(JUNE 2007) 10. Consider the following chemical reaction in which forward rate constant (K1) is 1/sec and backward rate constant is 107/sec What will equilibrium rate constant? (1) 1 (2) 107 (3) 10-7 (4) 106

10. Consider the following chemical reaction in which forward rate constant (K1) is 1/sec and
backward rate constant is 107/sec

What will equilibrium rate constant?
(1) 1                                                               (2) 107
(3) 10-7                                                          (4) 106

The correct answer is (3) 10−7. The equilibrium constant (Keq) for the reaction is calculated as the ratio of the forward rate constant K1=1 s−1 to the backward rate constant K2=107 s−1, so Keq=K1K2=1107=10−7.


Introduction

The equilibrium constant is a fundamental concept in chemistry and biochemistry, representing the ratio of product to reactant concentrations at equilibrium in reversible reactions. Understanding how to calculate the equilibrium constant using the rate constants for the forward and backward reactions is essential for students, researchers, and those preparing for competitive exams such as CSIR NET and GATE. This article provides a step-by-step explanation for calculating equilibrium rate constants from provided kinetic data.


Theoretical Background: Rate Constants and Equilibrium

A reversible chemical reaction can be represented as:

A⇌K1K2B

  • Forward rate constant (K1): Rate at which A converts to B.

  • Reverse (backward) rate constant (K2): Rate at which B converts back to A.

At equilibrium, the rates of forward and reverse reactions equalize, and the equilibrium constant (Keq) links the two:

Keq=K1K2


Problem Breakdown

Given:

  • Forward rate constant (K1) = 1 s−1

  • Backward rate constant (K2) = 107 s−1

To find:
Equilibrium constant (Keq)


Mathematical Calculation

Plugging the numbers into the equation:

Keq=K1K2=1107=10−7

Thus, the equilibrium rate constant for this reaction is 10−7.


Conceptual Explanation

  • Low Equilibrium Constant (Keq<1): Indicates that at equilibrium, the concentration of reactant A is much higher than product B. The reverse reaction dominates.

  • High Equilibrium Constant (Keq>1): Favors product formation—most reactant is converted into product at equilibrium.

  • In this scenario, K2 (backward rate) is much larger than K1, meaning the system heavily favors the reactant side (A) at equilibrium.


Importance in Life Sciences

Equilibrium constants dictate the direction and extent of biological and chemical reactions:

  • Enzyme kinetics: Understanding how enzymes drive reactions toward products or substrates.

  • Metabolic control: Pathways with low equilibrium constants limit the conversion of substrates to products unless coupled with favorable reactions.

  • Drug design: Binding affinities, reaction reversibility, and metabolic flux control are all governed by kinetic and equilibrium principles.


Real-World Applications

  • Clinical Chemistry: Drug binding, metabolic transformations, enzymatic assays use equilibrium constants for quantitation.

  • Biochemical Research: Protein folding, ligand interactions, nucleic acid hybridization all rely on these calculations.

  • Environmental Chemistry: Predicting the fate of pollutants based on kinetic and equilibrium data.


Examples and Practice for Students

  1. If a reaction has K1=100 s−1 and K2=50 s−1, calculate Keq:

    Keq=10050=2

    The product (B) is favored at equilibrium.

  2. For K1=5 s−1 and K2=20 s−1:

    Keq=520=0.25

    The reactant (A) is favored.


Common Pitfalls and Misconceptions

  • Units: Equilibrium constants are typically dimensionless for concentration-based equilibria, but kinetic units (s⁻¹) must be consistent for proper calculations.

  • Directionality: Always use the forward and backward rate constants according to the direction specified in the question.

  • Reaction Type: Applies only to simple, reversible reactions. Complex mechanisms may require more advanced treatment.


Summary Table

K1 (Forward) K2 (Backward) Keq Equilibrium Favored
1 107 10−7 Reactant (A)
103 102 10 Product (B)
2 2 1 Both (A ≈ B)

Conclusion

The equilibrium rate constant for the reaction, given the kinetic parameters, is 10−7. This calculation confirms that the reaction heavily favors the reactant side at equilibrium. Knowledge of equilibrium constants and their calculation from rate constants is crucial for mastering biochemistry, enzyme kinetics, and many fields in life sciences.

47 Comments
  • Aakansha sharma Sharma
    September 12, 2025

    Equilibrium rate constant (Keq)=kf/kb so 1/(10)7=(10)-7

  • Mohd juber Ali
    September 12, 2025

    K1 = forward reaction = 1
    K2 = backword reaction =10^7
    Kf/kb= 1/10^7=(10)^-7

  • Mansukh Kapoor
    September 12, 2025

    The correct answer is option 3rd
    Equilibrium rate constant =
    Kf/Kb=1/10^7
    So 10^-7 is the answer

  • Varsha Tatla
    September 12, 2025

    Given data -k1=1
    K2=10^7
    Keq=k1÷k2
    So 1÷10^7=10’7

  • Tanvi Panwar
    September 12, 2025

    Equilibrium constant= Kf/Kb
    So, 1/10^7=10^7.

