1. An enzyme catalyzes a reaction by (a) decreasing the energy of the substrate. (b) deveasing the activation energy of the reaction. (c) decreasing product stability. (d) increasing the activation […]
Tag: GATE Biotechnology Previous Year Papers with Solutions
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GATE Biotechnology 2018 Previous Year Papers with Solutions
Number of Proteins in a Rod-Shaped Bacterium Cell
Q.65 A rod shaped bacterium has a length of 2 µm, diameter of 1 µm and density the same as that of water. If proteins constitute 15% of the cell […]
![Q.64 The product of complete digestion of the plasmid shown below with EcoRI and HaeIII was purified and used as a template in a reaction containing Klenow fragment of DNA polymerase, dNTPs and [α-32P]-dATP in a suitable reaction buffer. The product thus obtained was purified and subjected to gel electrophoresis followed by autoradiography. EcoRI 5′–GAATTC–3′ 3′–CTTAAG–5′ HaeIII 5′–GGCC–3′ 3′–CCGG–5′ The number of bands that will appear on the X-ray film is ________](https://www.letstalkacademy.com/wp-content/uploads/2026/01/slide_64-11.png)
GATE Biotechnology 2018 Previous Year Papers with Solutions
EcoRI + HaeIII Digestion and Klenow Labeling
Q.64 The product of complete digestion of the plasmid shown below with EcoRI and HaeIII was purified and used as a template in a reaction containing Klenow fragment of DNA […]
GATE Biotechnology 2018 Previous Year Papers with Solutions
Unveiling Enzyme Inhibition
Q.63 Consider a simple uni-substrate enzyme that follows Michaelis-Menten kinetics. When the enzyme catalyzed reaction was carried out in the presence of 10 nM concentration of an inhibitor, there was […]
GATE Biotechnology 2018 Previous Year Papers with Solutions
Enzyme Half-Life Ratio
Q.62 First order deactivation rate constants for soluble and immobilized amyloglucosidase enzyme are 0.03 min-1 and 0.005 min-1, respectively. The ratio of half-life of the immobilized enzyme to that of […]
GATE Biotechnology 2018 Previous Year Papers with Solutions
Calculate DNA Alignment Score
Q.61 Consider the following alignment of two DNA sequences: AGTAAC AA—-AC Assuming an affine gap scoring scheme of an identity matrix for substitution, a gap initiation penalty of 1 and […]
GATE Biotechnology 2018 Previous Year Papers with Solutions
Calculate Initial Culture Volume
Q.60 At the end of a batch culture, glucose solution is added at a flow rate of 200 ml/h. If the culture volume after 2 h of glucose addition is […]
GATE Biotechnology 2018 Previous Year Papers with Solutions
Ethanol from Glucose
Q.59 Yeast converts glucose to ethanol and carbon dioxide by glycolysis as per the following reaction: C6H12O6 → 2C2H5OH + 2CO2 Assuming complete conversion, the amount of ethanol produced (in […]
GATE Biotechnology 2018 Previous Year Papers with Solutions
Mammalian Cell Population Doubling Time
Q.58 Mammalian cells in active growth phase were seeded at a density of 1×105 cells/ml. After 72 hours, 1×106 cells/ml were obtained. The population doubling time of the cells in […]
GATE Biotechnology 2018 Previous Year Papers with Solutions
Chemostat Effluent Substrate Concentration
Q.57 In a chemostat, the feed flow rate and culture volume are 100 mL/h and 1.0 L, respectively. With glucose as substrate, the values of μmax and Ks are 0.2 […]
