A microorganism grows in a continuous chemostat culture of 60 m3 working volume with sucrose as the growth limiting nutrient at dilution rate, D = 0.55 h−1. The steady state biomass concentration is 4.5 kg dry biomass m−3 and the residual sucrose concentration is 2.0 kg m−3. The sucrose concentration in the incoming feed medium is 10.0 kg m−3. Q.50 What would be the yield YX/S (kg biomass/kg substrate)? (A) 0.562 (B) 0.462 (C) 0.362 (D) 0.162

A microorganism grows in a continuous chemostat culture of 60 m3 working volume with sucrose as the growth limiting nutrient at dilution rate,

D = 0.55 h−1. The steady state biomass concentration is 4.5 kg dry biomass m−3 and the residual sucrose concentration is 2.0 kg m−3.
The sucrose concentration in the incoming feed medium is 10.0 kg m−3.

Q.50 What would be the yield YX/S (kg biomass/kg substrate)?

(A) 0.562

(B) 0.462

(C) 0.362

(D) 0.162

Chemostat Basics

A chemostat maintains steady-state growth by balancing dilution rate D with specific growth rate μ, where biomass X and residual substrate S remain constant. Here, working volume is 60 m³ (unused for YX/S), D=0.55 h⁻¹, X=4.5 kg dry biomass m⁻³, S=2.0 kg m⁻³, and feed substrate S₀=10.0 kg m⁻³. Substrate consumption drives biomass formation under growth-limited conditions.

Yield Calculation

YX/S = X / (S₀ – S), derived from mass balance: biomass produced equals yield times substrate consumed.

Substitute values:

YX/S = 4.5 / (10.0 - 2.0) = 4.5 / 8.0 = 0.562 kg biomass/kg substrate

This ignores maintenance or product formation, standard for such problems.

Options Explained

(A) 0.562: Correct, as 4.5 / 8 = 0.562 directly from data.
(B) 0.462: Incorrect; possibly 4.5 / (10 – 1.25) or misread S as 1.0, but data shows 2.0 kg m⁻³.
(C) 0.362: Incorrect; might assume extra loss like 4.5 / 12.4, unrelated to given values.
(D) 0.162: Incorrect; could be 1.3 / 8 or volume error, but YX/S uses concentrations only.

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