(DEC 2007) 29. In a biochemical reaction catalyzed by enzyme following the Michales-Menten equation, what will be the substrate concentration, when the observed velocity of reaction is 90% of the maximum velocity? (1) 18 Km (2) 9Km (3) 5 Km (4) 1Km

(DEC 2007)
29. In a biochemical reaction catalyzed by enzyme following the Michales-Menten equation, what will be the substrate concentration, when the observed velocity of reaction is 90% of the maximum velocity?
(1) 18 Km                                                (2) 9Km
(3) 5 Km                                               (4) 1Km

The correct answer is (2) 9Km.


Introduction

Enzyme kinetics underpins our understanding of biochemical reactions, particularly those following Michaelis-Menten behavior. The Michaelis-Menten equation relates reaction velocity to substrate concentration, allowing predictions of enzymatic behavior. One important calculation is determining the substrate concentration required to reach a specified fraction of the maximum velocity, such as 90%. This article explains how to calculate this substrate concentration and interprets it with respect to Km.


Michaelis-Menten Equation

The reaction velocity (V0) relates to substrate concentration [S] as:

V0=Vmax[S]Km+[S]

Where:

  • V0: Initial reaction velocity

  • Vmax: Maximum reaction velocity

  • Km: Michaelis constant (substrate concentration at half Vmax)

  • [S]: Substrate concentration


Goal: Find [S] when V0=0.9×Vmax

Set:

0.9Vmax=Vmax[S]Km+[S]

Divide both sides by Vmax:

0.9=[S]Km+[S]

Cross multiply:

0.9(Km+[S])=[S]0.9Km+0.9[S]=[S]

Subtract 0.9[S] from both sides:

0.9Km=[S]−0.9[S]=0.1[S]

Solve for [S]:

[S]=0.9Km0.1=9Km


Interpretation

  • To reach 90% of Vmax, the substrate concentration needs to be 9 times the Km value.

  • This shows substrate concentration must be significantly higher than Km to approach saturation.


Practical Importance

  • Helps in biochemical assay design ensuring substrate levels are sufficient for near-maximal enzyme activity.

  • Assists in understanding enzyme capacity in metabolic regulation.

  • Aids drug design by considering substrate/enzyme binding dynamics.


Summary Table

Fraction of Vmax Substrate Concentration [S] Interpretation
0.5 (50%) Km Half saturation
0.9 (90%) 9×Km Near saturation
0.99 (99%) 99×Km Near complete saturation

Conclusion

For enzyme-catalyzed reactions following Michaelis-Menten kinetics, the substrate concentration required to reach 90% of the maximum velocity is 9 times the Michaelis constant (9Km). This relationship helps define enzyme efficiency and informs protocols for studying enzyme activities in various scientific fields.


This comprehensive explanation strengthens knowledge of enzyme kinetics principles, equipping students and researchers to analyze and apply Michaelis-Menten theory effectively in practical and academic contexts.

36 Comments
  • Varsha Tatla
    September 12, 2025

    9kn

  • Aakansha sharma Sharma
    September 12, 2025

    Here we have to find substrate conc . andVo is given 90./.of Vmax means Vo= 90/100 of Vmax
    90/100Vmax =Vmax S/Km+S
    100S=90Km+90S
    100S-90S=90km
    10S=90Km
    s=90Km/10=9Km is answer

  • Mansukh Kapoor
    September 13, 2025

    The correct answer is option 2nd
    9Km

  • Khushi Vaishnav
    September 13, 2025

    9Km

  • Kanica Sunwalka
    September 13, 2025

    90 /100 Vmax = Vmax S / Km + S
    Ans is 9 Km

  • Sakshi Kanwar
    September 13, 2025

    Vo 90% can be written as 0.9 of Vmax
    So according to M.M equation
    0.9Vmax = Vmax.S / Km+S
    Dividing Vmax from both side we get
    0.9 = S / Km+ S
    0.9Km+0.9 S = S
    0.9Km = 0.1 S
    S = 9km

  • Mohd juber Ali
    September 14, 2025

    According to question
    V= Vmax✖️90/100
    V=Vmax✖️9/10
    (V =Vmax.s/km+s)
    Vmax✖️9/10=Vmax.S/km+S
    9/10=s/km+S
    Km+S=10S/9
    Km=10S-9S/9
    Km=S/9
    S=9Km

  • Sakshi yadav
    September 14, 2025

    Vo = 90/100vmax=vmax s /km + s=. 100s = 90km+ 90s = 100- 90= 90 so s= 90/10= 9 km

  • Aafreen Khan
    September 14, 2025

    9 Km is the correct answer

  • Pooja
    September 14, 2025

    Option b is correct

  • Kirti Agarwal
    September 14, 2025

    0.9Vmax= Vmax× S/Km +s
    0.9Km+0.9s=s
    0.9km=s-0.9s
    S=0.9km/0.1
    S=9km

  • Anurag Giri
    September 14, 2025

    The correct answer is option 2nd
    9Km

  • Khushi Agarwal
    September 14, 2025

    The correct answer is (2)
    9Km

  • Anju
    September 14, 2025

    Ans:9km
    V=Vmax.s/km+s

  • Neha Yadav
    September 14, 2025

    Vo 90% can be written as 0.9 of Vmax
    So according to M.M equation
    0.9Vmax = Vmax.S / Km+S
    0.9 = S / Km+ S
    0.9Km+0.9 S = S
    0.9Km = 0.1 S
    S = 9km

  • Rishita
    September 14, 2025

    9Km.

  • Bhawna Choudhary
    September 14, 2025

    9km is correct answer

  • Anjali
    September 14, 2025

    The correct answer is (2)
    9Km

  • Vanshika Sharma
    September 14, 2025

    9 km is ans

  • Tanvi Panwar
    September 14, 2025

    9 Km is the answer.

  • Payal Gaur
    September 14, 2025

    Option 2 9km

  • Ayush Dubey
    September 14, 2025

    9Km

  • Shivani
    September 14, 2025

    9km

  • anjani sharma
    September 14, 2025

    9 Km is the answer.

  • Pallavi Ghangas
    September 14, 2025

    9km

  • Avni
    September 14, 2025

    9 Km is the correct answer

  • Nilofar Khan
    September 15, 2025

    Correct answer is (2) s= 9Km
    Vo=.9Vmax

  • Mitali saini
    September 15, 2025

    The correct answer is (2) 9Km.

  • Asha Gurzzar
    September 15, 2025

    Option 2is correct 9km

  • Simran Saini
    September 15, 2025

    Option 2nd
    9Km.

  • Arushi Saini
    September 15, 2025

    90 /100 Vmax = Vmax S / Km + S
    Ans is 9 Km

  • Minal Sethi
    September 16, 2025

    V = Vmax*S/Km+S
    90= 100S/Km+S
    90Km + 90S = 100S
    90 Km = 10S
    S = 9Km

  • Palak Sharma
    September 16, 2025

    according to M.M equation
    0.9Vmax = Vmax.S / Km+S
    0.9 = S / Km+ S
    0.9Km+0.9 S = S
    0.9Km = 0.1 S
    S = 9km

  • Muskan Yadav
    September 17, 2025

    The maximum velocity is 9 times the Michaelis constant [9Km]

  • Deepika sheoran
    September 18, 2025

    Option 2 is correct
    9km

  • Khushi Singh
    September 25, 2025

    9 Km

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