30. The value of ΔG at 37∘C for the movement of Ca2+ ions from the endoplasmic reticulum where [ Ca2+ ] is 1 mM to the cytosol where [ Ca2+ ] is 0.1μM at -50 mV membrane potential is ____ kJmol−1. [R = 8.314JK−1 mol−1 and 1 Faraday = 96500 Coulombs ]
Key Result: ΔG = -37 kJ/mol confirms spontaneous Ca²⁺ release from endoplasmic reticulum (1 mM) to cytosol (0.1 μM)
at physiological conditions (37°C, -50 mV membrane potential).
Complete Electrochemical Gradient Calculation
The free energy change combines chemical and electrical work:
Given Parameters
- R = 8.314 J K⁻¹ mol⁻¹
- T = 37°C = 310 K
- [Ca²⁺]ER = 1 mM = 10⁻³ M
- [Ca²⁺]cytosol = 0.1 μM = 10⁻⁷ M
- z = +2 (Ca²⁺ charge)
- F = 96,500 C mol⁻¹
- Δψ = -50 mV = -0.05 V (cytosol negative)
Step-by-Step Calculation
1. Chemical Gradient Component
Concentration gradient opposes movement (10,000:1 ratio).
2. Electrical Gradient Component
Membrane potential strongly favors Ca²⁺ exit (×2 due to divalent charge).
3. Total Free Energy
Physiological Significance
Negative ΔG confirms thermodynamically favorable Ca²⁺ release, essential for:
- Calcium signaling in muscle contraction
- Neurotransmitter release
- Gene expression regulation
- ER stress response
Multiple Choice Options Analysis
| Option | Error Type | Explanation | Status |
|---|---|---|---|
| -37 kJ/mol | Complete calculation | RT ln(10⁴) + 2F(-0.05V) | CORRECT |
| +37 kJ/mol | Reversed direction | Cytosol → ER (opposite physiological) | INCORRECT |
| -23 kJ/mol | Chemical only | Ignores electrical component | INCORRECT |
| +61 kJ/mol | Wrong sign | Electrical term reversed | INCORRECT |
| -60 kJ/mol | Electrical only | Ignores chemical opposition | INCORRECT |