- Although ribonucleoside triphosphates (rNTPs) are present at approximately IO-fold higher concentration than deoxyribo-nucleoside triphosphates (dNTPs) in the
cell but they are incorporated into DNA at a rate that is more than 1000-fold lower than dNTPs. This is because
(1) DNA polymerase cannot discriminate between dNTPs and rNTPs. But as soon as rNTPs areincorporated in the DNA chain, they are hydrolyzed due to the presence of 2′-OH group.
(2) DNA polymerase cannot dtscrirntnate between dNTPs and rNTPs. But IIS soon as rNTPs are incorporated in the DNA chain, they are excised by the proof reading activity of DNA polymerase.
(3) DNA polymerase efficiently discrtrrunatee. Between rNTPs and dNTPs, because its nucleotide binding pocket cannot accommodate a 2′-OH on the
incoming nucleotide.
(4) DNA polymerase cannot discriminate between rNTPs and dNTPs. Since the rate of transcription jncell is 106 times faster than replication, it cannot compete with RNA polymerase for rNTPs.
Introduction
Inside cells, ribonucleoside triphosphates (rNTPs) are generally present at concentrations roughly 10 times higher than deoxyribonucleoside triphosphates (dNTPs). However, DNA polymerases incorporate rNTPs into DNA at rates more than 1000-fold lower than dNTPs. This remarkable selectivity is essential to maintain DNA integrity and prevent errors during replication. Understanding the molecular mechanism behind this discrimination is critical for insights into DNA replication fidelity.
Cellular Concentrations vs. Incorporation Rates
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rNTPs: Abundant substrates primarily used for RNA synthesis during transcription.
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dNTPs: Less abundant but the correct substrates for DNA synthesis during replication.
Despite the higher abundance of rNTPs, DNA polymerase preferentially incorporates dNTPs, ensuring DNA is composed of deoxyribonucleotides rather than ribonucleotides.
Molecular Basis of Discrimination by DNA Polymerase
Key Reason:
DNA polymerase’s nucleotide binding pocket is structurally designed to exclude the 2′-OH group present on ribonucleotides (rNTPs) but absent on deoxyribonucleotides (dNTPs).
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The presence of the 2′-OH group on rNTPs causes steric hindrance within the active site of DNA polymerase.
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This steric clash prevents efficient binding and incorporation of rNTPs.
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Consequently, DNA polymerase exhibits high fidelity and selectivity for dNTPs.
Evaluation of Options
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DNA polymerase cannot discriminate but rNTPs are hydrolyzed after incorporation due to 2′-OH:
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Incorrect. DNA polymerase discriminates before incorporation; rNTPs are rarely incorporated.
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DNA polymerase cannot discriminate but proofreading excises rNTPs after incorporation:
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Incorrect. Proofreading mainly removes mismatched bases, not ribonucleotides incorporated at very low frequency.
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DNA polymerase efficiently discriminates because its nucleotide binding pocket cannot accommodate 2′-OH on rNTPs:
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Correct. This structural discrimination is the primary reason for low rNTP incorporation.
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DNA polymerase cannot discriminate and transcription outcompetes replication for rNTPs:
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Incorrect and unrelated to polymerase substrate specificity.
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Correct Answer
(3) DNA polymerase efficiently discriminates between rNTPs and dNTPs because its nucleotide binding pocket cannot accommodate a 2′-OH on the incoming nucleotide.
Biological Significance
This discrimination prevents the incorporation of ribonucleotides into DNA, which would otherwise destabilize the DNA double helix and increase mutation rates. The structural specificity of DNA polymerase thus ensures genome stability and faithful replication.
Summary Table
| Option | Description | Correctness |
|---|---|---|
| (1) | No discrimination; rNTPs hydrolyzed after incorporation | Incorrect |
| (2) | No discrimination; proofreading excises rNTPs | Incorrect |
| (3) | Efficient discrimination due to inability to accommodate 2′-OH in binding pocket | Correct |
| (4) | No discrimination; transcription outcompetes replication for rNTPs | Incorrect |
Conclusion
DNA polymerase’s ability to discriminate between ribonucleotides and deoxyribonucleotides is primarily due to the structural constraints of its nucleotide binding pocket, which cannot accommodate the 2′-OH group of rNTPs. This ensures that DNA synthesis proceeds with high fidelity, incorporating dNTPs preferentially despite the higher cellular concentration of rNTPs.



17 Comments
Manisha choudhary
July 25, 2025Nice 🙂🤓😎
Khushi Agarwal
July 29, 2025Option c is correct bcs
DNA polymerase ka jo active site (nucleotide binding pocket) hota hai, wo sirf dNTPs fit kar sakta hai
rNTPs ke paas extra OH group hota hai t2′ position of sugar
Ye extra 2′-OH DNA polymerase ke
pocket mein fit nahi hota, isliye polymerase rNTPs ko reject kar deta hai
Surbhi Rajawat
July 29, 20253rd is correct answer because we know that DNA polymerase has an extra pocket in it’s structure for 3′ to 5′ exonuclease activity. Hence if rNTP are incorporated they will be soon removed
Mansukh Kapoor
July 29, 2025Option 3rd is correct because dNTPs have not the extra oxygen and rNTPs have extra oxygen so the nucleotide pocket detect the rNTPs easily and remove them
anurag giri
July 29, 2025Ans 3 bcoz dntps no extra oxygen and rntos have extra oxygen on 2’ so rntps not fit in nucleotide pocket
Heena
July 29, 2025Dna polymerase enzyme can definitely discriminate between rntps and dntps as rntps have 2’oh that can’t be accommodated in polymerase enzyme structure..that part is already accomplished by amino acids.
Priti Khandal
July 29, 2025Yes sir 3 option is right dna me oh nahi hota aur rna me OH hota h
Priya Khandal
July 29, 2025Third option is right because RNA mein oh hota hai aur DNA Mein on the h hi hota hai
shruti sharma
July 30, 2025option 3 is correct ,dna polymerase has extra pocket
Priya Dhakad
July 30, 2025Option 3 is correct becoz dntps no extra oxygen but rntps have extra oxygen so rntps not fit in nucleotide pocket.
HIMANI FAUJDAR
July 30, 2025Correct answer is 3 because rntps have extra oxygen which can not accomodate in the nucleotide pocket.
Aafreen
July 30, 20253rd is correct answer bcoz its nucleotide binding pocket cannot accommodate a 2′-OH on the incoming nucleotide.
Diksha Chhipa
July 31, 2025Yes dna poly can distinguish between rntps and dntps . Because dntp are lack 2 prime oh .
Dipti Sharma
July 31, 2025(3) DNA polymerase efficiently discriminates between rNTPs and dNTPs because rNTPs has extra 2’OH which can’t be accomodate in dna polymerase nucleotide binding pocket.
Santosh Saini
July 31, 2025Statement 3rd is correct
Khushi Vaishnav
August 1, 2025Efficient discrimination due to inability to accommodate 2′-OH in binding pocket
Deepika Sheoran
November 6, 2025DNA polymerase has extra pocket.