Q. 12 Which among the following has the least second ionization energy? (A) Al (B) Si (C) P (D)

Q. 12 Which among the following has the least second ionization energy?
(A) Al
(B) Si
(C) P
(D) S

Mg has the least second ionization energy among Al, Si, and P.

Second ionization energy measures the energy needed to remove a second electron from a gaseous +1 ion. For these period 3 elements, Mg requires the lowest energy at 1450.7 kJ/mol due to its electron configuration after the first ionization.

Answer Key

(D) Mg

Mg⁺ (losing an electron from 3s¹) has the lowest second IE at 1450.7 kJ/mol, compared to Al (1816.7 kJ/mol), Si (1577.1 kJ/mol), and P (1907 kJ/mol).

Option Analysis

(A) Al

Al loses its first 3p¹ electron easily (first IE: 577.5 kJ/mol), forming Al⁺ ([Ne] 3s²). The second IE removes from stable full 3s², requiring high energy (1816.7 kJ/mol).

(B) Si

Si⁺ ([Ne] 3s² 3p¹) loses a 3p electron for second IE (1577.1 kJ/mol), higher than Mg but lower than Al due to less stable p orbital vs. full s².

(C) P

P⁺ ([Ne] 3s² 3p²) removes from less stable 3p² (1907 kJ/mol), higher than Si and Al due to increasing effective nuclear charge across the period.

(D) Mg

Mg⁺ ([Ne] 3s¹) removes from half-filled 3s¹ to stable [Ne] configuration (1450.7 kJ/mol), lowest as it avoids breaking a full subshell unlike others.

Introduction to Second Ionization Energy Trends

Second ionization energy trends across period 3 elements like Al, Si, P, and Mg depend on electron configurations post-first ionization and nuclear charge effects. Mg shows the least second ionization energy due to forming a stable noble gas configuration easily.

Detailed Comparison Table

Element Configuration (Neutral) +1 Ion Config. Second IE (kJ/mol) Reason for Value
Al [Ne] 3s² 3p¹ [Ne] 3s² 1816.7 Removes from stable 3s²
Si [Ne] 3s² 3p² [Ne] 3s² 3p¹ 1577.1 3p electron easier than full s²
P [Ne] 3s² 3p³ [Ne] 3s² 3p² 1907 Higher Zeff in p orbitals
Mg [Ne] 3s² [Ne] 3s¹ 1450.7 Lowest; achieves [Ne] stability

Why Mg Has Least Second Ionization Energy

Mg’s second ionization forms Mg²⁺ ([Ne]), a stable noble gas structure from 3s¹, requiring minimal energy compared to Al’s full 3s² breach or Si/P’s p-orbital removals amid rising nuclear pull. This exception highlights subshell stability over general left-to-right IE increase.

CSIR NET Exam Tips

For competitive exams, memorize period 3 second IE order: Mg < Si < Al < P, focusing on stability jumps like full/half-filled subshells. Practice with values from reliable tables for quick MCQ solving.

 

Leave a Reply

Your email address will not be published. Required fields are marked *

Latest Courses