Q.42 A forest has four different tree species (A, B, C and D) and their numbers are:
A = 60; B = 20; C = 10 and D = 10.
The Shannon biodiversity index of the trees in this forest is________________. (rounded
off to 2 decimals)
Shannon Biodiversity Index Calculation: Forest Trees Example
The Shannon biodiversity index measures species diversity by accounting for both richness and evenness in a community. For the given forest with trees A=60, B=20, C=10, D=10, the index calculates to 1.07 when rounded to two decimals.
Formula and Steps
The Shannon index H′=−∑piln(pi), where pi is the proportion of each species. Total trees = 100, so proportions are A: 0.60, B: 0.20, C: 0.10, D: 0.10.
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Compute: -[0.60×ln(0.60) + 0.20×ln(0.20) + 0.10×ln(0.10) + 0.10×ln(0.10)] = -[-0.392 -0.224 -0.230 -0.230] = 1.076.
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Rounded: 1.07, indicating moderate diversity due to dominance by species A.
Step-by-Step Computation
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Proportions: pA=60/100=0.6, pB=0.2, pC=pD=0.1.
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Ln values: ln(0.6)≈-0.510, ln(0.2)≈-1.609, ln(0.1)≈-2.303.
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Products: 0.6×-0.510=-0.306, 0.2×-1.609=-0.322, 0.1×-2.303=-0.230 (twice).
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Sum = -1.076, negate for H’=1.076≈1.07.
Interpretation Guide
Higher values show greater diversity; 0 means one species dominates fully. Here, 1.07 reflects low evenness from A’s 60% share, unlike equal distribution (max H’=1.39 for 4 species).
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Low (<1): Heavy dominance.
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Moderate (1-2): Several species, uneven.
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High (>2): Even, rich communities.
Common Mistakes in Options
No explicit options provided, but typical MCQ traps include:
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Using log10 instead of ln: Yields ~0.47 (wrong base).
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Forgetting negative sign: Positive sum error.
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Simpson index confusion: 1−∑pi2=0.68 (different metric).
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Incorrect total (e.g., unnormalized): Leads to ~1.92.