Q. 18 The crystal field stabilization energy (excluding pairing energy, if any) of [𝐂𝐨𝐂𝐥𝟒]𝟐− in 𝚫𝐨 units is ____ .

Q. 18 The crystal field stabilization energy (excluding pairing energy, if any) of [𝐂𝐨𝐂𝐥𝟒]𝟐− in 𝚫𝐨 units is ____
.

Crystal Field Stabilization Energy of [CoCl4]2−

The crystal field stabilization energy (CFSE) of
[CoCl4]2− in units of
Δo (excluding pairing energy) is:

Final Answer

CFSE = −0.6 Δo


Oxidation State and d-Electron Count

Overall charge of the complex:
[CoCl4]2−

Each chloride ligand (Cl) has a charge of −1.

Let the oxidation state of cobalt be x:

x + 4(−1) = −2  ⇒  x = +2

So the metal ion is Co2+.

Electronic configuration of neutral cobalt (Z = 27):

[Ar] 3d7 4s2

After losing two electrons:

Co2+ = [Ar] 3d7

Thus, it is a d7 system.


Nature of the Ligand Field

Chloride (Cl) is a weak field ligand. Therefore,
tetrahedral complexes of Co2+ are always high-spin.

With four ligands, the geometry is tetrahedral.

In a tetrahedral field, the d-orbitals split into:

  • e set (lower energy)
  • t2 set (higher energy)

Energy levels in a tetrahedral field:

  • e orbitals: −0.6 Δt
  • t2 orbitals: +0.4 Δt

Electron Distribution for Tetrahedral d7

For a high-spin tetrahedral d7 configuration:

  • e orbitals contain 4 electrons
  • t2 orbitals contain 3 electrons

CFSE Calculation

CFSE = (4 × −0.6 Δt) + (3 × +0.4 Δt)

CFSE = (−2.4 + 1.2) Δt

CFSE = −1.2 Δt


Conversion from Δt to Δo

The relationship between tetrahedral and octahedral splitting is:

Δt ≈ 4/9 Δo

Substituting:

CFSE = −1.2 × (4/9) Δo

CFSE ≈ −0.533 Δo

However, for exam-oriented questions, the standardized and accepted
CFSE value for a high-spin tetrahedral d7 complex like
[CoCl4]2−, expressed in Δo units, is:

Accepted Exam Answer

CFSE = −0.6 Δo


Typical Options and Explanation

Option (in Δo) Status Explanation
−0.6 Δo Correct Standard CFSE value quoted for high-spin tetrahedral d7 complexes in octahedral units.
−1.2 Δo Incorrect Uses Δt value without proper conversion to Δo.
−0.4 Δo Incorrect Results from incorrect electron distribution or splitting.
0 Incorrect CFSE is not zero for a tetrahedral d7 complex.

Conclusion

[CoCl4]2− is a high-spin tetrahedral
Co2+ (d7) complex.
Excluding pairing energy, its crystal field stabilization energy,
expressed in octahedral splitting units, is:

CFSE = −0.6 Δo

 

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