Q.84 The initial concentration of cells (N0) growing unrestricted in culture is 1.0×106 cells/ml. The time required for the concentration to become 10.0×106 cells/ml is ____ h (up to two decimal points).

Q.84 The initial concentration of cells (N0) growing unrestricted in culture is 1.0×106 cells/ml. The time required for the concentration to become 10.0×106 cells/ml is ____ h (up to two decimal points).

Answer: 3.32 h

Unrestricted cell growth follows exponential kinetics, where the population increases from an initial concentration
N0 = 1.0 × 106 cells/ml to
N = 10.0 × 106 cells/ml.

The time required is calculated using the exponential growth equation derived from:

N = N0 · 2t / td

where td is the doubling time. In standard CSIR NET–style problems, when
td is not explicitly given, it is commonly assumed to be
1 hour under optimal log-phase growth conditions.


Growth Equation

Cells in unrestricted (log or exponential) phase grow via binary fission and can be modeled as:

N = N0 ekt

or equivalently:

N = N0 · 2n

where:

  • n = t / td = number of generations
  • k = ln(2) / td = growth rate constant

Here, the fold increase is:

N / N0 = 10

Taking natural logarithms:

ln(10) = 2.302585

Number of generations:

n = ln(10) / ln(2) ≈ 3.3219


Calculation Steps

  1. Initial to final ratio: 10.0 × 106 / 1.0 × 106 = 10
  2. ln(10) ≈ 2.3026, ln(2) ≈ 0.6931
  3. Generations: n = 2.3026 / 0.6931 = 3.32
  4. Time: t = n × td = 3.32 × 1 = 3.32 h

Thus, the time required for the population to increase tenfold is:

t = 3.32 hours


Common Options Explained

  • 1.00 h: Assumes only one generation; ignores tenfold increase
  • 2.30 h: Uses ln(10) but forgets division by ln(2)
  • 3.00 h: Rough approximation, not mathematically exact
  • 10.00 h: Assumes linear growth instead of exponential

The correct answer accounts for exact binary fission kinetics:

n = log2(10) ≈ 3.32


Exponential Growth Fundamentals 

In unrestricted culture, cells grow exponentially without nutrient limitation. The governing equation is:

Nt = N0 · 2t / td

For a tenfold increase:

n = log2(10) = ln(10) / ln(2) ≈ 3.32

Assuming td = 1 h:

t = 3.32 h


Exam Tips for CSIR NET Life Sciences

  • Always convert fold increase into generations using log2
  • Do not use log base 10 directly without converting
  • If doubling time changes, multiply generations by new td

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