Q.5 Among CH4, H2O, NH3 and PH3, the molecule having the smallest percent s character for the covalent bond (X—H) between the central element (X = C, O, N or P) and hydrogen is (A) CH4 (B) H2 (C) NH3 (D) PH3

Q.5 Among CH4, H2O, NH3 and PH3, the molecule having the smallest percent s character for the covalent bond (X—H) between the central element (X = C, O, N or P) and hydrogen is

(A) CH4
(B) H2
(C) NH3
(D) PH3

PH3 has the smallest percent s-character in its X-H bonds among the given options. This stems from its minimal hybridization compared to the sp³ hybridization in CH4, H2O, and NH3.

Option Analysis

CH4: Carbon undergoes sp³ hybridization, mixing one 2s and three 2p orbitals to form four equivalent sp³ orbitals. Each C-H bond uses an sp³ orbital with 25% s-character (1/4 s).

H2O: Oxygen also shows sp³ hybridization despite two lone pairs. The O-H bonds form from sp³ orbitals, maintaining 25% s-character, though bond angles compress to 104.5° due to lone pair repulsion.

NH3: Nitrogen exhibits sp³ hybridization with one lone pair. N-H bonds involve sp³ orbitals with 25% s-character, and the bond angle is 107° from bond pair-lone pair repulsion.

PH3: Phosphorus barely hybridizes due to the inert pair effect—the large 3s-3p energy gap keeps the 3s orbital mostly unhybridized with the lone pair. P-H bonds form primarily from pure 3p orbitals (nearly 0% s-character), yielding a ~93.5° bond angle.

Introduction to Percent S-Character in X-H Bonds

Percent s-character determines bond strength and length in molecules like CH4, H2O, NH3, and PH3. For CSIR NET aspirants studying hybridization, understanding why PH3 deviates from sp³ norms is crucial. This analysis covers each molecule’s central atom (X = C, O, N, P) bonding with hydrogen.

Hybridization Breakdown

  • CH4 (sp³, 25% s): Perfect tetrahedral geometry, 109.5° angles, all bonds equivalent.

  • H2O (sp³, 25% s): Bent shape, two lone pairs compress angles to 104.5°.

  • NH3 (sp³, 25% s): Trigonal pyramidal, one lone pair gives 107° angles.

  • PH3 (minimal hybridization, ~0% s): Bonds use pure p orbitals; inert pair keeps s electrons non-bonding.

Molecule Hybridization % s-Character (X-H) Bond Angle
CH4 sp³ 25% 109.5°
H2O sp³ 25% 104.5°
NH3 sp³ 25% 107°
PH3 ~pure p ~0% 93.5°

Why PH3 Has Smallest S-Character

The inert pair effect in phosphorus stabilizes the 3s² electrons, preventing effective s-p mixing. Unlike nitrogen’s small 2s-2p gap in NH3, PH3 bonds rely on 3p orbitals overlapping with H 1s, minimizing s-contribution.

Answer: (D) PH3

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