31. Which of the following gaphs represents uncompetitive inhibition?
Introduction
Questions based on enzyme inhibition are very common in biochemistry and competitive exams
like NEET, CSIR-NET, GATE, and university exams. One such important question is identifying
the graph representing uncompetitive inhibition. In this article, we analyze
each graph using Lineweaver–Burk plots and explain why the correct option represents
uncompetitive inhibition.
Question
Which one of the following graphs represents uncompetitive inhibition?
(All graphs are Lineweaver–Burk plots of
1/V0 vs 1/[S])
Basic Concept: Uncompetitive Inhibition
Before analyzing the graphs, recall the key properties of uncompetitive inhibition:
Key Characteristics
- Inhibitor binds only to the enzyme–substrate (ES) complex
- Both Vmax decreases and Km decreases
- The ratio Km/Vmax remains constant
Effect on Lineweaver–Burk Plot
- Parallel straight lines
- Same slope
- Different intercepts
Parallel lines = Uncompetitive inhibition
Understanding the Axes
- X-axis: 1/[S]
- Y-axis: 1/V0
Slope of Lineweaver–Burk Plot
Slope = Km / Vmax
Option-Wise Explanation
Option (A)
- Lines intersect on the Y-axis
- Same Y-intercept → Vmax unchanged
- Different slopes → Km changed
This pattern represents competitive inhibition, not uncompetitive inhibition.
Option (B)
- Lines intersect left of the Y-axis
- Both slope and intercept change
- Neither parallel nor same intercept
This graph is characteristic of mixed inhibition.
Option (C) Correct Answer
- Lines are perfectly parallel
- Slope remains the same
- Y-intercept increases with inhibitor
- X-intercept shifts left
This matches uncompetitive inhibition where:
- Vmax ↓
- Km ↓
- Km/Vmax remains constant
✔ Correct representation of uncompetitive inhibition
Option (D)
- Lines intersect on the X-axis
- Same X-intercept → Km unchanged
- Different Y-intercepts → Vmax decreased
This represents non-competitive inhibition, not uncompetitive inhibition.
Final Answer
Option (C)
Quick Comparison Table
| Inhibition Type | Vmax | Km | Line Pattern |
|---|---|---|---|
| Competitive | Same | Increases | Intersect Y-axis |
| Non-competitive | Decreases | Same | Intersect X-axis |
| Mixed | Decreases | Changes | Intersect left of Y |
| Uncompetitive | Decreases | Decreases | Parallel lines |
Important Exam Tip
Always remember:
Parallel Lineweaver–Burk lines = Uncompetitive inhibition
Conclusion
The graph representing uncompetitive inhibition is Option (C)
because it shows parallel Lineweaver–Burk plots, indicating that both Vmax and
Km decrease proportionally. Mastering these graphical patterns is essential for
scoring high in enzyme kinetics questions.