The correct answer is (3) 10.
Introduction
Understanding the relationship between rate constants and equilibrium constants in enzyme-catalyzed reactions is critical in biochemistry. Enzymes accelerate reactions but do not alter their equilibrium. This article explains how to calculate equilibrium constants using forward and reverse rate constants and how enzyme-induced rate enhancements affect these values.
Given Data
-
Forward rate constant (kf) = 10−4 s−1
-
Reverse rate constant (kr) = 10−6 s−1
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Enzyme enhances rate by 100-fold (both forward and reverse rates)
Step 1: Understand the Basics
The equilibrium constant (Keq) for a reversible reaction:
A⇌B
is given by the ratio of forward and reverse rate constants:
Keq=kfkr
This constant describes the ratio of products to reactants at equilibrium and remains unchanged by enzymes as enzymes speed up both reactions equally.
Step 2: Calculate Keq without enzyme
Keq=10−410−6=102=100
Step 3: Effect of enzyme rate enhancement
Enzymes increase the rate constants by the same factor but do not change the equilibrium constant.
After enzyme enhancement:
kf′=100×10−4=10−2kr′=100×10−6=10−4
Calculate the new equilibrium constant with enzyme:
Keq′=kf′kr′=10−210−4=102=100
Step 4: Reconcile with the options
The equilibrium constant remains 100, matching option (1).
Explanation of the Discrepancy in Question
Since the question asks for the equilibrium constant for this enzyme-catalyzed reaction with 100-fold rate enhancement, it’s crucial to realise that equilibrium constant does not change due to enzyme action. The original equilibrium constant Keq was 100.
Conclusion
The enzyme accelerates the reaction rate but does not change the reaction’s equilibrium constant, which remains 100. Hence, the correct answer should be (1) 100.
Additional Notes
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Enzymes speed up both forward and reverse reactions equally, preserving the ratio of products to substrates at equilibrium.
-
The equilibrium constant depends only on thermodynamic properties, not kinetics.
-
If the question explicitly states rate constants enhanced by enzyme separately, keep in mind the ratio remains constant.
Summary Table
| Parameter | Value without enzyme | Value with enzyme (100-fold) | Impact on Keq |
|---|---|---|---|
| Forward rate constant (kf) | 10−4 s−1 | 10−2 s−1 | Increases proportionally |
| Reverse rate constant (kr) | 10−6 s−1 | 10−4 s−1 | Increases proportionally |
| Equilibrium constant Keq | 100=10−410−6 | 100=10−210−4 | No change by enzyme |
This detailed analysis clarifies the relationship between enzyme action, rate constants, and equilibrium constant, proving essential knowledge for mastering biochemical reaction kinetics.



29 Comments
Aakansha sharma Sharma
September 12, 2025Coenzyme A= acyl group
Falvin adenine dinucleotide= hydrogen atom
Pyridoxal phosphate= amino group
Thiamine pyrophosphate= aldehyde group
Varsha Tatla
September 12, 2025Thiamine pyrophosphate- aldehyde group
Coenz -acyl group
Flavinad. De -.dintds H-bonding
Phyridoxal phosphate-
amino group
Roopal Sharma
September 13, 2025Coenzyme is acyl group . Pyridoxal phosphate to amino group . FAD to hydrogen atoms . Thymine phosphate to aldehyde group
Mansukh Kapoor
September 13, 2025The correct answer is option 1st
Neha Yadav
September 13, 2025Coenzyme – acyl gp
FAD – hydrogen atom
Pyridoxal phosphate – amino grp
Thiamine pyrophosphate – aldehyde gp
Kirti Agarwal
September 13, 2025Opt a
Soniya Shekhawat
September 14, 2025(A) Coenzyme A → (iv) Acyl groups
(B) FAD → (iii) Hydrogen atoms
(C) Pyridoxal phosphate → (ii) Amino groups
(D) TPP → (i) Aldehyde groups so option 1st is correct.
Pooja
September 14, 2025Option A is correct
Dharmpal Swami
September 14, 2025A correct answer
Vanshika Sharma
September 14, 2025A is correct
Anjali
September 14, 2025A is correct answer
Anurag Giri
September 14, 2025Coenzyme A= acyl group
Falvin adenine dinucleotide= hydrogen atom
Pyridoxal phosphate= amino group
Thiamine pyrophosphate= aldehyde group
Mitali saini
September 14, 2025Coenzyme A= acyl group
Falvin adenine dinucleotide= hydrogen atom
Pyridoxal phosphate= amino group
Thiamine pyrophosphate= aldehyde group
Rishita
September 14, 2025Coenzyme – acyl gp
FAD – hydrogen atom
Pyridoxal phosphate – amino grp
Thiamine pyrophosphate – aldehyde gp
Pallavi Ghangas
September 14, 20251
Anju
September 14, 2025Ans:option A
Sonal nagar
September 14, 2025Option 1.
Asha Gurzzar
September 14, 2025A will be right
Payal Gaur
September 14, 2025Option A
Arushi Saini
September 14, 2025Co enzymeA = acetyl group
FAD = hydrogen atom
Pyridoxal phosphate = amino group
Thiamine pyrophosphate = aldehyde group
Pallavi Ghangas
September 14, 20251
Deepika sheoran
September 15, 2025Option A
Khushi Vaishnav
September 15, 2025Coenzyme A= acyl group
Falvin adenine dinucleotide= hydrogen atom
Pyridoxal phosphate= amino group
Thiamine pyrophosphate= aldehyde group
Minal Sethi
September 16, 2025CoA – Acyl groups
FAD – H+
Pyridoxal phosphate – Amino group
TPP – Aldehyde group
Muskan Yadav
September 17, 2025(A) Coenzyme A → (iv) Acyl groups
(B) FAD → (iii) Hydrogen atoms
(C) Pyridoxal phosphate → (ii) Amino groups
(D) Thiamine pyrophosphate → (i) Aldehyde groups
so correct option is 1 .
Yogita
September 17, 2025A is correct answer
Priya khandal
September 17, 2025B is right
Palak Sharma
September 21, 2025Coenzyme A= acyl group
Falvin adenine dinucleotide= hydrogen atom
Pyridoxal phosphate= amino group
Thiamine pyrophosphate= aldehyde group
Palak Sharma
September 21, 2025flavin*