Q.21 What is the solution of \( \int \frac{x}{x^2 \ln x} \, dx \)? Given \( C \) is an arbitrary constant. (A) \( \frac{x^3}{3} \ln x - \frac{x^3}{9} + C \) (B) \( \frac{x^3}{3} \ln x + \frac{x^3}{9} + C \) (C) \( -\frac{x^3}{9} \ln x + \frac{x^3}{9} + C \) (D) \( \frac{x^3}{9} \ln x - \frac{x^3}{3} + C \)

Q.21

What is the solution of \( \int \frac{x}{x^2 \ln x} \, dx \)? Given \( C \) is an arbitrary constant.

  • (A) \( \frac{x^3}{3} \ln x – \frac{x^3}{9} + C \)
  • (B) \( \frac{x^3}{3} \ln x + \frac{x^3}{9} + C \)
  • (C) \( -\frac{x^3}{9} \ln x + \frac{x^3}{9} + C \)
  • (D) \( \frac{x^3}{9} \ln x – \frac{x^3}{3} + C \)

Evaluating the integration of x squared ln x is a classic calculus question that frequently appears in competitive exams and university tests. This problem not only checks familiarity with integration by parts but also the ability to verify each multiple-choice option by differentiation. Understanding the complete solution and analyzing every option strengthens conceptual clarity and reduces errors in timed exams.

Step-by-Step Solution

Use integration by parts: \(\int u\,dv = uv – \int v\,du\)

Choose:

  • \(u = \ln x \Rightarrow du = \frac{1}{x}dx\)
  • \(dv = x^2 dx \Rightarrow v = \frac{x^3}{3}\)
$$\int x^2 \ln x\,dx = \ln x \cdot \frac{x^3}{3} – \int \frac{x^3}{3} \cdot \frac{1}{x} dx = \frac{x^3}{3}\ln x – \frac{1}{3}\int x^2 dx$$

$$= \frac{x^3}{3}\ln x – \frac{1}{3} \cdot \frac{x^3}{3} + C = \frac{x^3}{3}\ln x – \frac{x^3}{9} + C$$

Option Analysis

Let \(F(x)\) be each option and differentiate to verify \(F'(x) = x^2 \ln x\).

Option (A): \(\frac{x^3}{3}\ln x – \frac{x^3}{9} + C\)

Differentiate: \(d/dx\left(\frac{x^3}{3}\ln x\right) = x^2\ln x + x^2\)

\(d/dx\left(-\frac{x^3}{9}\right) = -\frac{x^2}{3}\)

Total: \(x^2\ln x + x^2 – \frac{x^2}{3} – \frac{2x^2}{3} = x^2\ln x\) ✅ Correct

Option (B): \(\frac{x^3}{3}\ln x + \frac{x^3}{9} + C\)

Differentiate: \(d/dx\left(\frac{x^3}{3}\ln x\right) = x^2\ln x + x^2\)

\(d/dx\left(\frac{x^3}{9}\right) = \frac{x^2}{3}\)

Total: \(x^2\ln x + x^2 + \frac{x^2}{3} = x^2\ln x + \frac{4x^2}{3}\) ❌ Incorrect

Option (C): \(-\frac{x^3}{9}\ln x + \frac{x^3}{9} + C\)

Differentiate: \(d/dx\left(-\frac{x^3}{9}\ln x\right) = -\left(\frac{x^2}{3}\ln x + \frac{x^2}{3}\right)\)

Total: \(-\frac{x^2}{3}\ln x – \frac{x^2}{3} + \frac{x^2}{3} = -\frac{x^2}{3}\ln x\) ❌ Incorrect

Option (D): \(\frac{x^3}{9}\ln x – \frac{x^3}{3} + C\)

Differentiate: \(d/dx\left(\frac{x^3}{9}\ln x\right) = \frac{x^2}{3}\ln x + \frac{x^2}{3}\)

Total: \(\frac{x^2}{3}\ln x + \frac{x^2}{3} – x^2 = \frac{x^2}{3}\ln x – \frac{2x^2}{3}\) ❌ Incorrect

Final Answer

Among the given options, Option (A) is the correct antiderivative that differentiates back to \(x^2 \ln x\).

Exam Tips

  • Always verify MCQ options by differentiation, not just integration
  • Follow ILATE rule for choosing \(u\) in integration by parts
  • Watch for sign errors in the constant term
  • Practice similar problems: \(\int x^n \ln x\,dx\)

 

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