Q. 17 Among the following statements, (i) [NiCl4]2− (atomic number of Ni = 28) is diamagnetic (ii) Ethylamine is a weaker Lewis base compared to pyridine (iii) [NiCl2{P(C6H5)3}2] has two geometrical isomers (iv) Bond angle in H2O is greater than that in H2S, the CORRECT one is (i) (ii) (iii) (iv)

Q. 17 Among the following statements,

(i) [NiCl4]2− (atomic number of Ni = 28) is diamagnetic

(ii) Ethylamine is a weaker Lewis base compared to pyridine

(iii) [NiCl2{P(C6H5)3}2] has two geometrical isomers

(iv) Bond angle in H2O is greater than that in H2S,

the CORRECT one is

  1. (i)
  2. (ii)
  3. (iii)
  4. (iv)

The correct statement among the options is (iv), as confirmed by VSEPR theory and electronegativity differences.

Option (i): [NiCl₄]²⁻ Diamagnetic?

[NiCl₄]²⁻ is paramagnetic, not diamagnetic. Ni (Z=28) in +2 state has d⁸ configuration; Cl⁻ as weak field ligand yields tetrahedral sp³ hybrid, with two unpaired electrons.

Option (ii): Ethylamine Weaker Lewis Base Than Pyridine?

False—ethylamine (CH₃CH₂NH₂) is a stronger base than pyridine (C₅H₅N). Alkyl groups donate electrons, enhancing availability of N lone pair; pyridine’s sp² N lone pair delocalizes into ring, reducing basicity.

Option (iii): [NiCl₂{P(C₆H₅)₃}₂] Geometrical Isomers?

[NiCl₂(PPh₃)₂] shows cis-trans isomerism. Tetrahedral Ni(II) d⁸ with bulky phosphine ligands allows geometrical isomers, unlike simple tetrahedral complexes.

Why (iv) is Correct

Bond angle in H₂O (104.5°) > H₂S (92°). Both AX₂E₂ VSEPR, but O’s higher electronegativity pulls bond pairs closer, increasing bp-bp repulsion over lp-lp; S’s larger size reduces repulsion.

 

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