Q.85
A bacterial population increases from 103 cells to 109 cells in 10 h. Calculate the number of generations per hour.
Introduction
Bacteria grow by binary fission, where each cell divides into two.
This leads to exponential growth.
The number of times the population doubles is called the
generation number (n).
In this problem, we calculate the generations per hour.
Given Data
Initial population (N0) = 103
Final population (N) = 109
Time (t) = 10 hours
Find: Generations per hour
Growth Formula
Bacterial growth equation:
N = N0 × 2n
where:
- N = final population
- N0 = initial population
- n = number of generations
Step-by-Step Solution
Step 1: Substitute values
109 = 103 × 2n
Step 2: Simplify
109 / 103 = 2n
106 = 2n
Step 3: Take logarithm
n = log(106) / log 2
n = 6 / 0.301 ≈ 20
Step 4: Generations per hour
Generations per hour = n / t
= 20 / 10 = 2
Final Answer
2 generations per hour
Correct Option: (D)
Explanation of All Options
- (A) 20 – Total generations, not per hour
- (B) 10 – Incorrect division
- (C) 4 – Calculation mistake
- (D) 2 – Correct value (20 ÷ 10)
Important Exam Formulas
n = (log N − log N0) / log 2
Generations per hour = n / t
Shortcut: 106 ≈ 220
Conceptual Understanding
Each generation doubles the population.
Higher generations per hour indicate faster bacterial growth.
This concept is widely used in fermentation technology and microbiology.


