Q17. The O–O bond order in O22- species is (A) 0.5 (B) 1.0 (C) 1.5 (D) 2.0

Q17. The OO bond order in O22- species is
(A)
0.5
(B)
1.0
(C)
1.5
(D)
2.0


The O–O bond order in the O₂²⁻ (peroxide ion) species is 1.0.

This matches option (B) in competitive exams like CSIR NET Life Sciences, where molecular orbital theory determines bonding in diatomic species.

Bond Order Calculation

O₂²⁻ has 18 valence electrons (8 per O atom + 2 extra). The molecular orbital configuration is σ2s² σ2s*² σ2pz² π2px² π2py² π2px*² π2py*², ignoring core 1s orbitals.

  • Bonding electrons: 10 (σ2s², σ2pz², π2px², π2py²)
  • Antibonding electrons: 8 (σ2s*², π2px*², π2py*²)

Bond order = (10 – 8)/2 = 1

Option Analysis

(A) 0.5

Matches species like H₂⁺ or He₂ with 1 bonding and 1 antibonding electron; too weak for O₂²⁻’s filled orbitals.

(B) 1.0 ✓

Correct for O₂²⁻, indicating a single O–O bond as in peroxides (e.g., H₂O₂).

(C) 1.5

Applies to O₂⁻ (superoxide, 17 electrons, 10 bonding – 7 antibonding).

(D) 2.0

Matches neutral O₂ (16 electrons, 10 bonding – 6 antibonding).

O₂²⁻ Bond Order Calculations for CSIR NET

O₂²⁻ bond order calculations help CSIR NET aspirants master molecular orbital theory for diatomic oxygen species. The peroxide ion features a single O–O bond, contrasting stronger bonds in O₂ or O₂⁺.

Molecular Orbital Diagram Summary

The diagram shows 10 bonding vs. 8 antibonding electrons, yielding bond order 1—diamagnetic and stable in compounds like Na₂O₂. Lower bond order than O₂ (2.0) explains its longer O–O distance (~1.49 Å).

CSIR NET Exam Relevance

Species Bond Order Magnetic Property
O₂ 2.0 Paramagnetic
O₂⁻ 1.5 Paramagnetic
O₂²⁻ 1.0 Diamagnetic

Key Takeaway: This trend predicts stability: higher bond order means stronger bonds.

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