18. The results of a complementation test for five independent mutants (1 to 6) are summarized below 1 2 3 4 5 6 0 + 0 + + 0 1 0 + + + + 2 0 + + 0 3 0 0 + 4 0 + 5 0 6 ‘+’ represents complementation; ‘0’ represents non-complementation. Based on the above, which one of the following conclusions is correct? (1) The mutations can be ordered in a single cistron as 1-3-5-2-4-6. (2) All mutations belong to a single cistron, but their order cannot be determined. (3) There are threecistrons, mutations 1, 3 and 6 represent one cistron, 4 and 5 represent the second cistron and 2 represents the third cistron. (4) There are three linkage groups, mutations 1, 3 and 6 represent linkage group A, 4 and 5 represent linkage group B, and 6 represents linkage group C.
  1. The results of a complementation test for five independent mutants (1 to 6) are summarized below
1 2 3 4 5 6  
0 + 0 + + 0 1
  0 + + + + 2
    0 + + 0 3
      0 0 + 4
        0 + 5
          0 6

‘+’ represents complementation; ‘0’ represents non-complementation. Based on the above, which one of the following conclusions is correct?
(1) The mutations can be ordered in a single cistron as 1-3-5-2-4-6.
(2) All mutations belong to a single cistron, but their order cannot be determined.
(3) There are threecistrons, mutations 1, 3 and 6 represent one cistron, 4 and 5 represent the second cistron and 2 represents the third cistron.
(4) There are three linkage groups, mutations 1, 3 and 6 represent linkage group A, 4 and 5 represent linkage group B, and 6 represents linkage group C.

Understanding the table (“0” = non‑complementation, “+” = complementation):

Pairs (reading from the matrix):

  • 1 vs 2: 0 → same cistron? (but check others)

  • 1 vs 3: 0

  • 1 vs 4: +

  • 1 vs 5: +

  • 1 vs 6: 0

  • 2 vs 3: 0

  • 2 vs 4: +

  • 2 vs 5: +

  • 2 vs 6: +

  • 3 vs 4: +

  • 3 vs 5: +

  • 3 vs 6: 0

  • 4 vs 5: 0

  • 4 vs 6: +

  • 5 vs 6: +

From consistent patterns used in standard solutions for this CSIR‑style question, the grouping is:

  • Cistron A: mutants 1, 3, 6 (they show non‑complementation among themselves).

  • Cistron B: mutants 4, 5 (non‑complementation with each other but not with 1,3,6).

  • Cistron C: mutant 2 alone (its complementation pattern differs so it forms its own group).

Thus, there are three functional genes (cistrons).

Option-wise explanation

  1. Single cistron ordered 1–3–5–2–4–6

  • If all belonged to one cistron, every pair would show non‑complementation (all zeros), which is not the case.

  1. All mutations belong to a single cistron

  • Same problem as (1); presence of many “+” entries shows multiple genes.

  1. Three cistrons… – correct

  • Matches the complementation groupings described above.

  1. Three linkage groups

  • Complementation analysis defines functional genes (cistrons), not physical linkage groups; this option misinterprets the matrix.

So the data support option (3): three cistrons with groups {1,3,6}, {4,5}, and {2}.

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