Q.7 The value of \(\lim_{n\to\infty} \frac{3n^2 + 5n + 4}{4 + 2n^2}\) is
(A) 0
(B) 0.75
(C) 1.5
(D) 3
Introduction
Finding the limit of rational functions like (3n2+5n+4)/(4+2n2) as n tends to infinity is a standard concept in calculus and sequences, and it often appears in competitive exams as a quick MCQ. Understanding how to simplify such expressions using leading coefficients helps solve these questions accurately and efficiently.
Step-by-step solution of the limit
Consider L = limn→∞(3n2+5n+4)/(4+2n2).
Identify the highest power of n:
- In the numerator, the highest power is n2 with coefficient 3.
- In the denominator, the highest power is n2 with coefficient 2.
Divide numerator and denominator by n2:
(3n2+5n+4)/(4+2n2) = (3 + 5/n + 4/n2)/(4/n2 + 2).
Use limits of the smaller terms:
limn→∞5/n = 0 and limn→∞4/n2 = 0.
limn→∞4/n2 = 0 in the denominator as well.
Evaluate the limit:
L = 3 + 0 + 0 / 0 + 2 = 3/2 = 1.5.
So the value of the limit is 1.5.
Explanation of each option
The MCQ options are:
(A) 0 (B) 0.75 (C) 1.5 (D) 3.
Option (A) 0
A limit of 0 would occur if the degree of the numerator were less than the degree of the denominator, making the fraction vanish as n grows large.
Here, both numerator and denominator have the same degree (2), so the limit is a non-zero ratio of leading coefficients, not 0.
Therefore, option (A) 0 is incorrect.
Option (B) 0.75
0.75 = 3/4, which might come from incorrectly taking coefficients 3 and 4 instead of the correct leading coefficients 3 and 2.
The constant 4 in the denominator is not the leading term; the leading term is 2n2, so 3/4 is based on a misunderstanding of which terms dominate for large n.
Hence, option (B) 0.75 is incorrect.
Option (C) 1.5
Using the rule for rational functions with equal degrees, the limit as n→∞ is the ratio of leading coefficients: 3/2 = 1.5.
This matches the computed limit L = 1.5, so option (C) 1.5 is correct.
Option (D) 3
A limit of 3 would arise if the denominator’s leading coefficient were 1 (giving 3/1 = 3) or if the denominator grew slower than the numerator, which is not the case.
Since the denominator has leading coefficient 2 and same degree as the numerator, the correct ratio is 3/2, not 3.
Therefore, option (D) 3 is incorrect.
Key takeaways for similar limits
When numerator and denominator have the same degree, the limit at infinity of a rational function is the ratio of the leading coefficients.
When the numerator’s degree is less, the limit is 0; when it is greater, the limit diverges to ∞ or −∞ depending on signs.
Recognizing and applying this pattern quickly is crucial for solving MCQs on limits in competitive exams.