GATE Biotechnology Previous Year Papers with Solutions Archives - Page 34 of 104 - CSIR NET LIFE SCIENCE COACHING | NTA NET LIFE SCIENCE

60. The standard free energy change (ΔG°′) for ATP hydrolysis is −30 kJ·mole−1. The in vivo concentrations of ATP, ADP and Pi in E. coli are 7.90, 1.04 and 7.90 mM, respectively. When E. coli cells are cultured at 37 °C, the free energy change (ΔG) for ATP hydrolysis in vivo is __________ kJ·mole−1.

GATE Biotechnology 2015 Previous Year Papers with Solutions

ΔG for ATP Hydrolysis in E. coli at 37°C

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January 17, 2026
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60. The standard free energy change (ΔG°′) for ATP hydrolysis is −30 kJ·mole−1. The in vivo concentrations of ATP, ADP and Pi in E. coli are 7.90, 1.04 and 7.90 […]

61. In a fed-batch culture, 200 g·L−1 glucose solution is added at a flow rate of 50 L·h−1. The initial culture volume (at quasi steady state) and the initial cell concentration are 600 L and 20 g·L−1, respectively. The yield coefficient (Yx/s) is 0.5 g cell mass·g substrate−1. The cell concentration (g·L−1) at quasi steady state at t = 8 h is (A) 40 (B) 52 (C) 60 (D) 68

GATE Biotechnology 2015 Previous Year Papers with Solutions

Fed-Batch Culture Cell Concentration Calculation

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January 17, 2026
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61. In a fed-batch culture, 200 g·L−1 glucose solution is added at a flow rate of 50 L·h−1. The initial culture volume (at quasi steady state) and the initial cell […]

59. Three distinct antigens X, Y and Z were used to raise antibodies. Antigen Z was injected in a mouse on day zero followed by the administration of antigens X and Y on day 28. A second injection of antigen X was administered on day 70. The antibody titers were monitored in the serum every day and the results are shown below. Which one of the following statements regarding the antibody titers in the serum is INCORRECT? (A) Z-specific IgG will be high on day 14 (B) X-specific antibody titer will be high on day 84 (C) X-specific IgG will be high on day 42 (D) Y-specific IgG will be high on day 84

GATE Biotechnology 2015 Previous Year Papers with Solutions

Antibody Titer Dynamics Explained

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January 17, 2026
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59. Three distinct antigens X, Y and Z were used to raise antibodies. Antigen Z was injected in a mouse on day zero followed by the administration of antigens X […]

58. An in vitro translation system can synthesize peptides in all three reading frames of the RNA template. When 5′- UCUCUCUC---(UC)ₙ---UCUCUCUC -3′ was used as the template in this in vitro translation system, the synthesized peptides contained 50% each of serine and leucine. When 5′- CCUCCUCCU---(CCU)ₙ---CCUCCU -3′ was used as the template, the synthesized peptides contained 33.3% each of serine, leucine, and proline. Deduce the codon for proline. (A) UCU (B) CUC (C) CCU (D) UCC

GATE Biotechnology 2015 Previous Year Papers with Solutions

Deduce Proline Codon

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January 17, 2026
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58. An in vitro translation system can synthesize peptides in all three reading frames of the RNA template. When 5′- UCUCUCUC—(UC)ₙ—UCUCUCUC -3′ was used as the template in this in […]

57. A synchronous culture containing 1.8 × 105 monkey kidney cells was seeded into three identical flasks. The doubling time of these cells is 24 h. After 24 h, the cells from all the three flasks were pooled and dispensed equally into each well of three 6-well plates. The number of cells in each well will be __________ × 104.

GATE Biotechnology 2015 Previous Year Papers with Solutions

Monkey Kidney Cells Doubling Time Calculation

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January 17, 2026
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57. A synchronous culture containing 1.8 × 105 monkey kidney cells was seeded into three identical flasks. The doubling time of these cells is 24 h. After 24 h, the […]

56. Assuming random distribution of nucleotides, the average number of fragments generated upon digestion of a circular DNA of size 4.3 × 105 bp with AluI (5′-AG|CT-3′) is __________ × 103.

GATE Biotechnology 2015 Previous Year Papers with Solutions

Calculating AluI Restriction Fragments

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January 17, 2026
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56. Assuming random distribution of nucleotides, the average number of fragments generated upon digestion of a circular DNA of size 4.3 × 105 bp with AluI (5′-AG|CT-3′) is __________ × […]

55. A heterozygous tall plant (Tt) was crossed with a homozygous dwarf plant (tt). The resultant seeds were collected. If five seeds are chosen at random, then the probability (in %) that exactly two of these seeds will yield dwarf plants is __________.

GATE Biotechnology 2015 Previous Year Papers with Solutions

Probability Exactly 2 Dwarf Plants

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January 17, 2026
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55. A heterozygous tall plant (Tt) was crossed with a homozygous dwarf plant (tt). The resultant seeds were collected. If five seeds are chosen at random, then the probability (in […]

54. The Ki of a novel competitive inhibitor designed against an enzyme is 2.5 µM. The enzyme was assayed in the absence or presence of the inhibitor (5 µM) under identical conditions. The Km in the presence of the inhibitor was found to be 30 µM. The Km in the absence of the inhibitor is __________ µM.

GATE Biotechnology 2015 Previous Year Papers with Solutions

Calculate Km for Competitive Enzyme Inhibition

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January 17, 2026
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54. The Ki of a novel competitive inhibitor designed against an enzyme is 2.5 µM. The enzyme was assayed in the absence or presence of the inhibitor (5 µM) under […]