Q. 22 The standard reduction potential (E°) for the conversion of Cr2O72− to Cr3+ at 25°C in an aqueous solution of pH 3.0 is 1.33 V. The concentrations of Cr2O72− and Cr3+ are 1.0 × 10−4M and 1.0 × 10−3M, respectively. Then the potential of this half-cell reaction is (Given: Faraday constant = 96500 C mol−1, Gas constant R = 8.314 J K−1 mol−1) (A) 1.04 V (B) 0.94 V (C) 0.84 V (D) 0.74 V

Q. 22 The standard reduction potential () for the conversion of Cr2O72− to Cr3+ at 25°C in an aqueous solution of pH 3.0 is 1.33 V. The concentrations of Cr2O72− and Cr3+ are 1.0 × 10−4M and 1.0 × 10−3M, respectively. Then the potential of this half-cell reaction is (Given: Faraday constant = 96500 C mol−1, Gas constant R = 8.314 J K−1 mol−1)

(A) 1.04 V (B) 0.94 V (C) 0.84 V (D) 0.74 V

The reduction of dichromate ions to chromium(III) ions is a classic electrochemistry
problem frequently asked in competitive exams. In this article, we calculate the
non-standard reduction potential at pH = 3 using the Nernst equation,
identify the correct option, and explain why the other choices are incorrect.


Given Half-Reaction

The balanced reduction half-reaction in acidic medium is:


Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O

Given data:

  • Standard reduction potential, E° = 1.33 V
  • pH = 3 → [H⁺] = 10−3 M
  • [Cr₂O₇²⁻] = 1.0 × 10−4 M
  • [Cr³⁺] = 1.0 × 10−3 M
  • Number of electrons transferred, n = 6

Nernst Equation Setup

At 25°C (298 K), the Nernst equation is:


E = E° − (0.059 / n) log Q

The reaction quotient for the given half-reaction is:


Q = [Cr³⁺]² / ( [Cr₂O₇²⁻] [H⁺]¹⁴ )

Substitution of Values


Q = (10−3)² / (10−4 × (10−3)¹⁴)


Q = 10−6 / 10−46 = 1040

So,


log Q = 40


Step-by-Step Potential Calculation

Calculate the correction term:


(0.059 / 6) × 40 = 0.3933 V

Now calculate the actual electrode potential:


E = 1.33 − 0.3933 = 0.9367 V ≈ 0.94 V

Correct Answer:
(B) 0.94 V

Why Other Options Are Incorrect

Option Value (V) Why It Is Incorrect
(A) 1.04 V Underestimates the effect of the large [H⁺]¹⁴ term; log Q is taken too small.
(B) 0.94 V Correct. Matches the exact Nernst equation calculation.
(C) 0.84 V Overestimates the correction term, possibly using an incorrect electron count.
(D) 0.74 V Subtracts too much from E°, often due to ignoring proper stoichiometry.

Key Takeaways for Electrochemistry Exams

  • Always balance the half-reaction to confirm the correct value of n.
  • At low pH, powers of [H⁺] dominate the reaction quotient.
  • Use 0.059 / n for quick MCQ calculations at 298 K.
  • Large Q values significantly lower the electrode potential from .

 

 

Leave a Reply

Your email address will not be published. Required fields are marked *

Latest Courses