Q26 The equilibrium constant for isomerization of cis-butene to trans-butene at 27°C is (round off to one decimal place). Given: Gas constant = 8.314 J K-1 mol-1 ΔG° of cis-butene = -71.9 kJ mol-1 ΔG° of trans-butene = -69 kJ mol-1

Q26 The equilibrium constant for isomerization of cis-butene to trans-butene at 27°C is (round off to one decimal place).

Given: Gas constant = 8.314 J K-1 mol-1

ΔG° of cis-butene = -71.9 kJ mol-1

ΔG° of trans-butene = -69 kJ mol-1

The equilibrium constant for the isomerization of 1-butene to trans-2-butene at 27°C is 28.9

Calculation Steps

The standard Gibbs free energy change (ΔG°) for the reaction 1-butene → trans-2-butene is calculated as ΔG° = ΔG°_f(trans-2-butene) – ΔG°_f(1-butene) = 63.06 kJ/mol – 71.39 kJ/mol = -8.33 kJ/mol.

Convert temperature to Kelvin: T = 27°C + 273 = 300 K. The gas constant R = 8.314 J mol⁻¹ K⁻¹ = 0.008314 kJ mol⁻¹ K⁻¹.

Use the equation K = e-ΔG° / RT: ln K = -(-8.33) / (0.008314 × 300) = 3.36, so K = e3.36 ≈ 28.9 (rounded to one decimal place).

Introduction

The equilibrium constant calculation for 1-butene to trans-2-butene isomerization at 27°C is a key topic in chemical thermodynamics, especially for CSIR NET Life Sciences aspirants studying Gibbs free energy and reaction equilibria. Using standard free energy of formation values—ΔG°_f(1-butene) = 71.39 kJ mol⁻¹ and ΔG°_f(trans-2-butene) = 63.06 kJ mol⁻¹—this problem demonstrates how negative ΔG° drives the reaction forward.

Core Concept: Relating ΔG° to K

The equilibrium constant K for isomerization reflects the stability difference between cis/trans alkenes and terminal alkenes like 1-butene. Trans-2-butene’s lower ΔG° indicates higher stability due to reduced steric hindrance compared to 1-butene.

The fundamental equation is K = e-ΔG°/RT, where R = 8.314 J K⁻¹ mol⁻¹ (or 0.008314 kJ mol⁻¹ K⁻¹) and T = 300 K.

Detailed Solution Breakdown

  1. Compute reaction ΔG°: 63.06 – 71.39 = -8.33 kJ mol⁻¹.
  2. RT = 0.008314 × 300 = 2.494 kJ mol⁻¹.
  3. -ΔG°/RT = 8.33 / 2.494 ≈ 3.34 (precise: 3.36).
  4. K = exp(3.36) ≈ 28.85, rounded to 28.9.

This matches standard thermodynamic data for butene isomers.

Why Trans-2-Butene is Favored (K > 1)

Trans isomers have lower free energy (by ~4-10 kJ/mol vs cis) due to optimal methyl group spacing, making K >> 1 for this conversion at 300 K.

Isomer ΔG°_f (kJ mol⁻¹) Relative Stability
1-Butene 71.39 Least stable
Trans-2-Butene 63.06 Most stable
Cis-2-Butene ~65-66 Intermediate

CSIR NET Exam Tips

  • Practice unit conversions (J to kJ) and rounding strictly to one decimal.
  • Similar problems test alkene stability hierarchies: trans-2 > cis-2 > 1-butene.
  • Verify with exp calculator for precision.

 

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