Q.52 In an assay of the type II dehydroquinase of molecular mass 18 kDa, it is found that the
Vmax of the enzyme is 0.0134 μmol·min−1 when 1.8 μg enzyme is added to the assay mixture.
If the Km for the substrate is 25 μM, the kcat/Km ratio will be ________ × 104 M−1·s−1.
Type II Dehydroquinase Enzyme Kinetics: kcat/Km Calculation
Vmax: 0.0134 μmol·min-1 |
Enzyme mass: 1.8 μg |
Km: 25 μM
Introduction
The type II dehydroquinase kcat/Km ratio is a key measure of catalytic
efficiency in enzyme kinetics. It combines the turnover number (kcat)
and substrate affinity (Km) within the Michaelis–Menten framework.
This calculation is commonly tested in biotechnology, biochemistry, and molecular biology examinations.
Given Data
- Molecular mass of enzyme = 18 kDa = 18,000 g·mol-1
- Enzyme amount = 1.8 μg = 1.8 × 10-6 g
- Vmax = 0.0134 μmol·min-1
- Km = 25 μM = 25 × 10-6 M
Step-by-Step Calculation
Step 1: Convert Enzyme Mass to Moles
Moles of enzyme = (1.8 × 10-6 g) / (18,000 g·mol-1)
= 1 × 10-10 mol
Step 2: Convert Vmax to mol·s-1
Vmax = 0.0134 μmol·min-1
= 0.0134 × 10-6 mol·min-1
= (0.0134 × 10-6) / 60
= 2.233 × 10-10 mol·s-1
Step 3: Calculate kcat
kcat = Vmax / [E]total = (2.233 × 10-10 mol·s-1) / (1 × 10-10 mol) = 2.233 s-1
Step 4: Calculate kcat/Km
kcat/Km = 2.233 s-1 / (2.5 × 10-5 M)
= 8.93 × 104 M-1·s-1
Final Answer
kcat/Km = 8.93 × 104 M-1·s-1
Key Concepts
- kcat (Turnover Number):
Maximum number of substrate molecules converted per enzyme per second. - Km (Michaelis Constant):
Substrate concentration at which reaction rate is half of Vmax. - kcat/Km:
Measure of catalytic efficiency; diffusion-limited enzymes approach
108–109 M-1·s-1.
Conclusion
This type II dehydroquinase enzyme kinetics example highlights the importance
of correct unit conversion when calculating catalytic efficiency.
The final kcat/Km value of
8.93 × 104 M-1·s-1
is well within the expected range for metabolic enzymes and is highly relevant
for biotechnology and molecular biology examinations.


