Q. 17 Match the type of reaction in Group-1 with the most appropriate description in Group-2
Group 1 Group 2
P Hydroboration-oxidation 1 Electrophilic aromatic substitution
Q Nucleophilic aromatic substitution 2 Oxaphosphetane intermediate
R Wittig reaction 3 Meisenheimer complex
S Friedel-Crafts reaction 4 Anti-Markownikoff’s product
(A) P-2, Q-4, R-1, S-3
(B) P-4, Q-3, R-1, S-2
(C) P-4, Q-3, R-2, S-1
(D) P-2, Q-1, R-4, S-3
Hydroboration-oxidation yields anti-Markovnikov alcohols, while Wittig involves an oxaphosphetane intermediate. The correct matching for this GATE-style question is option (C). This guide breaks down each reaction for exam preparation.
Correct Answer
The right option is (C) P-4, Q-3, R-2, S-1. Hydroboration-oxidation (P) gives the anti-Markovnikov product (4). Nucleophilic aromatic substitution (Q) forms the Meisenheimer complex (3). Wittig reaction (R) proceeds via oxaphosphetane intermediate (2). Friedel-Crafts reaction (S) is electrophilic aromatic substitution (1).
Hydroboration-Oxidation (P)
This reaction adds water across alkenes in an anti-Markovnikov fashion, placing OH on the less substituted carbon. It follows syn addition with no carbocation rearrangements. Thus, P matches 4 (Anti-Markovnikov’s product).
Nucleophilic Aromatic Substitution (Q)
Nucleophiles attack electron-deficient aromatics, forming a sigma complex called the Meisenheimer complex. This stabilizes the negative charge during substitution. Q pairs with 3 (Meisenheimer complex).
Wittig Reaction (R)
Ylides react with carbonyls to form alkenes via a betaine, collapsing to an oxaphosphetane intermediate. The ring opens to yield the alkene and phosphine oxide. R corresponds to 2 (Oxaphosphetane intermediate).
Friedel-Crafts Reaction (S)
Alkylation or acylation on benzene uses Lewis acids like AlCl3 for electrophilic aromatic substitution. The acylium ion attacks the ring. S links to 1 (Electrophilic aromatic substitution).
Why Other Options Fail
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(A) Wrongly assigns Wittig to 1 and Friedel-Crafts to 3.
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(B) Mismatches Wittig to 1 and hydroboration to 4 correctly but swaps others.
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(D) Incorrectly places hydroboration with 2 and Wittig with 4.


