Q.36 An amino-acid has one proton donating group in the side chain (R). The pKCOOH, pKNH2 and pKR values for this amino-acid are 2.19, 9.67 and 4.25, respectively. Which one of the following statements about this amino-acid is CORRECT? (A) Majority of the molecules will have a net charge of -1 at pH of 7.0 (B) Majority of the molecules will have a net charge of 0 at pH of 4.25 (C) All the molecules will have a deprotonated R group at pH of 3.22 (D) During titration with a strong base, deprotonation will start with the R group

Q.36 An amino-acid has one proton donating group in the side chain (R).
The pKCOOH, pKNH2 and pKR values for this amino-acid are
2.19, 9.67 and 4.25, respectively. Which one of the following statements about this
amino-acid is CORRECT?

(A) Majority of the molecules will have a net charge of -1 at pH of 7.0

(B) Majority of the molecules will have a net charge of 0 at pH of 4.25

(C) All the molecules will have a deprotonated R group at pH of 3.22

(D) During titration with a strong base, deprotonation will start with the R group

Introduction

Amino acids can exist in different ionic forms depending on the pH of the solution.
Their net charge is governed by the pKa values of ionizable groups:

  • α-carboxyl group (–COOH)
  • α-amino group (–NH3+)
  • Side chain (R group), if ionizable

In this article, we solve a conceptual MCQ and explain why only one option is correct.
This topic is important for CSIR-NET, GATE, IIT-JAM, and MSc entrance exams.

Question Overview

An amino acid has one proton-donating group in the side chain (R).
The pKa values are:

  • pKCOOH = 2.19
  • pKNH2 = 9.67
  • pKR = 4.25

Which of the following statements is CORRECT?

Understanding Ionization of Each Group

1. α-Carboxyl Group (pK = 2.19)

At pH values greater than 2.19, the carboxyl group is deprotonated.

Charge: –1

2. Side Chain R Group (pK = 4.25)

The side chain is acidic and loses a proton when pH exceeds 4.25.

Charge: –1 (when deprotonated)

3. α-Amino Group (pK = 9.67)

Below pH 9.67, the amino group remains protonated.

Charge: +1

Correct Answer

Option (A): Majority of the molecules will have a net charge of –1 at pH 7.0

Why Option (A) is Correct

At pH = 7.0:

  • Carboxyl group → –1
  • R group → –1
  • Amino group → +1

Net Charge Calculation:

(–1) + (–1) + (+1) = –1

Hence, the majority of molecules possess a net charge of –1.

Explanation of All Options

Option (A)

Majority of the molecules will have a net charge of –1 at pH 7.0.

Status: ✅ Correct

Option (B)

Majority of the molecules will have a net charge of 0 at pH 4.25.

At pH equal to pKR, the R group is only 50% deprotonated,
resulting in a mixture of species rather than a dominant neutral form.

Status: ❌ Incorrect

Option (C)

All molecules will have a deprotonated R group at pH 3.22.

Since pH is less than pKR, the R group remains mostly protonated.

Status: ❌ Incorrect

Option (D)

During titration with a strong base, deprotonation starts with the R group.

Deprotonation always begins with the group having the lowest pKa value,
which is the carboxyl group (pK = 2.19).

Status: ❌ Incorrect

Key Concept to Remember

Lower pKa means stronger acid and earlier deprotonation.
Net charge depends on the ionization state of all functional groups.

Final Answer

Correct Option: (A)

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