  • Heena Mahlawat
    September 12, 2025

    10^-7

  • Santosh Saini
    September 13, 2025

    K1= 1 , K2=10^7 , equilibrium constant=kf/kb , so =1/10^7 ,=10^-7

  • Kanica Sunwalka
    September 13, 2025

    keq = kf /kb
    by putting values of kf =1 , kb = 10^7 in the above formula
    keq =10^minus 7

  • Dharmpal Swami
    September 13, 2025

    Keq.=k1/k2
    Keq.=1/ 10’7
    =10^-7

  • Kirti Agarwal
    September 13, 2025

    10^-7

  • Neha Yadav
    September 13, 2025

    10^-7

  • Bhawna Choudhary
    September 13, 2025

    Option C is correct

  • Soniya Shekhawat
    September 14, 2025

    Equilibrium rate constant keq=kf /kb so answer is c is correct.

    • Nilofar Khan
      September 14, 2025

      Equilibrium rate constant=kf/kb
      Correct answer is ( 3 ) 10^-7

    • Mitali saini
      September 14, 2025

      (3) 10-7

      • Mitali sainiKeq= Kf/Kb 1/10^⁷ 10^-⁷ Option 3rd is correct answer
        September 14, 2025

        (3) 10-7

  • Aafreen Khan
    September 14, 2025

    Keq= Kf/Kb
    1/10^⁷
    10^-⁷
    Option 3rd is correct answer

  • Kajal
    September 14, 2025

    Option c bcz kc equal to kf/kb

  • Ayush Dubey
    September 14, 2025

    Option 3

  • Vanshika Sharma
    September 14, 2025

    Opt 3

  • Khushi Agarwal
    September 14, 2025

    Option C is correct answer
    10^-7

  • Anjali
    September 14, 2025

    Option 3

  • Bhavana kankhedia
    September 14, 2025

    10^-7

  • Manisha choudhary
    September 14, 2025

    Equilibrium rate constants=K (foward) / K (backwards)
    So option 3 is right 👍🏻

  • Anurag Giri
    September 14, 2025

    Equilibrium rate constant (Keq)=kf/kb so 1/(10)7=(10)-7

  • Avni
    September 14, 2025

    Keq = kf/kb
    1/ (10)7 = (10)-7

  • Sonal nagar
    September 14, 2025

    10-7

  • Deepika sheoran
    September 14, 2025

    K1= forward Reaction =1
    K2=Backward Reaction=10^7
    Kf/Kb =1/10^7=(10)^-7

  • Rishita
    September 14, 2025

    Done sir 👍🏻

  • Asha Gurzzar
    September 14, 2025

    Done sir option 3

  • Simran Saini
    September 14, 2025

    Equilibrium rate constant (Keq)=kf/kb
    1/(10)7=(10)-7

  • Payal Gaur
    September 14, 2025

    Option 3rd equilibrium constant Kf/Kb= 1/10^7 =10^-7

  • Pallavi Ghangas
    September 14, 2025

    3

  • anjani sharma
    September 14, 2025

    Answer 3
    Equilibrium rate constant (Keq)=kf/kb so 1/(10)7=(10)-7

  • Sneha Kumawat
    September 14, 2025

    10^-7

  • Devika
    September 15, 2025

    10^7

  • Preeti sharma
    September 15, 2025

    Correct answer is option 3rd

  • Ajay Sharma
    September 15, 2025

    Kf/kb= 1/10^7 = 10^-7 , option 3 is correct

  • Khushi Vaishnav
    September 15, 2025

    Equilibrium rate constant
    (Keq)=kf/kb so,
    1/(10)7=(10)-7

  • Minal Sethi
    September 16, 2025

    keq = kf/kb
    = 1/10^7
    = 10^-7

  • Yogita
    September 16, 2025

    10-7

  • Muskan singodiya
    September 16, 2025

    10-7

  • Alec
    September 16, 2025

    option c is correct- 10^ -7

  • Monika jangid
    September 17, 2025

    10-⁷

  • Muskan Yadav
    September 17, 2025

    K1 = forward reaction = 1
    K2 = backward reaction =10^7
    Kf/kb= 1/10^7=(10)^-7

  • Divya rani
    September 17, 2025

    Keq……kf/kb
    1/10^7……10^-7

  • Priti khandal
    September 17, 2025

    C is right

Leave a Reply

Your email address will not be published. Required fields are marked *

Latest Courses