Q.85 A bacterial population increases from 103 cells to 109 cells in 10 h. Calculate the number of generations per hour. (A) 20 (B) 10 (C) 4 (D) 2

Q.85
A bacterial population increases from 103 cells to 109 cells in 10 h. Calculate the number of generations per hour.

(A) 20
(B) 10
(C) 4
(D) 2

Introduction

Bacteria grow by binary fission, where each cell divides into two.
This leads to exponential growth.
The number of times the population doubles is called the
generation number (n).
In this problem, we calculate the generations per hour.


Given Data

Initial population (N0) = 103

Final population (N) = 109

Time (t) = 10 hours

Find: Generations per hour


Growth Formula

Bacterial growth equation:

N = N0 × 2n

where:

  • N = final population
  • N0 = initial population
  • n = number of generations

Step-by-Step Solution

Step 1: Substitute values

109 = 103 × 2n

Step 2: Simplify

109 / 103 = 2n

106 = 2n

Step 3: Take logarithm

n = log(106) / log 2

n = 6 / 0.301 ≈ 20

Step 4: Generations per hour

Generations per hour = n / t

= 20 / 10 = 2


Final Answer

2 generations per hour

Correct Option: (D)


Explanation of All Options

  • (A) 20 – Total generations, not per hour
  • (B) 10 – Incorrect division
  • (C) 4 – Calculation mistake
  • (D) 2 – Correct value (20 ÷ 10)

Important Exam Formulas

n = (log N − log N0) / log 2

Generations per hour = n / t

Shortcut: 106 ≈ 220


Conceptual Understanding

Each generation doubles the population.
Higher generations per hour indicate faster bacterial growth.
This concept is widely used in fermentation technology and microbiology.

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