29. How many different protein sequences of 100 residues can be generated using 20 standard amino acids? (A) 10020    (B) 100 × 20    (C) 20100    (D) 100! × 20!

29. How many different protein sequences of 100 residues can be generated using 20 standard amino acids?

(A) 10020
(B) 100 × 20
(C) 20100
(D) 100! × 20!

A protein sequence of 100 residues using 20 standard amino acids yields an enormous number of possibilities due to independent choices at each position. The correct answer is option (C) 20100, representing total combinations in molecular biology. This fundamental concept appears in exams like GATE Biotechnology.

Core Concept

Proteins consist of chains where each of the 100 positions can independently select any of 20 amino acids (glycine, alanine, etc.). This follows the multiplication principle: for position 1, 20 choices; position 2, another 20; up to position 100. Total sequences equal 20×20×⋯×20 (100 times), or 20100.

Option Analysis

  • (A) 10020: Incorrect, as this assumes 100 amino acid types with 20 positions, reversing the actual scenario of 20 types over 100 positions.
  • (B) 100 × 20: Wrong, representing just two positions’ choices (100 for one, 20 for another), not a full chain.
  • (C) 20100: Correct, capturing all combinations since each residue independently chooses from 20 amino acids.
  • (D) 100! × 20!: Invalid, as factorials count permutations of distinct items without replacement; amino acids allow repetition.

Biological Relevance

There are 20 standard amino acids encoded by the genetic code, enabling vast sequence diversity despite nature using only a fraction. 20100 exceeds 10130, dwarfing atoms in the universe (~1080), explaining why random proteins rarely fold functionally. This underscores protein engineering challenges in biotechnology.

Exam Application

Common in GATE BT/XL for testing combinatorics in molecular biology. Practice by calculating smaller cases: for 2 residues, 202=400 sequences verifies the exponent rule. For n residues, always 20n.

 

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