Q.11 Which one among the following mixtures gives a buffer solution in water? (A) CH3COOH + CH3COONa (B) CH3COOH + NaCl (C) NaOH + NaCl (D) NaOH + CH3COONa

Q.11 Which one among the following mixtures gives a buffer solution in water?
(A)
CH3COOH + CH3COONa
(B)
CH3COOH + NaCl
(C)
NaOH + NaCl
(D)
NaOH + CH3COONa

CH3COOH + CH3COONa forms a buffer solution in water. This mixture of a weak acid and its conjugate base resists pH changes effectively. The correct answer is option (A).

Buffer Solution Basics

A buffer solution maintains stable pH when small amounts of acid or base are added. It requires either a weak acid with its conjugate base (acidic buffer) or a weak base with its conjugate acid (basic buffer).

Option Analysis

  • (A) CH3COOH + CH3COONa: Acetic acid (weak acid, CH3COOH ⇌ CH3COO⁻ + H⁺) pairs with sodium acetate (provides CH3COO⁻ conjugate base). Added H⁺ reacts with CH3COO⁻ to form CH3COOH; added OH⁻ reacts with CH3COOH to form CH3COO⁻. This resists pH change, forming an acidic buffer.

  • (B) CH3COOH + NaCl: Weak acid alone with neutral salt (NaCl → Na⁺ + Cl⁻, no buffering species). Added base consumes all CH3COOH without conjugate replenishment; pH shifts drastically.

  • (C) NaOH + NaCl: Strong base (NaOH → Na⁺ + OH⁻) with neutral salt. No weak acid/base pair; fully dissociates, causing large pH swings with added acid/base.

  • (D) NaOH + CH3COONa: Strong base reacts completely with CH3COO⁻ (hydrolyzes to basic solution). Excess OH⁻ dominates; lacks weak acid for buffering.

Introduction (with Keyphrase: “which mixture gives buffer solution in water”)
Searching for “which mixture gives buffer solution in water”? CH3COOH + CH3COONa stands out as the classic acidic buffer. This guide breaks down all options for CSIR NET aspirants, explaining why weak acid-salt pairs like acetic acid and sodium acetate maintain pH stability in aqueous solutions.

What Makes a Buffer Solution?
Buffer solutions resist pH changes via equilibrium between weak acids/bases and conjugates. Acidic buffers (pH < 7) use weak acid + conjugate base salt; pH ≈ pKa (Henderson-Hasselbalch: pH = pKa + log([salt]/[acid])). CH3COOH (pKa 4.76) + CH3COONa exemplifies this.

Why CH3COOH + CH3COONa Forms a Buffer
CH3COOH partially dissociates; CH3COONa supplies CH3COO⁻. Equilibrium shifts per Le Chatelier: H⁺ + CH3COO⁻ → CH3COOH (neutralizes acid); CH3COOH + OH⁻ → CH3COO⁻ + H2O (neutralizes base). pH stays near 4.76.

Why Other Mixtures Fail

Mixture Reason Not a Buffer
CH3COOH + NaCl Neutral salt adds no conjugate; weak acid depletes easily 
NaOH + NaCl Strong base + neutral salt; no weak pair 
NaOH + CH3COONa Strong base hydrolyzes salt fully; excess OH⁻ 

CSIR NET Exam Tips
Focus on identifying weak acid/conjugate pairs. Practice: Buffer capacity peaks at [acid] = [salt]. Avoid strong acid/base mixes.

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