Q.50 A 0.1 mL aliquot of a bacteriophage stock having a concentration of 4 × 109 phages mL−1 is added to 0.5 mL of E. coli culture having a concentration of 2 × 108 cells mL−1. The multiplicity of infection is _________.

Q.50 A 0.1 mL aliquot of a bacteriophage stock having a concentration of
4 × 109 phages mL−1 is added to 0.5 mL of E. coli culture having a
concentration of 2 × 108 cells mL−1. The multiplicity of infection is _________.

Multiplicity of infection (MOI) measures the ratio of bacteriophages to bacterial cells in virology experiments. In this case, adding 0.1 mL of 4 × 109 phages mL−1 stock to 0.5 mL of 2 × 108 E. coli mL−1 culture yields an MOI of 4.

MOI Formula

Multiplicity of infection equals total infecting phages divided by total target cells: MOI = (phage particles) / (bacterial cells). This dimensionless ratio guides infection outcomes, like single-hit kinetics at MOI <1 or multi-hit at MOI >1.

Step-by-Step Calculation

First, compute phages added: 0.1 mL × 4 × 109 phages mL−1 = 4 × 108 phages.

Next, compute E. coli cells: 0.5 mL × 2 × 108 cells mL−1 = 1 × 108 cells.

Finally, MOI = (4 × 108) / (1 × 108) = 4.

Common Errors Explained

  • Using concentrations directly without volumes gives 20, ignoring dilution.
  • Forgetting mL-to-L conversion or assuming 1 mL total volume leads to 2 or 8.
  • MOI ignores adsorption efficiency; actual infection may vary.

Common Calculation Errors

Error Type Wrong MOI Reason
Volume Ignored 20 (4×109)/(2×108) skips volumes
Total Volume Used 0.8 Assumes mixed volume as denominator
E. coli Miscalc 2 Halves cells incorrectly

 

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