11. Possible types of gametes formation from genotype AABBCcDdEe would be-
(1) 16           (2) 64
(3) 8             (4) 128

Step-by-step reasoning

Genotype given: AABBCcDdEe

• A: AA → homozygous (only A in gametes).
• B: BB → homozygous (only B in gametes).
• C: Cc → heterozygous (C or c).
• D: Dd → heterozygous (D or d).
• E: Ee → heterozygous (E or e).

Only heterozygous loci generate variation in gametes.

Count heterozygous pairs: Cc, Dd, Ee → n = 3 heterozygous gene pairs.

Number of different gametes is given by:

No. of gametes = 2ⁿ = 2³ = 8

So the organism can produce 8 distinct gamete types (e.g., ABCDE, ABCDe, ABCdE, ABCde, ABcDE, ABcDe, ABcdE, ABcde).

Checking options

• 16 → 2⁴, would require 4 heterozygous pairs.
• 64 → 2⁶, for 6 heterozygous pairs.
• 8 → 2³, matches our calculation.
• 128 → 2⁷, for 7 heterozygous pairs.

Therefore, the correct option is (3) 8.