better stabilization of the superoxide ion (O₂⁻). This guide breaks down the correct order, explains each option, and provides exam insights.
Why Stability Increases Down the Group
Superoxides contain the paramagnetic O₂⁻ ion, which is large and requires a sizable cation for ionic lattice stability. LiO₂ remains unstable due to disproportionation (2LiO₂ → Li₂O₂ + O₂), observable only at cryogenic temperatures. NaO₂ shows moderate stability, while KO₂ and RbO₂ are stable solids used in applications like oxygen generation.
Key Factors
- Cation size effect: Larger Rb⁺ (1.47 Å) vs. small Li⁺ (0.76 Å) reduces polarizing power, stabilizing O₂⁻.
- Lattice energy: Decreases appropriately down the group, favoring MO₂ formation.
- Electropositivity: Increases from Li to Rb, weakening M-O bonds but enhancing overall compound stability.
Detailed Option Breakdown for Exams
CSIR NET questions test this trend precisely. Here’s why only one option fits:
| Option | Order | Why Correct/Incorrect |
|---|---|---|
| (A) | LiO₂ > NaO₂ > KO₂ > RbO₂ | Wrong; reverses actual trend. |
| (B) | LiO₂ < NaO₂ < KO₂ < RbO₂ | Correct; aligns with cation size increase. |
| (C) | LiO₂ < NaO₂ > KO₂ > RbO₂ | Wrong; no peak at NaO₂. |
| (D) | LiO₂ > NaO₂ < KO₂ < RbO₂ | Wrong; LiO₂ cannot be most stable. |
Exam Tips for Alkali Metal Oxides
- Remember: Oxides (M₂O) stable for Li; peroxides (MO₂) for Na; superoxides (MO₂) for K, Rb, Cs.
- Mnemonic: “Superoxides Stabilize Sizewise” (Li small → unstable; Cs largest → most stable).


