Q. 14 Two equivalents of π react with one equivalent of π to produce a major product π.
The number of double bonds present in the major product π is ____ .
Question Overview
Two equivalents of compound P react with one equivalent of compound Q to produce a major product R.
The question asks:
What is the number of double bonds present in the major product R?
This problem is based on Wittig reaction chemistry and tests your understanding of:
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Phosphonium ylides
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Carbonyl reactions
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Double bond formation
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Conjugated polyene systems
Identification of Reactants
Compound P
From the structure shown:
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P contains a terminal aldehyde group (βCHO)
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It already has conjugated C=C double bonds
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Acts as a carbonyl compound
Compound Q
From the given structure:
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Q is a bis-phosphonium ylide
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Contains two Wittig-active phosphorus ylides
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Each ylide can react with one carbonyl group
Reaction Concept (Core Chemistry)
π¬ Key Reaction: Wittig Reaction
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Each phosphonium ylide reacts with one aldehyde
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Forms one new C=C double bond
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Produces triphenylphosphine oxide (by-product)
Important Observation
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Q has two ylide centers
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Two equivalents of P are required
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Hence, two new C=C double bonds are formed
Step-by-Step Double Bond Counting
Step 1: Existing Double Bonds in P
From the given structure of P:
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Three C=C double bonds
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One C=O double bond (aldehyde)
Step 2: Effect of Wittig Reaction
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The C=O double bond is replaced by C=C
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Each reaction adds one new alkene
Since two equivalents of P react:
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Two C=O bonds are converted
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Two new C=C bonds are formed
Total Double Bonds in Product R
| Source | Number of Double Bonds |
|---|---|
| Existing C=C in two P molecules | 6 |
| New C=C formed via Wittig | 2 |
| Total | 8 |
β Correct Answer
βοΈ Number of double bonds in the major product R = 8
Why Other Answers Are Incorrect
β 6 Double Bonds
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Ignores formation of new C=C bonds from Wittig reaction
β 7 Double Bonds
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Counts only one Wittig reaction instead of two
β 9 or More Double Bonds
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Overcounts by assuming additional unsaturation not formed in reaction
Final Conclusion
βοΈ Since:
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Q contains two phosphonium ylides
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Each reacts with one aldehyde group
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Two new C=C bonds are formed
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And existing conjugation remains intact
β The major product R contains exactly 8 double bonds
Exam Tip π
In Wittig reaction problems:
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Always count existing unsaturation
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Then add one C=C for each ylide used
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Carbonyl C=O becomes C=C, not extra


