Q.13 The CORRECT order of stability of the given metal oxides is (A) LiO2 > NaO2 > KO2 > RbO2 (B) LiO2 < NaO2 < KO2 < RbO2 (C) LiO2 < NaO2 > KO2 > RbO2 (D) LiO2 > NaO2 < KO2 < RbO2

Q.13 The CORRECT order of stability of the given metal oxides is
(A)
LiO2 > NaO2 > KO2 > RbO2
(B)
LiO2 < NaO2 < KO2 < RbO2
(C)
LiO2 < NaO2 > KO2 > RbO2
(D)
LiO2 > NaO2 < KO2 < RbO2

The correct answer is (B) LiO₂ < NaO₂ < KO₂ < RbO₂.

Stability Trend

Stability of alkali metal superoxides (MO₂) increases down Group 1 due to larger cation size. Small Li⁺ poorly stabilizes the large O₂⁻ ion, causing low lattice energy and instability for LiO₂. Larger cations like Rb⁺ provide better charge balance and higher stability.

Option Analysis

  • (A) LiO₂ > NaO₂ > KO₂ > RbO₂: Incorrect, as stability decreases down the group, opposite to the observed trend.
  • (B) LiO₂ < NaO₂ < KO₂ < RbO₂: Correct, matches increasing stability with cation size (Li⁺ < Na⁺ < K⁺ < Rb⁺).
  • (C) LiO₂ < NaO₂ > KO₂ > RbO₂: Incorrect, implies peak stability at NaO₂, but trend continues upward.
  • (D) LiO₂ > NaO₂ < KO₂ < RbO₂: Incorrect, wrongly shows LiO₂ most stable despite its known instability.

Introduction to Superoxide Stability

The stability order of LiO₂, NaO₂, KO₂, RbO₂ metal oxides follows a clear periodic trend crucial for CSIR NET Life Sciences and chemistry exams. Alkali metal superoxides (MO₂) gain stability down Group 1 as cation size increases from Li⁺ to Rb⁺, enabling better stabilization of the superoxide ion (O₂⁻). This guide breaks down the correct order, explains each option, and provides exam insights.

Why Stability Increases Down the Group

Superoxides contain the paramagnetic O₂⁻ ion, which is large and requires a sizable cation for ionic lattice stability. LiO₂ remains unstable due to disproportionation (2LiO₂ → Li₂O₂ + O₂), observable only at cryogenic temperatures. NaO₂ shows moderate stability, while KO₂ and RbO₂ are stable solids used in applications like oxygen generation.

Key Factors

  • Cation size effect: Larger Rb⁺ (1.47 Å) vs. small Li⁺ (0.76 Å) reduces polarizing power, stabilizing O₂⁻.
  • Lattice energy: Decreases appropriately down the group, favoring MO₂ formation.
  • Electropositivity: Increases from Li to Rb, weakening M-O bonds but enhancing overall compound stability.

Detailed Option Breakdown for Exams

CSIR NET questions test this trend precisely. Here’s why only one option fits:

Option Order Why Correct/Incorrect
(A) LiO₂ > NaO₂ > KO₂ > RbO₂ Wrong; reverses actual trend.
(B) LiO₂ < NaO₂ < KO₂ < RbO₂ Correct; aligns with cation size increase.
(C) LiO₂ < NaO₂ > KO₂ > RbO₂ Wrong; no peak at NaO₂.
(D) LiO₂ > NaO₂ < KO₂ < RbO₂ Wrong; LiO₂ cannot be most stable.

Exam Tips for Alkali Metal Oxides

  • Remember: Oxides (M₂O) stable for Li; peroxides (MO₂) for Na; superoxides (MO₂) for K, Rb, Cs.
  • Mnemonic: “Superoxides Stabilize Sizewise” (Li small → unstable; Cs largest → most stable).

 

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