Q.50 The distance between the parallel lines 2𝑥 + 5𝑦 = 7 and 2𝑥 + 5𝑦 = 15 is ______ (rounded
off to 2 decimals).
Formula Overview
Parallel lines share the same coefficients for x and y. For lines ax + by + c₁ = 0 and ax + by + c₂ = 0, the perpendicular distance d is:
d = \frac{|c₂ – c₁|}{\sqrt{a² + b²}}
Rewrite the given equations in standard form: 2x + 5y – 7 = 0 and 2x + 5y – 15 = 0. Here, a = 2, b = 5, c₁ = -7, c₂ = -15.
Step-by-Step Calculation
- Substitute values: |c₂ – c₁| = |-15 – (-7)| = |-8| = 8
- Denominator: \sqrt{2² + 5²} = \sqrt{4 + 25} = \sqrt{29} ≈ 5.385
- Thus, d = \frac{8}{\sqrt{29}} ≈ \frac{8}{5.385} ≈ 1.48597
- Rounded to two decimals: 1.49
Common Options Explained
In multiple-choice contexts, options might include:
- 1.48: Under-rounded value before precise check
- 1.49: Correct rounded answer (1.48597 ≈ 1.49)
- 1.50: Over-approximation ignoring exact sqrt
- 8/√29: Unrounded exact form, not decimal
The correct choice is 1.49, as it matches standard rounding (1.48597 to two decimals).


