Q.73 If the radius of a spherical coccus is 0.8 μm, the value of surface area volume in μm−1 will be (A) 7.45 (B) 4.05 (C) 3.75 (D) 0.85

Q.73

If the radius of a spherical coccus is 0.8 μm, the value of

surface area
volume

in μm−1 will be

(A) 7.45

(B) 4.05

(C) 3.75

(D) 0.85


Introduction

The surface area to volume (SA/V) ratio is an important biological concept.
Smaller spherical bacteria like coccus have a higher SA/V ratio,
allowing faster diffusion of nutrients and gases.
Let us calculate the ratio for a spherical coccus of radius 0.8 μm.


Given

Radius (r) = 0.8 μm

Find:
Surface Area / Volume (μm-1)


Step 1: Formula for Sphere

Surface Area (SA)

SA = 4πr2

Volume (V)

V = 4/3 πr3


Step 2: Take Ratio

SA / V = (4πr2) / ((4/3)πr3)

Cancel 4π

= r2 / (1/3 r3)

= 3 / r


Shortcut Formula (Exam Trick)

For any sphere:

SA / V = 3 / r


Step 3: Substitute Value

SA / V = 3 / 0.8

= 3.75 μm-1


Final Answer

3.75

Correct Option: (C)


Explanation of All Options

  • (A) 7.45 – Too large, incorrect calculation
  • (B) 4.05 – Formula error
  • (C) 3.75 – Correct using 3/r
  • (D) 0.85 – Inverse taken (V/SA)

Conceptual Understanding

SA/V ∝ 1/r

Smaller cells → Higher surface area to volume ratio → Faster nutrient exchange.

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