Q.48 The amount of agarose required to prepare 250 π‘šπΏ of 0.8% agarose gel is __________ π‘”π‘Ÿπ‘Žπ‘šπ‘  (rounded off to the nearest integer).

Q.48 The amount of agarose required to prepare 250 π‘šπΏ of 0.8% agarose gel
is __________ π‘”π‘Ÿπ‘Žπ‘šπ‘  (rounded off to the nearest integer).

2 grams of agarose are required to prepare 250 mL of 0.8% agarose gel. This calculation uses the standard weight/volume (w/v) formula for gel concentration, rounded to the nearest integer.​

Calculation Method

Agarose gel percentage is defined as grams of agarose per 100 mL of buffer (w/v). For 0.8%, dissolve 0.8 g agarose in 100 mL buffer.​
Scale proportionally: Mass (g) = (0.8 / 100) Γ— 250 mL = 2.0 g.​
Round 2.0 to the nearest integer: 2 g.

Step-by-Step Preparation

  • Weigh 2 g agarose powder.​

  • Add to ~200 mL electrophoresis buffer (TAE or TBE) in a flask.​

  • Microwave to dissolve (swirl to avoid boiling), cool to ~60Β°C, add dye if needed, pour into gel tray.​
    A 0.8% gel suits DNA fragments of 1–10 kb.​

Agarose Gel Concentrations

Gel % DNA Size Range (bp) Common Use
0.5% 2,000–50,000 Large fragments
0.8% 1,000–10,000 PCR products, plasmids
1.0% 400–8,000 Routine DNA
2.0% 100–2,000 Small fragments

CSIR NET Exam Context

This fill-in-the-blank question tests precise calculation skills for molecular biology techniques. No options provided; direct computation yields 2 g. Verify units (mL, %, g) to avoid errors like confusing v/w.​


Agarose gel electrophoresis remains essential in molecular biology for DNA separation, andΒ agarose gel calculationΒ for precise concentrations likeΒ 0.8% agarose gelΒ is a core skill for CSIR NET aspirants. This guide solves “amount of agarose required to prepare 250 mL of 0.8% agarose gel” with detailed math, protocol, and exam tips.​

Agarose Percentage Explained

Agarose gel concentrationΒ uses w/v: 0.8% = 0.8 g per 100 mL buffer. Higher % creates smaller pores for better small-fragment resolution; 0.8% excels for 1–10 kb DNA. Common range: 0.5–2%.​

Exact Calculation for 250 mL 0.8% Gel

Formula: Mass (g) = (% / 100) Γ— Volume (mL)
= (0.8 / 100) Γ— 250 =Β 2.0 gΒ (rounds toΒ 2 grams).​
Pro Tip: Use analytical balance; errors in scaling lead to poor resolution.​

Full Preparation Protocol

  1. WeighΒ 2 g agarose.​

  2. Add to 250 mL 1Γ— TAE/TBE in 500 mL flask.​

  3. Microwave (1–2 min, swirl every 30 s).​

  4. Cool to 60Β°C, add EtBr (0.5 ΞΌg/mL), pour into tray with comb.​

  5. Solidify 20–30 min; run at 5–10 V/cm.​

Concentration Grams per 100 mL Ideal DNA (bp)
0.8% 0.8 g 1,000–10,000
1.0% 1.0 g 400–8,000
1.5% 1.5 g 200–3,000

CSIR NET Tips for Agarose Questions

  • Recognize w/v units; avoid v/w mix-ups.​

  • 0.8% suits plasmids/PCR; memorize ranges.​

  • Practice: For 50 mL 1%, use 0.5 g.​
    Master this for Unit 2 (Techniques) scoring.​

Leave a Reply

Your email address will not be published. Required fields are marked *

Latest Courses