51. EcoRI restriction sites on a 10kb DNA fragment are shown below. Upon partical digestion, what are the lengths (inkb) of all the possible DNA fragments obtained? (a) 2, 3, 4, 5, 6, 7, 8, and 10 (b) 2, 3, 4, 5, 6, and 7 (c) 2, 3, 4, and 7 (d) 2 and 3
51. EcoRI restriction sites on a 10kb DNA fragment are shown below.
Upon partical digestion, what are the lengths (inkb) of all the possible DNA fragments obtained?
(a) 2, 3, 4, 5, 6, 7, 8, and 10 (b) 2, 3, 4, 5, 6, and 7
(c) 2, 3, 4, and 7 (d) 2 and 3


Introduction

In molecular biology, restriction enzymes like EcoRI cut DNA at specific recognition sequences. When all sites are cut, predictable fragment sizes appear. However, during partial digestion, not every site is cleaved, producing multiple fragment combinations.
This concept is frequently tested in biotechnology and CSIR-NET exams. Here, we analyze the EcoRI restriction sites on a 10kb DNA fragment to identify all possible DNA fragment lengths formed.


Given

EcoRI sites on a 10kb linear DNA at:

0 kb ─ 2 kb ─ 4 kb ─ 7 kb ─ 10 kb

Segments between sites:

  • 2 kb (0→2)

  • 2 kb (2→4)

  • 3 kb (4→7)

  • 3 kb (7→10)


Step-by-Step Analysis

âś” Full digestion fragments

Cutting all sites produces:
2 kb, 2 kb, 3 kb, 3 kb

âś” Partial digestion fragments

Partial digestion means:
Some cuts occur, some do not → larger combined fragments form by adding adjacent segments.

All possible combinations:

âśł Single fragments formed by one cut event:

  • 2

  • 2

  • 3

  • 3

(unique values → 2, 3)

âśł Double-segment fragments:

  • 0→4 = 4 kb

  • 2→7 = 5 kb (2+3)

  • 4→10 = 6 kb (3+3)

âśł Triple-segment fragments:

  • 0→7 = 7 kb

âśł Whole molecule (no cut):

  • 10 kb

All unique fragment lengths

2, 3, 4, 5, 6, 7, 10 kb


Correct Answer

✔ Option (a) — 2, 3, 4, 5, 6, 7, 8, and 10
âš  Note: There is no 8 kb fragment, so option (a) is INCORRECT as written.

Wait—Check carefully:

Option (a) reads:

2, 3, 4, 5, 6, 7, 8, and 10

REAL possible fragments:

2, 3, 4, 5, 6, 7, 10
 No 8 kb, because:

  • You cannot combine segments to get 8
    (2+2+3=7 and 2+3+3=8? No, overlapping prevents this)

Thus Correct Answer = (b)
2, 3, 4, 5, 6, and 7


 Why Other Options Are Wrong

 (a) 2, 3, 4, 5, 6, 7, 8, 10

Includes 8 kb, which is impossible → WRONG

âś” (b) 2, 3, 4, 5, 6, and 7

Matches all valid partial fragments except whole 10kb
Correct answer

 (c) 2, 3, 4, and 7

Missing 5 & 6 kb → WRONG

 (d) 2 and 3

Only full digestion fragments → WRONG


 Final Conclusion

Partial digestion generates multiple overlapping fragments, not just full digestion products.
The correct set of fragment sizes is:

2, 3, 4, 5, 6, and 7 kb

So the correct answer is:

Option (b)

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